' +JJJJ ?\>m0M='+l> /+l   d]@ŵLҦ]]LF L}BBL] X  ` 鷎귭෍ᷩ췩緈JJJJx Lȿ L8ᷭ緍췩 緍i 8 `巬 췌`x (`(8`I`B` ``>J>J>VU)?`8'x0|&HhHh VY)'&Y)xꪽ)' `Hh`V0^*^*>&` aI꽌ɪVɭ&Y&&Y& 꽌ɪ\8`&&꽌ɪɖ'*&%&,E'зЮ꽌ɪФ`+*xS&x'8*3Ixix&& 8  '  & x)*++`FG8`0($ p,&"ųųೳŪŪųųij  !"#$%&'()*+,-./0123456789:;<=>?   1 '" " *  (9"1 ( ,.(0# 2  /#0/#0 *?'#07#00/0/'#07#0:"4<*55/**5/*%5/)1/)1/)1/)'#0/#0*5/*75/**5/*:5//#0/#0'#07#0:::*::'#07#0/28$2>, 7$$2%4%$$2%4%$(2()!)E(!8b $!H(+0#1 "Ph !D)"E` @ $ C ` DQ &J80^݌Hh ü ü݌ ռ ռ ռA ļD ļ? ļAEDE?HJ>h Լ ռ ռ ռ`HJ>݌h Hh݌`)`ȔЖȔЖȠHIHHHHhHH݌hHhHh݌H6 VDP (ED Z $0x8x D- ܸDD# H8`?E Vk *f???0xE Hh D#-EEE8` D ܸx D - ܸx8`-0ݩ?ʥD EEE`   LDcpq` [` ~  LӜu`".Q`pNФbptťܥm2<(-Py0\|e<6e<g< JJJJj귍hI  aUL@ kU8  L  Q^R(jQ0l^l\  wUuW ԧ H h@ [_ /QSIRb_L`LLLL`ª`LQLYLeLXLeLee ўQH\(h0L& Ꝥ$`( R \ZLl8 ўR HH\`\Z[YS6`LxQɿu3'RͲʎRʎ]]]ɍuL͟ɍ}RLRɍg^H8 ^hZLɍR LͲɊRR% QLܤͲ Z@ -^ ş\[Z QY\[Z8`l6Lş_Ȍb_Ͳ] )Y h( ֭ͲLɍ [LLĦ__ ^ 9 LҦ3 9 a   0LjLY u< (_9 ˭ɠuɠK_9 ?LˆʎõĵL õ ĵµ aµ`` L̦µ_bJLuLz`  ȟ QlXJ̥KlV  ȟ QlV eօ3L e3L &RL &QL d L4 Ne)n `@-eff L f`L . tQLѤ LҦL` OPu d L Ne)noon 8ɍ` ^f\õL ^NR  RΩLҦ)\Z ʽ LHv 3h`0h8` [L NС õ`A@` ŵL^Lõ`  \ 濭0 \  ȟ Q ^\lZl^?cqH şch`fhjõĵ@OAP`u@`@&`QR`E Ls  @DAE@u`8` %@ @A@`@`@A`Mµ ) LЦ`8@AWc@8@-@HAȑ@hHȑ@ȑ@hHȑ@Ȋ@ch8&ȑ@Hȑ@Ah@LHȑ@ȑ@ htphso`hMhL`9V8U897T6S67`INILOASAVRUCHAIDELETLOCUNLOCCLOSREAEXEWRITPOSITIOOPEAPPENRENAMCATALOMONOMOPRINMAXFILEFINBSAVBLOABRUVERIF!pppp p p p p`" t""#x"p0p@p@@@p@!y q q p@  LANGUAGE NOT AVAILABLRANGE ERROWRITE PROTECTEEND OF DATFILE NOT FOUNVOLUME MISMATCI/O ERRODISK FULFILE LOCKESYNTAX ERRONO BUFFERS AVAILABLFILE TYPE MISMATCPROGRAM TOO LARGNOT DIRECT COMMANč$3>L[dmx- (  Ϡ@跻~!Wo*9~~~~ɬƬ~_ j ʪHɪH`Lc (L ܫ㵮赎 ɱ^_ J QL_Ls贩紎 DǴҵԵƴѵӵµȴ 7 ַ :ŵƴѵǴҵȴµ納贍﵎ٵ്ᵭⳍڵL^ѵ-I `  4 ò-յ!  8صٵ紭ﵝ 7L (0+BC  7L HH`LgL{0 HH` õL H hBL BH [ h`Lo õ ڬL B ڬ LʬH hB@ յյ [L (ȴ) ȴ 7L L ( L (ȴL{ƴѵ洩ƴǴҵ 7 ^* B0 HȱBh ӵԵ 8 L8 ݲ` ܫ  / / ED B / / ]ƴS0Jȴ ȴ)  紅D贅E B ƴ  / 0L Ν `HD٤DEEhiHLGh ` ŵBѵ-` ѵB-` ܫ XI볩쳢8 DH E𳈈췍Ȍ X0 · JLǵBȵC`,յp` 䯩 R-յյ`յ0` K R-յյ`ɵʵӵԵ` 4 K ( ѵҵLBȱBL8` DBHBH : ַ޵BȭߵBhhӵԵ RBܵmڵ޵ȱBݵm۵ߵ` 䯩LR˵̵ֵ׵`êĪLR E( 8` R` ELRŪƪ`췌 յյI뷭鷭귭ⵍ㵍跬ª 뷰` Lf ݵܵߵ޵ ^`8ܵ i B8` 4L ֵȱB׵ ܯ䵍൭嵍 ` DȑB׵Bֵ  ַ յյ`굎뵎쵬 뵎쵌``õĵBCõĵ`µµ`L õBĵCصص Qƴ0"Bƴ 󮜳` 0۰ϬBƴ8`i#`ЗLw!0>ﵭ` m ﳐ 7i볍 8 ЉLw`H h ݲL~ `浍국䵍뵩嵠Jm赍嵊mjnnn浈ۭm浍浭m䵍䵩m嵍`"L ŵ8ŵH ~(` d ֠z# u`E FOR THE PURPOSE OF SOLVING INJECTION VOLUME VARIATIONS.~ THE METHOD OF STANDARD ADDITIONS,IS A TECHNIQUE IN WHICH THE ANALYTE IS ADDED TO THE SAMPLE IN INCREASING AMOUNTS. END,ACT2QU102VCAL BALANCE IS VERY ACCURATE."j THE RESPONSE FACTOR METHOD,IS BASED ON THE FACT THAT A DETECTOR DOES NOT RESPOND EQUALLY TO ALL MIXTURE COMPONENTS.9t THE INTERNAL STANDARD METHOD,INVOLVES SPIKING THE SAMPLES AND STANDARDS WITH A REFERENCE SUBSTANC SECOND PEN.V THE COMPUTING INTEGRATOR,"IS A VERY ACCURATE, VERSATILE AND POPULAR AREA MEASURING DEVICE WHICH EMPLOYS A METHOD BASED ON CALCULUS."` THE PEAK WEIGHT METHOD,"IS A METHOD THAT IS NOT OFTEN USED, BUT IS VERY ACCURATE SINCE THE ANALYTIHALF-HEIGHT IN DETERMINING THE AREA.B THE PLANIMETER IS A SMALL INSTRUMENT WHICH,MEASURES THE AREA OF A PEAK BY TRACING ITS PERIMETER BOUNDARY LINE. L THE DISC INTEGRATOR,IS AN OBSOLETE AREA MEASURING DEVICE WHICH WRITES ON THE CHART PAPER USING AF THE DISTANCE FROM THE BASELINE TO THE APEX OF THE PEAK.. THE TRIANGULATION METHOD,INVOLVES THE MEASUREMENT OF THE AREA OF A TRIANGLE MADE OUT OF THE PEAK.$8 THE HALF-WIDTH METHOD,INVOLVES THE MEASUREMENT OF THE HEIGHT OF A PEAK AND THE WIDTH AT DENTIFIES MOLECULAR FRAGMENTS ON THE BASIS OF THEIR CHARGE AND MASS." PREPARATIVE GC,IS TECHNIQUE IN WHICH SEPARATED GASES ARE CONDENSED AND COLLECTED INDIVIDUALLY AS THEY ELUTE FROM THE COLUMN.9$ THE PEAK HEIGHT METHOD,INVOLVES THE MEASUREMENT O BRIDGE CIRCUIT, IS UNIVERSAL, BUT IS NOT VERY SENSITIVE." THE ELECTRON CAPTURE DETECTOR,"USES A RADIOACTIVE MATERIAL AND IS EXCELLENT FOR CHLORINATED HYDROCARBONS."E GAS CHROMATOGRAPHY-MASS SPECTROMETRY,IS A VERY POWERFUL ANALYSIS SYSTEM THAT I********"W0RY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."Z\R$af6g THE FLAME IONIZATION DETECTOR,"USES HYDROGEN, IS VERY SENSITIVE, BUT IS NOT UNIVERSAL.": THE THERMAL CONDUCTIVITY DETECTOR,"USES A WHEATSTONE**********************************")8>9" ";NA$D:z<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #28"M R"********************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::#6"*****ER CORRECT = "CR+50" NUMBER WRONG = "IRc5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 ETE THE FOLLOWING: ":7:JK$" "A$(AO(P)):195:Z:"THE CORRECT ANSWER IS: ":y:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUMB::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPLJK$" E) NONE OF THESE":195$ G$4 G$"A"G1D G$"B"G2T G$"C"G3d G$"D"G4t G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT! THE ANSWER IS: ";G$:"PRESS .":510JK,E: / ::JK$" "A$(AO(P)):1955 U JK$" A) "B$(C(F(1))):195c SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ  6HC1605 ;SW39+ ^P1J:355:4151 cE hQ15:C(Q)0:S mQ14FSx rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215? L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195U W$JK$:W$:135:e W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0 TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #28"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u       ORBED. END, ACT2QU92 ONARY PHASE IS POLAR,A POLAR MIXTURE COMPONENT WILL HAVE A LONG RETENTION TIME.j IF THE STATIONARY PHASE IS NONPOLAR,A NONPOLAR MIXTURE COMPONENT WILL HAVE A LONG RETENTION TIME.t CHROMOSORB IS A MATERIAL ON WHICH,A LIQUID STATIONARY PHASE IS ADSSAME STATIONARY PHASE) IS THAT,THERE IS IMPROVED RESOLUTION DUE TO GREATER CONTACT WITH THE STATIONARY PHASE.V EVEN THOUGH THEY CAN BE HUNDREDS OF FEET LONG,OPEN TUBULAR CAPILLARY COLUMNS HAVE LITTLE RESISTANCE TO CARRIER GAS FLOW.O` IF THE STATIDENSE WHEN PASSING THROUGH IT.B TEMPERATURE PROGRAMMING IS A TECHNIQUE IN WHICH,THE TEMPERATURE OF THE COLUMN IS INCREASED OR DECREASED IN THE MIDDLE OF A RUN SO AS TO IMPROVE RESOLUTION.mL AN ADVANTAGE THAT A LONG COLUMN HAS OVER A SHORT COLUMN (FROM THE COLUMN.. RETENTION TIME IS A PARAMETER FOR WHICH,THE LENGTH OF CHART PAPER FROM THE POINT OF INJECTION TO THE APEX OF THE PEAK IS MEASURED.8"IN THE GC INSTRUMENT, THE DETECTOR MUST BE HEATED SO THAT",THE SEPARATED COMPONENTS WILL NOT CONURE OF THE COLUMN. FOR THIS REASON,THE COLUMN IS PLACED IN A THERMOSTATED OVEN. THE INJECTION PORT IS AN INSTRUMENT COMPONENT IN WHICH,THE MIXTURE COMPONENTS ARE FLASH VAPORIZED.$ A GC DETECTOR DETECTS WHEN,A SEPARATED MIXTURE COMPONENT ELUTES A SHORT RETENTION TIME IS OBSERVED WHEN,A SUBSTANCE WITH A HIGH VAPOR PRESSURE AND A LOW SOLUBILITY IN A LIQUID STATIONARY PHASE IS STUDIED.P VAPOR PRESSURE CHANGES WITH TEMPERATURE AND THUS IT IS IMPORTANT TO BE ABLE TO CAREFULLY CONTROL THE TEMPERAT********"W0RY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."Z\R$af6g A LONG RETENTION TIME IS OBSERVED WHEN,A SUBSTANCE WITH A LOW VAPOR PRESSURE AND A HIGH SOLUBILITY IN A LIQUID STATIONARY PHASE IS STUDIED. **********************************")8>9" ";NA$D:z<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #27"M R"********************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::#6"*****ER CORRECT = "CR+50" NUMBER WRONG = "IRc5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 ETE THE FOLLOWING: ":7:JK$" "A$(AO(P)):195:Z:"THE CORRECT ANSWER IS: ":y:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUMB::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPLJK$" E) NONE OF THESE":195$ G$4 G$"A"G1D G$"B"G2T G$"C"G3d G$"D"G4t G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT! THE ANSWER IS: ";G$:"PRESS .":510JK,E: / ::JK$" "A$(AO(P)):1955 U JK$" A) "B$(C(F(1))):195c SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ  6HC1605 ;SW39+ ^P1J:355:4151 cE hQ15:C(Q)0:S mQ14FSx rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215? L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195U W$JK$:W$:135:e W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0 TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #27"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u       THUS SAVES TIME.# END,ACT2QU82CPHY IS A"CONFIGURATION" IN WHICH,THE STATIONARY PHASE CAN EITHER BE A LIQUID OR A SOLID ALWAYS HELD IN A "COLUMN" INSIDE AN INSTRUMENT.j HPLC IS ALWAYS A "CONFIGURATION IN WHICH,THE LIQUID MOBILE PHASE IS ALWAYS PUMPED THROUGH THE STATIONARY PHASE ANDLD IN PLACE ON THE SURFACE OF A FLAT MATERIAL SUCH AS A PLASTIC SHEET.V OPEN COLUMN CHROMATOGRAPHY IS A "CONFIGURATION" IN WHICH, THE MOBILE PHASE ALWAYS MOVES BY GRAVITY THROUGH STATIONARY PHASE PARTICLES PACKED IN A GLASS TUBE.` GAS CHROMATOGRATYPES".B PAPER CHROMATOGRAPHY IS A "CONFIGURATION" IN WHICH,A LIQUID MOBILE PHASE ALWAYS MOVES UPWARD THROUGH A CELLULOSE STRIP BY CAPILLARY ACTION.FL THIN LAYER CHROMATOGRAPHY IS ALWAYS A "CONFIGURATION" IN WHICH,THE STATIONARY PHASE IS ALWAYS HECRIBED AS "LLC" IS ONE IN WHICH,"THE CONFIGURATION CAN VARY, BUT BOTH THE MOBILE AND STATIONARY PHASES ARE ALWAYS LIQUIDS."8 LSC IS ALWAYS A METHOD IN WHICH,THE MOBILE PHASE IS A LIQUID AND THE STATIONARY PHASE A SOLID. IT CAN BE ANY ONE OF SEVERAL " "GLC" IS ONE IN WHICH,THE MOBILE PHASE IS ALWAYS A GAS AND THE STATIONARY PHASE A LIQUID.$ A CHROMATOGRAPHY METHOD DESCRIBED AS "GSC" IS ONE IN WHICH,THE MOBILE PHASE IS ALWAYS A GAS AND THE STATIONARY PHASE A SOLID.{. A CHROMATOGRAPHY METHOD DESDE PLACES WITH OTHER IONS BONDED TO THE STATIONARY PHASE. SIZE EXCLUSION CHROMATOGRAPHY IS ALWAYS A "TYPE" IN WHICH,POROUS STATIONARY PHASE PARTICLES SEPARATE LARGE MOLECULES IN THE SAMPLE FROM SMALLER ONES.Z A CHROMATOGRAPHY METHOD DESCRIBED AS ADSORPTION CHROMATOGRAPHY IS A "TYPE" IN WHICH,THE MOBILE PHASE CAN BE EITHER LIQUID OR GAS AND THE MIXTURE COMPONENTS "STICK" TO THE SOLID STATIONARY PHASE.9 ION EXCHANGE CHROMATOGRAPHY IS ALWAYS A "TYPE" IN WHICH,DISSOLVED IONS IN THE SAMPLE TRA*********"W0SY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."[\R$bf6h PARTITION CHROMATOGRAPHY IS A "TYPE" IN WHICH,THE MOBILE PHASE CAN BE EITHER A LIQUID OR A GAS AND THE STATIONARY PHASE IS A THIN LIQUID FILM.***********************************"*8?9" ";NA$E:{<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #26"M R"*******************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::$6"****BER CORRECT = "CR+60" NUMBER WRONG = "IRd5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 LETE THE FOLLOWING: ":8:JK$" "A$(AO(P)):195:[:"THE CORRECT ANSWER IS: ":z:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUM::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPJK$" E) NONE OF THESE":195% G$5 G$"A"G1E G$"B"G2U G$"C"G3e G$"D"G4u G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT! THE ANSWER IS: ";G$:"PRESS .":510K K,E: 0 ::JK$" "A$(AO(P)):1956 V JK$" A) "B$(C(F(1))):195d SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ 6HC1605 ;SW39, ^P1J:355:4152 cF hQ15:C(Q)0:T mQ14FSy rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215@ L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195V W$JK$:W$:135:f W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM110 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:%1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #26"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u        SPECTROGRAPHY.~ AN EXAMPLE OF AN "INDIRECT" METHOD IS,THE DETERMINATION OF CHLORIDE BY MEASURING SILVER CONTENT BEFORE AND AFTER PRECIPITATION WITH THE CHLORIDE-CONTAINING SAMPLE. END,ACT2QU72RQUE THAT EXISTS BECAUSE INTERMEDIATE ELECTRONIC STATES MAY BE ENCOUNTERED PRIOR TO THE FINAL DROP TO THE GROUND STATE IS,ATOMIC FLUORESCENCE.t A TECHNIQUE THAT IS USEFUL ESPECIALLY FOR THE QUALITATIVE ANALYSIS OF SOLID SAMPLES IS,ARC OR SPARK EMISSION POPULAR EMISSION (NOT ABSORPTION) TECHNIQUE IS,THE INDUCTIVELY COUPLED PLASMA.` A SOLUTION TO THE PROBLEM OF A NARROW LINEAR CONCENTRATION RANGE IN AA IS,"TO USE THE ICP TECHNIQUE, SINCE A BROADER LINEAR CONCENTRATION IS AN ADVANTAGE."j A TECHNIS MEASURED.bB ONE ADVANTAGE OFFERED BY THE GRAPHITE FURNACE ATOMIZER IS,INCREASED SENSITIVITY.L A SOLUTION TO THE PROBLEM OF HAVING TOO LITTLE SOLUTION VOLUME FOR ASPIRATION INTO A FLAME IS,TO USE A GRAPHITE FURNACE ATOMIZER.OV AN EXAMPLE OF A MATRIX.x. "WHEN THE TOTAL SAMPLE COMPOSITION IS NOT KNOWN, A USEFUL PROCEDURE IS",THE METHOD OF STANDARD ADDITIONS. 8 "IN THE METHOD OF STANDARD ADDITIONS, THE PROBLEM OF UNKNOWN SAMPLE MATRIX IS",SOLVED BY USING THE SAMPLE MATRIX FOR ALL SOLUTIONNE OF THE ANALYTE. INCOMPLETE ATOMIZATION DUE TO THE PRESENCE OF A PARTICULAR CHEMICAL SPECIES IN THE SAMPLE IS ,REFERRED TO AS A "CHEMICAL INTERFERENCE".$ THE SOLUTION TO THE INCOMPLETE ATOMIZATION OF CALCIUM IS,THE ADDITION OF LANTHANUM TO THE ATOMIC ABSORPTION INSTRUMENTS IS,THE PREMIX BURNER.t IMPROPERLY MIXED FUEL AND AIR IS,THE CAUSE OF FLASHBACKS. "IN AA, AN INSTRUMENTAL INTERFERENCE IS",ONE IN WHICH A SPECTRAL LINE OF ANOTHER COMPONENT IN THE SAMPLE OVERLAPS WITH THE PRIMARY LI********"W0RY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."Z\R$af6g "IN THE TOTAL CONSUMPTION BURNER, THE DESIGN IS","SUCH THAT THE FUEL, AIR AND OXIDANT ALL MEET AT THE BASE OF THE FLAME."4 THE BURNER USED IN**********************************")8>9" ";NA$D:z<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #25"M R"********************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::#6"*****ER CORRECT = "CR+50" NUMBER WRONG = "IRc5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 ETE THE FOLLOWING: ":7:JK$" "A$(AO(P)):195:Z:"THE CORRECT ANSWER IS: ":y:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUMB::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPLJK$" E) NONE OF THESE":195% G$5 G$"A"G1E G$"B"G2U G$"C"G3e G$"D"G4u G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT!THE ANSWER IS: ";G$:"PRESS .":510J K,E: 0 ::JK$" "A$(AO(P)):1956 V JK$" A) "B$(C(F(1))):195d SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ 6HC1605 ;SW39, ^P1J:355:4152 cF hQ15:C(Q)0:T mQ14FSy rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215@ L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195V W$JK$:W$:135:f W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM110 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #25"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u            OWER RATE. END,ACT2QU62ERNATING SIGNALS ARE OBSERVED BY THE DETECTOR.|~ THE TYPICAL FLAME FOR AA OR FLAME PHOTOMETRY IS,AN AIR-ACETYLENE FLAME. "WHEN NITROUS OXIDE IS USED INSTEAD OF AIR AS THE OXIDANT FOR A FLAME, THE FLAME THAT IS PRODUCED IS",HOTTER AND BURNS AT A SLIVE ANALYSIS IN FLAME PHOTOMETRY IS,EMISSION INTENSITY VS CONCENTRATION..t THE SOLUTION TO THE PROBLEM OF THE DETECTOR DETECTING BOTH LIGHT EMITTED BY THE FLAME AND UNABSORBED LIGHT FROM THE SOURCE IN AA IS,TO CHOP THE LIGHT FROM THE SOURCE SO THAT ALTCCURRING IN THE FLAME ALSO OCCURS IN THE LAMP.rV THE PATHLENGTH IN AN AA EXPERIMENT IS,THE WIDTH OF THE FLAME.` THE MONOCHROMATOR IN AN AA SPECTROPHOTOMETER IS,LOCATED BETWEEN THE SAMPLE AND THE DETECTOR.Hj THE GRAPH THAT IS MADE FOR QUANTITATENT COMPONENT THAT IS REQUIRED FOR ATOMIC ABSORPTION BUT NOT FOR FLAME PHOTOMETRY IS,A LIGHT SOURCE FOR DIRECTING A BEAM OF LIGHT AT THE FLAME..L THE BEAM OF LIGHT REQUIRED FOR AN ANALYSIS IS GENERATED WITHIN A HOLLOW CATHODE LAMP BECAUSE,THE PROCESS OIS",THE EMISSION OF LIGHT BY EXCITED ATOMS IN A FLAME.. "WITH ATOMIC ABSORPTION, THE FLAME IS",NEEDED ONLY FOR ATOMIZATION AND NOT FOR EXCITATION.8 "WITH FLAME PHOTOMETRY, THE FLAME IS",NEEDED FOR BOTH ATOMIZATION AND EXCITATION.B AN INSTRUM PHOTOMETRY IS,"ESSENTIALLY THE FLAME TEST WITH A MONOCHROMATOR, DETECTOR AND READOUT ADDED." "WITH ATOMIC ABSORPTION, THE PROCESS MEASURED IS",THE ABSORPTION OF LIGHT BY UNEXCITED ATOMS IN A FLAME.6$ "WITH FLAME PHOTOMETRY, THE PROCESS MEASURED T ACTUALLY IS,THE COLOR REPRESENTING THE LINE SPECTRUM OF THE ATOM INVOLVED. THE LINE SPECTRUM EMITTED BY THE ATOMS IN A FLAME IS,DUE TO THE LIMITED NUMBER OF TRANSITIONS THAT ARE POSSIBLE BETWEEN THE GROUND AND EXCITED STATES IN AN ATOM.] FLAME*********"W0SY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."[\R$bf6h THE PROCESS OF CONVERTING DISSOLVED METAL IONS INTO FREE GROUND STATE ATOMS IS,ATOMIZATION.L THE COLOR EMITTED BY THE FLAME IN THE FLAME TES***********************************"*8?9" ";NA$E:{<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #24"M R"*******************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::$6"****BER CORRECT = "CR+60" NUMBER WRONG = "IRd5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 LETE THE FOLLOWING: ":8:JK$" "A$(AO(P)):195:[:"THE CORRECT ANSWER IS: ":z:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUM::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPJK$" E) NONE OF THESE":195% G$5 G$"A"G1E G$"B"G2U G$"C"G3e G$"D"G4u G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT! THE ANSWER IS: ";G$:"PRESS .":510K K,E: 0 ::JK$" "A$(AO(P)):1956 V JK$" A) "B$(C(F(1))):195d SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ 6HC1605 ;SW39, ^P1J:355:4152 cF hQ15:C(Q)0:T mQ14FSy rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215@ L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195V W$JK$:W$:135:f W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM110 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #24"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u            COMPOUNDS THAT POSSESS THE ABILITY TO FLUORESCE IS GENERALLY QUITE INTENSE IS,A SOLID ADVANTAGE FOR FLUOROMETRY AS AN ANALYTICAL TECHNIQUE BECAUSE OF THE HIGH SENSITIVITY THAT RESULTS. END,ACT2QU522EVE IN ORDER TO EXHIBIT FLUORESCENCE IS,A FUSED BENZENE RING SYSTEM.j THE FACT THAT A LIMITED NUMBER OF COMPOUNDS POSSESS THE ABILITY TO FLUORESCE IS,A DISADVANTAGE FOR THE TECHNIQUE OF FLUOROMETRY IN GENERAL.t THE FACT THAT THE FLUORESCENCE FROM HROMATORS IN A FLUOROMETER IS,ONE DIFFERENCE BETWEEN AN ABSORPTION SPECTROPHOTOMETER AND A FLUOROMETER.V"IN FLUOROMETRY, THE FLUORESCENCE INTENSITY IS",DIRECTLY PROPORTIONAL TO CONCENTRATION.C` A STRUCTURAL FEATURE THAT COMPOUNDS MUST GENERALLY HA LIGHT ABSORBED IS,KNOWN AS QUANTUM EFFICIENCY.B IN A FLUOROMETER THE DETECTOR IS SITUATED SUCH THAT THE LIGHT EMITTED IS MEASURED AT RIGHT ANGLES TO THE INCOMING LIGHT BEAM. THIS IS,KNOWN AS RIGHT ANGLE CONFIGURATION.gL THE PRESENCE OF TWO MONOCWAVELENGTH REGION THAN THE CORRESPONDING ABSORPTION SPECTRUM. THIS IS,KNOWN AS STOKE'S SHIFT.. THE LOSS OF FLUORESCENCE DUE TO THE PRESENCE OF OF ANOTHER CHEMICAL SPECIES IN SOLUTION IS,KNOWN AS QUENCHING./8 THE COMPARISON OF LIGHT EMITTED TO THEED BY LIGHT EMISSION. PHOSPHORESCENCE IS A TYPE OF LIGHT EMISSION THAT IS,CAUSED BY ENERGY LOSS THROUGH AN INTERMEDIATE ELECTRONIC STATE PRIOR TO DROPPING TO THE GROUND STATE.^$ THE ENTIRE FLUORESCENCE SPECTRUM OF A COMPOUND IS FOUND IN A LONGER R THAN THE WAVELENGTH OF LIGHT ABSORBED.  THE PRESENCE OF VIBRATIONAL LEVELS WITHIN ELECTRONIC LEVELS IS,DIRECTLY RESPONSIBLE FOR THE PHENOMENON KNOWN AS FLUORESCENCE. INTERNAL CONVERSION IS A TYPE OF MOLECULAR ENERGY LOSS THAT IS,NOT ACCOMPANI*****" W0OY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."W\R$^f6d IN FLUORESCENCE THE ENERGY OF LIGHT EMITTED IS,LESS THAN THE ENERGY OF LIGHT ABSORBED.) IN FLUORESCENCE THE WAVELENGTH OF LIGHT EMITTED IS,LONGE*******************************"&8;9" ";NA$A:w<" HAS ACHIEVED A SCORE OF ";(CR100L);"%"}>C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #23"MR"**********************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41:: 6"********CORRECT = "CR+20" NUMBER WRONG = "IR`5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 * THE FOLLOWING: ":4:JK$" "A$(AO(P)):195:W:"THE CORRECT ANSWER IS: ":v:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1 &" NUMBER :"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPLETEJK$" E) NONE OF THESE":195% G$5 G$"A"G1E G$"B"G2U G$"C"G3e G$"D"G4u G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU CORRECT! THE ANSWER IS: ";G$:"PRESS .":510G: K,E: 0 ::JK$" "A$(AO(P)):1956 V JK$" A) "B$(C(F(1))):195d SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ 6HC1605 ;SW39, ^P1J:355:4152 cF hQ15:C(Q)0:T mQ14FSy rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215@ L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195V W$JK$:W$:135:f W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM110 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #23"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u        SPECTROGRAPHY.~ AN EXAMPLE OF AN "INDIRECT" METHOD IS,THE DETERMINATION OF CHLORIDE BY MEASURING SILVER CONTENT BEFORE AND AFTER PRECIPITATION WITH THE CHLORIDE-CONTAINING SAMPLE. END,ACT2QU72QUE THAT EXISTS BECAUSE INTERMEDIATE ELECTRONIC STATES MAY BE ENCOUNTERED PRIOR TO THE FINAL DROP TO THE GROUND STATE IS,ATOMIC FLUORESCENCE.t A TECHNIQUE THAT IS USEFUL ESPECIALLY FOR THE QUALITATIVE ANALYSIS OF SOLID SAMPLES IS,ARC OR SPARK EMISSION POPULAR EMISSION (NOT ABSORPTION) TECHNIQUE IS,THE INDUCTIVELY COUPLED PLASMA.` A SOLUTION TO THE PROBLEM OF A NARROW LINEAR CONCENTRATION RANGE IN AA IS,"TO USE THE ICP TECHNIQUE, SINCE A BROADER LINEAR CONCENTRATION IS AN ADVANTAGE."j A TECHNIS MEASURED.bB ONE ADVANTAGE OFFERED BY THE GRAPHITE FURNACE ATOMIZER IS,INCREASED SENSITIVITY.L A SOLUTION TO THE PROBLEM OF HAVING TOO LITTLE SOLUTION VOLUME FOR ASPIRATION INTO A FLAME IS,TO USE A GRAPHITE FURNACE ATOMIZER.OV AN EXAMPLE OF A MATRIX.x. "WHEN THE TOTAL SAMPLE COMPOSITION IS NOT KNOWN, A USEFUL PROCEDURE IS",THE METHOD OF STANDARD ADDITIONS. 8 "IN THE METHOD OF STANDARD ADDITIONS, THE PROBLEM OF UNKNOWN SAMPLE MATRIX IS",SOLVED BY USING THE SAMPLE MATRIX FOR ALL SOLUTIONNE OF THE ANALYTE. INCOMPLETE ATOMIZATION DUE TO THE PRESENCE OF A PARTICULAR CHEMICAL SPECIES IN THE SAMPLE IS ,REFERRED TO AS A "CHEMICAL INTERFERENCE".$ THE SOLUTION TO THE INCOMPLETE ATOMIZATION OF CALCIUM IS,THE ADDITION OF LANTHANUM TO THE ATOMIC ABSORPTION INSTRUMENTS IS,THE PREMIX BURNER.t IMPROPERLY MIXED FUEL AND AIR IS,THE CAUSE OF FLASHBACKS. "IN AA, AN INSTRUMENTAL INTERFERENCE IS",ONE IN WHICH A SPECTRAL LINE OF ANOTHER COMPONENT IN THE SAMPLE OVERLAPS WITH THE PRIMARY LI********"W0RY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."Z\R$af6g "IN THE TOTAL CONSUMPTION BURNER, THE DESIGN IS","SUCH THAT THE FUEL, AIR AND OXIDANT ALL MEET AT THE BASE OF THE FLAME."4 THE BURNER USED IN**********************************")8>9" ";NA$D:z<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #25"M R"******************************* CUVETTES MUST BE MADE OF",QUARTZ3 END,ACT2QU42ER THAT IS USEFUL FOR RAPID SCANNING THROUGH A PARTICULAR WAVELENGTH REGION IS CALLED A,DOUBLE BEAM SPECTROPHOTOMETER THE LIGHT SOURCE USED IN ULTRAVIOLET SPECTROPHOTOMETERS IS THE,HYDROGEN DISCHARGE TUBE! "FOR ULTRAVIOLET SPECTROPHOTOMETRY, THE THE,WAVELENGTH OF MAXIMUM ABSORBANCEr~ THE SOLUTION THAT IS USED TO ADJUST THE READOUT TO 100 %T IS THE,BLANK THE BEAM OF LIGHT THAT PASSES THROUGH THE BLANK IN A DOUBLE BEAM SPECTROPHOTOMETER IS CALLED THE,REFERENCE BEAMu A SPECTROPHOTOMETTRATION IS CALLED",BEER'S LAW` "THE UNITS OF THIS PARAMETER CAN BE PPM, MOLARITY, OR GRAMS/100 ML, AMONG OTHERS.",CONCENTRATIONj THE SPECTRONIC-20 IS AN EXAMPLE OF A,SINGLE BEAM SPECTROPHOTOMETER%t THE BEST WAVELENGTH TO USE IN AN ANALYSIS IS IN CM IS CALLED THE,MOLAR EXTINCTION COEFFICIENTL INCREASING THIS PARAMETER RESULTS IN MORE LIGHT BEING ABSORBED JUST AS IF WE HAD INCREASED THE CONCENTRATION.,PATHLENGTHV"THE RELATIONSHIP BETWEEN ABSORBANCE, ABSORPTIVITY, PATHLENGTH, AND CONCENAND CONCENTRATION IS CALLED THE",ABSORBANCE8 THE INHERENT ABILITY OF AN ABSORBING SPECIES TO ABSORB LIGHT IS CALLED THE,ABSORPTIVITY1B A PARAMETER SPECIFICALLY DEFINED AS THE ABSORPTIVITY WHEN THE CONCENTRATION IS IN MOLARITY AND THE PATHLENGTH ISIS HELD IN A SPECTROPHOTOMETER IS CALLED THE,CUVETTE$ THE RATIO OF THE INTENSITY OF LIGHT WITH THE SAMPLE IN ITS PATH TO THE INTENSITY OF LIGHT WITH THE BLANK IN ITS PATH IS CALLED THE,TRANSMITTANCE+. "THE PRODUCT OF THE ABSORPTIVITY, PATHLENGTH, ECTRUM IS CALLED THE,COLORIMETER| THE LIGHT SOURCE FOR THE VISIBLE REGION OF THE SPECTRUM IS THE,TUNGSTEN FILAMENT BULB THE DISPERSING ELEMENT IN A SPECTROPHOTOMETER IS USUALLY EITHER A PRISM OR A,GRATING4 THE CONTAINER IN WHICH THE SAMPLE THE MENU AGAIN, PRESS .")\R$0f66 THE SPECTROPHOTOMETER COMPONENT THAT SELECTS THE WAVELENGTH TO BE USED IS CALLED THE,MONOCHROMATOR  A SPECTROPHOTOMETER THAT IS USED STRICTLY FOR MEASUREMENTS IN THE VISIBLE REGION OF THE SP ";NA$:I<" HAS ACHIEVED A SCORE OF ";(CR100L);"%"O>~C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #22"MR"***************************************"W0!Y:"IF YOU WOULD LIKE TO SEERIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::6"***************************************"8 9" "IR25:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 *:/" PLEASE REMOVE THE DISK FROM THE DCRCR1:525c:JK$" WRONG! THE CORRECT ANSWER IS: "B$(AO(P)):195:" PRESS "oIRIR1w R$CC1C10ī535P::::!LCRIR:L0L1&" NUMBER CORRECT = "CR+0" NUMBER WRONG =JK$" E) NONE OF THESE":195$ G$4 G$"A"G1D G$"B"G2T G$"C"G3d G$"D"G4t G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 :JK$" YOU ARE CORRECT! THE ANSWER IS: "B$(AO(P)):195:" PRESS "K,E: / ::JK$" "A$(AO(P)):1955 U JK$" A) "B$(C(F(1))):195c SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ  6HC1605 ;SW39+ ^P1J:355:4151 cE hQ15:C(Q)0:S mQ14FSx rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215? L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195U W$JK$:W$:135:e W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0 TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:51011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #22"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u       z#    ԲձԲձԲձ" Բշ ԲմԲյ ԲնԱշ ԲոԲչԲձϠ Աձˠ,ԱձԱձԲղ!Բճ::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPLJK$" E) NONE OF THESE":195$ G$4 G$"A"G1D G$"B"G2T G$"C"G3d G$"D"G4t G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT! THE ANSWER IS: ";G$:"PRESS .":510JK,E: / ::JK$" "A$(AO(P)):1955 U JK$" A) "B$(C(F(1))):195c SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ  6HC1605 ;SW39+ ^P1J:355:4151 cE hQ15:C(Q)0:S mQ14FSx rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215? L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195U W$JK$:W$:135:e W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0 TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #29"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u   POLAROGRAPHY"&" 16) MENU PAGE 1",U"TYPE THE NUMBER OF YOUR SELECTION"\S{S10ĺD$;"RUN ACT2QU7,D1"S11ĺD$;"RUN ACT2QU8,D1"S12ĺD$;"RUN ACT2QU9,D1" S13ĺD$;"RUN ACT2QU10,D1"S14ĺD$;"RUN ACT2QU11,D1"S"***************************************/ Y " 10) QUIZ 25: ATOMIC TECHNIQUES II"} " 11) QUIZ 26: CHROMATOGRAPHY" " 12) QUIZ 27: GAS CHROMATOGRAPHY I" " 13) QUIZ 28: GAS CHROMATOGRAPHY II" " 14) QUIZ 29: HPLC"" 15) QUIZ 30:N ACT2QU2,D1"+ S6ĺD$;"RUN ACT2QU3,D1"I S7ĺD$;"RUN ACT2QU4,D1"g S8ĺD$;"RUN ACT2QU5,D1" S9ĺD$;"RUN ACT2QU6,D1" S0ī165 S9ī12 "***************************************": " MENU PAGE TWO":) : ATOMIC TECHNIQUES I"- M" 0) MENU PAGE 23 Z[ _"TYPE THE NUMBER OF YOUR SELECTIONb dSt iD$(13)(4) nS1ĺD$;"RUN ACT1QU16,D1" sS2ĺD$;"RUN ACT1QU17,D1" xS3ĺD$;"RUN ACT1QU18,D1" }S4ĺD$;"RUN ACT2QU1,D1" S5ĺD$;"RUL POTENTIAL CALCULA- TIONS"Q #" 4) QUIZ 19: FUNDAMENTALS OF LIGHT I" (" 5) QUIZ 20: FUNDAMENTALS OF LIGHT II" -" 6) QUIZ 21: BEER'S LAW, ETC." 2" 7) QUIZ 22: SPECTROPHOTOMETRY" 7" 8) QUIZ 23: FLUOROMETRY" <" 9) QUIZ 24 MENU PAGE ONE! P "****************************************V  " 1) QUIZ 16: EQUIVALENT WEIGHTS - REDOX (HANDOUT REQUIRED)" " 2) QUIZ 17: REDOX CALCULATIONS (HANDOUT REQUIRED)"$ " 3) QUIZ 18: CEL 1011,100'::::::X"***************************************":" ANALYTICAL CHEMISTRY":" FOR TECHNICIANS":" COMPUTER QUIZZES": " COPYRIGHTED 1990 BY JOHN KENKEL": "      OF THE HANDOUT?,37.228 @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KNO@D3@@ AS USED IN EQUATION (@@D@@) OF THE HANDOUT?,33.703B @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KC@@L@@O@D3 @@AS USED IN EQUATION (@@E@@) OF THE HANDOUT?,61.28\L @HW@@HAT IS T@A@@C@@L@@O@@ AS USED IN EQUATION (@@C@@) OF THE HANDOUT?,18.61$ @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KNO@D3@@ AS USED IN EQUATION (@@C@@) OF THE HANDOUT?,50.56. @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@N@@A@@C@@L@@O@@ AS USED IN EQUATION (@@D@@) @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@N@@A@@C@@L AS USED IN EQUATION (@@B@@) OF THE HANDOUT?,14.61 @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KNO@D3@@ AS USED IN EQUATION (@@B@@) OF THE HANDOUT?,25.278? @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@N@ MENU AGAIN,PRESS .#\R$*a60 @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KC@@L AS USED IN EQUATION (@@A@@) OF THE HANDOUT?,12.43 @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KNO@D3@@ AS USED IN EQUATION (@@A@@) OF THE HANDOUT?,12.64g ";NA$:F<" HAS ACHIEVED A SCORE OF ";(CR100L);"%"L>{C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #16"MR"***************************************"W0Y:"IF YOU WOULD LIKE TO SEE THEE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::6"***************************************"8 9" SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;ZF$"@H"<G$?G$"Y"125DG$"N"800S570 *:,/" PLEASE REMOVE THE DISK FROM THE DRIV$"WRONG! THE CORRECT ANSWER IS: "B$(AO(P)):195:" PRESS ."XIRIR1_ IiCC1vC7535}P:::::!LCRIR:L0L1&" NUMBER CORRECT = "CR+0" NUMBER WRONG = "IR5:" STUDENT ZF$"@H"I(A"@HA,B,C,D,E"9ZA$"A"G1JZA$"B"G2[ZA$"C"G3lZA$"D"G4}ZA$"E"G5C(F(G))AO(P)515JK$" YOU ARE CORRECT! THE ANSWER IS: "B$(AO(P)):195:" PRESS ."CRCR1:525LJK)F(E)395 K,E : ::JK$" "A$(AO(P)):195@ f JK$"@H A) "B$(C(F(1))):195 JK$"@H B) "B$(C(F(2))):195 JK$"@H C) "B$(C(F(3))):195 JK$"@H D) "B$(C(F(4))):195 JK$"@H E) NONE OF THESE":1951275 NP(AO(I))1:I" 'FS0, ;SW387 ^P1J> cNR hQ15:C(Q)0:` mQ14FS rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)SW215, TSWO1:(JK$,T,1)" "2108 T:215t L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195 W$JK$:W$: W$: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))NA$ZA$ "GOOD LUCK, ";NA$7 :"PRESS ANY KEY."H TIMER11E8X A(16384)s A127SEEDTIMER:179y Z(SEED):16368,0:N:::::"ONE MOMENT, PLEASE ....." NM35 AO(NM),A$(NM),B$(NM),NP(NM) 225 XK(0):(JK$IS QUIZ." q:::, t"PRESS ."4 vN$: |D }IR0N CR0V :{ 6:5:"ONE MOMENT, PLEASE....." (13);(4);"BRUN ACTPACK" 35326 N ::::"TYPE YOUR NAME THEN PRESS ." ZF$"@H" : I  C026::F7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"eA" QUIZ #16"qZ:::n" SPECIAL INSTRUCTIONS:"o::: p" THE TABLE OF MOLECULAR WEIGHTS ON THE INSIDE BACK COVER OF THE TEXT WILL BE USEFUL FOR TH        OVER TIME. END,ACT2QU112CCLOGGING OF THE COLUMN.V DEGASSING THE MOBILE PHASE,REMOVES DISSOLVES GASES WHICH MAY OTHERWISE WITHDRAW FROM THE SOLVENT WHEN PRESSURES DROP IN THE SYSTEM. ` AN AQUEOUS BUFFER OF LOW PH,MUST BE FLUSHED FROM THE SYSTEM TO AVOID DAMAGE TO THE PUMP EX DETECTOR,"IS ALMOST UNIVERSAL, BUT IS NOT VERY SENSITIVE."B THE FLUORESCENCE DETECTOR,"IS VERY SELECTIVE AND SENSITIVE, JUST LIKE AN ORDINARY FLUOROMETER."L FILTERING THE MOBILE PHASE IN ADVANCE,REMOVES PARTICLES WHICH WOULD OTHERWISE LEAD TO UV ABSORBANCE DETECTOR,UTILIZES A LIGHT FILTER AS THE MONOCHROMATOR. THE VARIABLE WAVELENGTH UV ABSORBANCE DETECTOR,"IS SENSITIVE, NOT ENTIRELY UNIVERSAL, AND CAN BE ADJUSTED PRECISELY TO THE WAVELENGTH OF MAXIMUM ABSORBANCE."=8 THE REFRACTIVE IND MOBILE PHASE COMPOSITION IS GRADUALLY AND CONTINUOUSLY CHANGED DURING THE SEPARATION EXPERIMENT. THE LOOP INJECTOR,IS A TWO POSITION VALVE WHICH OVERCOMES THE PROBLEM OF INTRODUCING THE SAMPLE TO THE HIGH PRESSURE SYSTEM.C$ THE FIXED WAVELENGTH -POLAR STATIONARY PHASE.S ION CHROMATOGRAPHY,UTILIZES A CONDUCTIVITY DETECTOR. ISOCRATIC ELUTION,IS A SYSTEM IN WHICH A SINGLE MOBILE PHASE COMPOSITION IS USED FOR THE ENTIRE SEPARATION EXPERIMENT.a GRADIENT ELUTION,IS A SYSTEM IN WHICH THE********"W0RY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."Z\R$af6g NORMAL PHASE HPLC,UTILIZES A NON-POLAR MOBILE PHASE AND A POLAR STATIONARY PHASE. REVERSE PHASE HPLC,UTILIZES A POLAR MOBILE PHASE AND A NON**********************************")8>9" ";NA$D:z<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #29"M R"********************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::#6"*****ER CORRECT = "CR+50" NUMBER WRONG = "IRc5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 ETE THE FOLLOWING: ":7:JK$" "A$(AO(P)):195:Z:"THE CORRECT ANSWER IS: ":y:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUMBF THE HANDOUT?,119.01| @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@SO@D3 @@AS USED IN EQUATION (@@K@@) OF THE HANDOUT?,13.34 END,ACT1QU1622T OF @@N@@A@@C@@L AS USED IN EQUATION (@@J@@) OF THE HANDOUT?,7.305 @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@K@D2SO@D4 @@AS USED IN EQUATION (@@J@@) OF THE HANDOUT?,29.045 @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KB@@R AS USED IN EQUATION (@@K@@) OUT?,10.01n~ @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KC@@L AS USED IN EQUATION (@@H@@) OF THE HANDOUT?,37.28 @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@K@D2SO@D4 @@AS USED IN EQUATION (@@H@@) OF THE HANDOUT?,87.14C @HW@@HAT IS THE EQUIVALENT WEIGHSO@D4 @@AS USED IN EQUATION (@@F@@) OF THE HANDOUT?,71.02j @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KIO@D3 @@AS USED IN EQUATION (@@G@@) OF THE HANDOUT?,107.00 t @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@SO@D3@@ AS USED IN EQUATION (@@G@@) OF THE HANDOHE EQUIVALENT WEIGHT OF @@N@@A@D2@@SO@D4@@ AS USED IN EQUATION (@@E@@) OF THE HANDOUT?,17.76V @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@KB@@R@@O@D3 @@AS USED IN EQUATION (@@F@@) OF THE HANDOUT?,83.519` @HW@@HAT IS THE EQUIVALENT WEIGHT OF @@N@@A@D2@@x=) oȥ{o`x)) z w`yLVn.A& $< >,.?: ; ` 8```m`m``e` H!) Lv)z{  hm Umze z z ݀zTzKUmE Sn UmLl Mn UmL m zm zm& SnLlL=l xmLlH)[ Ah `h`H)a{h)`=`x!=a 9n\ȱ T 0"ȱ0$H >n"ȱ  -)ȱx 9nȱ 0 ȱxsȱo?$oƝŢȑoh`& Sn MnQ&YLl Mn zm& Mn `` Hheh8& &i``枩x zm Sn Um Um0)   zmLl Sn Mn xmLBl Um=L5l zmLl Um Mn x zm&Ll xmLsl &'0%% 0杹&& 'y"'Х&Ģ hhh` '͐hL l̒hhhhh vgozm0>H)?(ŝ 0杩 {HDthoh )D lLkDf8tȩXo n n&'&ȱȱJI&@'0:3 ,"%0 "& @"Lj'0"  0 0&'L#jLj!&0)? )&&祛0  JJxp ȹy >йclwmЙ n8Ě"Щ0梥ȥȄ Sn MnȐLh!0зH lhDfLiLh SnL lLJkŢ& i愰إi愠` g gm8knlmimnkiklȥȑL h`zm n MnLCiLi<>ŝ ढ़Lbȹy) UmsLhi Pg g8逅ɀ8LfͩZ gȑȑ`湥FgGgG-` 5g Um` 5g `H %gh` vgo` g gJ gĥ&ȥo8奅opȥp`o8mpnMLԠZ gHȱȱh` gȱ`څijkl*уȥуnnnn𘪠`); H)h  hm Umɀ8` Vn `a먱ɀ ɎɏɆɇɐɢ ɘ əɜɝЇ` Pg g ᤠ : ,  5g`Le8 Ld f z, f z 7e둃La 7e%L*e Pg_:[ b` 멀 5g% ) bF 5g% Pg,8 5g f g)Ȋ) I챃` g gLeLԩ Pg: f68 ȱ ȱ{ Ryh{Ld RyhzLa f, f,A %z z0 we80e8ʆLeLe f,  fHh,b fʆ, f,ʆHe h8H hʅHHei hhHh Zghi Xgέh Zgh͓h h gLa e g .{ gii g g bg #g XgZT g0 >)˥ ZgLa6n7  ݀ )y %g %g #g̩x Zg g gLazHz 5g:7z  eLe{Hvpkn` g"ȱȱ fyƥLa:08``[A0{a0y g+y  ZgLe f ftĥ솥i hHЀ( Igw ~ }Lc[8ʆ %ze8zH IgbzLe IgsrЉi0i0 Igs yLa y : 5g`ȱɯ 5gLa`hhh ghh0 5g:`" fkn 5gLb"< fy% 5g0",H Um`)<ffx"850525COPYRIGHT 1983 COMPUTER TEACHING CV`譳``LY`ƹƸ ~ Ig8a{D `轀`lac``c`va`,c`aUa`ca``c%ea/e`aee` ` `/l ` H [ hI e }LdcLe f e3 }               ~`NO`0"a0 b0%{4&{/%{0*%{,)a {``8`F{`'{0a Um '{0 hmH)JJJiJhh΄`!{O{HHƥ!{ ɀzH ƀzn楥ğ n業'{)'{`{'{I '{${ь{0ɀНЁ{Ф'{ Т!{  ,LT|ĝ{{ n{枦L|ĝ͹ ,ɩ  M~  '{0 '{0,{ 0-{`+{({({ ){ n*{Ln ~ { } z~#{, g; [ i #g %gLv} ,ΥLr} |ş } { { I LH h` ~6?N2$kğ     ʀ {($ % ie g gݩ '{ ʀ#{{${ %z z y B { 4| x z { {!{{${'{"{X {LX| gĢ3H) |h {0({+{ € Y ?| € 4| i`+{{ z`H)h)U `z````ȱȱi{)ee{ `ƚeM{)I{暨`% e z$(e($H { {h` %`J ee8h8i{v8塍ov` y y`$%PRUW@)! yH)@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_hJ В`zzz` {z{`{z {` z e`{<8嚅થz { {iiz w{ w` x8z {ભ {Ltx઩ʊIe`8``i@i@`PPPP 03tɂ jz vʭ{lȃ) j)Ȅ%  ɃɃ xϤɃ80sh sh H sh s륊 ʩAзʩ:r0H Ksh` CsH _shɂɂ` `II`H) sh)!tb!tc bi  ts  sLs sʥ0`!t!t`llb p0x`;)-)"d0){fHEf hĨLEt%J00JfJJ)MIH rhH ʆ0  rȦh ʆ0 Ĩȱ r``%JJ H 2sh`e7tH0tH)t shH 0 y {Ldt vLurZq ` 9x%)H qhJJJJ@x qieĨL rH) qhJJJJ q0ׅ& & &  q@ & p& &  q & 8&퐋 ЇxHJJJJHi@ qhh) %).-439=> x 2w x wd0Lq  ȱ8` 0J)?e wLv 0 w "wLQp w wLQpȱHdVȱJħ  0 xz ȄLpJ뤨% yy xh` jz xzeLv`C880 xLv{81{L{G0P܅L pɀ`zUȌzK{FȌ{;Ȍz5Ȍz/Ȍz zLv zLv)%ooȌ{{ yLvȌ{АЌȌ{颜Ȍ{Ȍ{բȌ {ùٺ 215? L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195U W$JK$:W$:135:e W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0 TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #30"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u                 &@HLzyz            "9%<  > ? ??? ??~ >H?  ! ? !BD /O//O/  $BB@ zyzLH@L2~>""?@`P@@@~???????CT|`{}_\@[]  ~   ~   `2CTPACK2B,C,D,E????`8򅛥8ҥˆ yz0 𳦍J xJ J (x mv8塅&J 8 ix%I w &%E&'i') ȥ8娅z n{H{HzH h h{h{ Iz T(z nh` n`ƜЅ` ze`#{zcz`yyz{`y{zy`, z,̠BX gyx` `&{i` Bhz Yh G ih{!{"{'{` ƀ Y B ƀ!{${٬!{zH nhzĥ` g  NO g&H i Tz h n n#{I#{``z` gi gŜoH  ( THE DROP FALLS DURING A LINEAR INCREASE IN POTENTIAL.t PULSE POLAROGRAPHY,IS A TECHNIQUE IN WHICH A SERIES OF INCREASING PULSES IS APPLIED TO THE DME. ~ DIFFERENTIAL PULSE POLAROGRAPHY,IS A TECHNIQUE IN WHICH A SERIES OF PULSES ARE SUPERIMPOSED OE DIFFUSION CURRENT IS HALF ITS FULL VALUE.` CLASSICAL POLAROGRAPHY,IS A SPECIFIC TECHNIQUE IN WHICH THE DROPPING OF THE MERCURY IS EVIDENT ON THE RECORDER TRACE.6j SAMPLED DC POLAROGRAPHY,IS A TECHNIQUE IN WHICH THE CURRENT IS SAMPLED JUST BEFORETRY,IS THE NAME GIVEN TO THE GENERAL TECHNIQUE IN WHICH THE WORKING ELECTRODE IS A STATIONARY ELECTRODE.L THE DIFFUSION CURRENT,IS THE CURRENT DUE TO THE PRESENCE OF THE ELECTROACTIVE SPECIES.+V THE HALF-WAVE POTENTIAL,IS THE POTENTIAL AT WHICH THLUTION.. THE DROPPING MERCURY ELECTRODE,"IS AN ELECTRODE, THE SURFACE OF WHICH IS CONTINUOUSLY RENEWED DURING THE EXPERIMENT."8 POLAROGRAPHY,IS THE GENERAL TECHNIQUE IN WHICH THE DROPPING MERCURY ELECTRODE IS THE WORKING ELECTRODE.hB VOLTAMMEINTEREST OCCURS IN AN ELECTROCHEMICAL CELL. THE COUNTER ELECTRODE,IS THE ELECTRODE AT WHICH NO ANALYTICALLY SIGNIFICANT PROCESS OCCURS.$ THE SUPPORTING ELECTROLYTE,IS A SUBSTANCE THAT PROVIDES THE CONCENTRATION OF INACTIVE IONS TO THE ANALYTE SO THE CURRENT THAT FLOWS IS A FORCED CURRENT RESULTING FROM A POWER SOURCE IN THE CIRCUIT. CONDUCTIMETRY,IS A TECHNIQUE FOR DETERMINING WHETHER THERE ARE IONS PRESENT IN A SOLUTION.+ THE WORKING ELECTRODE,IS THE ELECTRODE AT WHICH THE PROCESS OF ********"W0RY:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN, PRESS ."Z\R$af6g A GALVANIC CELL,"IS A CELL IN WHICH THE CURRENT FLOWS SPONTANEOUSLY, WITH NO EXTERNAL POWER SOURCE."Y AN ELECTROLYTIC CELL,IS A CELL IN WHICH**********************************")8>9" ";NA$D:z<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #30"M R"********************************:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::#6"*****ER CORRECT = "CR+50" NUMBER WRONG = "IRc5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 ETE THE FOLLOWING: ":7:JK$" "A$(AO(P)):195:Z:"THE CORRECT ANSWER IS: ":y:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUMB::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPLJK$" E) NONE OF THESE":195$ G$4 G$"A"G1D G$"B"G2T G$"C"G3d G$"D"G4t G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT! THE ANSWER IS: ";G$:"PRESS .":510JK,E: / ::JK$" "A$(AO(P)):1955 U JK$" A) "B$(C(F(1))):195c SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ  6HC1605 ;SW39+ ^P1J:355:4151 cE hQ15:C(Q)0:S mQ14FSx rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 15ĺD$;"RUN ACT2QU12,D1")'S16ė:138,S16ī165F1S10ī12 " THESE ARE MULTIPLE CHOICE QUIZZES. SELECT THE BEST ANSWER TO EACH QUESTION.AFTER YOU HAVE BEEN ASKED A PARTICULAR NUMBER OF QUESTIONS, THE COMPUTER WILL CALCULATE YOUR GRADON MECHANISMS. AN AMPEROMETRIC TITRATION,IS A TECHNIQUE IN WHICH A DECREASE IN DIFFUSION CURRENT IS OBSERVED AS A REACTING SPECIES IS ADDED. END,ACT2QU122AN THE LINEAR POTENTIAL INCREASE. STRIPPING VOLTAMMETRY,IS A TECHNIQUE IN WHICH THE ANALYTE IS PRECONCENTRATED IN OR ON THE WORKING ELECTRODE PRIOR TO A REVERSE POTENTIAL SCAN. CYCLIC VOLTAMMETRY,IS A GOOD TECHNIQUE FOR STUDYING ELECTRODE REACTIS IN- STALLED AND ALLIGNED PROPERLY."P:" PRESS TO CONTINUE."XN$^ THE PRINTOUT TO YOURINSTRUCTOR. BE SURE THAT YOUR PRINTER IS ON AND CONNECTED TO YOUR COMPUTER. ALSO, BE SURE THAT THE PAPER IS IN- STALLED AND ALLIGNED PROPERLY.":" PRESS TO CONTINUE."N$ S, BE SURE THAT THE PAPER IE AND DISPLAY IT ON THE SCREEN.":" YOU WILL THEN HAVE THE OPTION OF RE- PEATING THE QUIZ TO IMPROVE YOUR GRADE. AFTER YOU HAVE A GRADE THAT YOU ARE SATISFIED WITH, THE COMPUTER WILL PRINT YOUR GRADE ON THE PRINTER.":" YOU CAN THEN TAKEN@@ SOLUTION IF IT IS TO BE USED AS IN EQUATION (@@R@@) OF THE HANDOUT?,20.5 @HH@@OW MANY GRAMS OF IRON METAL ARE REQUIRED TO PREPARE 400.0 M@@L@@ OF A 0.400 @@N@@ SOLUTION IF IT IS TO BE USED AS IN EQUATION (@@Q@@) OF THE HANDOUT?,2.98$ @HH@@OWOW MANY GRAMS OF CHROMIUM METAL ARE REQUIRED TO PREPARE 600.0 M@@L@@ OF A 0.150 @@N@@ SOLUTION IF IT IS TO BE USED AS IN EQUATION (@@R@@) OF THE HANDOUT?,1.56L @HH@@OW MANY GRAMS OF @@N@@A@D3@@PO@D4 @@ARE REQUIRED TO PREPARE 500.0 M@@L@@ OF A 0.500 @@UTION IF IT IS TO BE USED AS IN EQUATION (@@S@@) OF THE HANDOUT?,1.47 @HH@@OW MANY GRAMS OF @@N@@A@D3@@PO@D4 @@ARE REQUIRED TO PREPARE 700.0 M@@L@@ OF A 0.200 @@N@@ SOLUTION IF IT IS TO BE USED AS IN EQUATION (@@S@@) OF THE HANDOUT?,4.59 @HH@@ QUIZ #17"MCR"***************************************"JW0Y:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN,PRESS .\R$a6E @HH@@OW MANY GRAMS OF NICKEL METAL ARE REQUIRED TO PREPARE 500 M@@L@@ OF A 0.100 @@N@@ SOL YOUR INSTRUCTOR.SEE YOU NEXT TIME!"/41::^6"***************************************"d8y9" ";NA$:<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" <G$?G$"Y"125%DG$"N"800.S5704 <*:B,$/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO:!LCRIR:L0L16&" NUMBER CORRECT = "CR<+[0" NUMBER WRONG = "IR5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;ZF$"@H"515WJK$" YOU ARE CORRECT! THE ANSWER IS: "B$(AO(P)):195:" PRESS ."hCRCR1:525JK$"WRONG! THE CORRECT ANSWER IS: "B$(AO(P)):195:" PRESS ."IRIR1 ICC1C7535P::::JK$"@H C) "B$(C(F(3))):195GJK$"@H D) "B$(C(F(4))):195nJK$"@H E) NONE OF THESE":195{ZF$"@H"IA"@HA,B,C,D,E"ZA$"A"G1ZA$"B"G2ZA$"C"G3ZA$"D"G4ZA$"E"G5C(F(G))AO(P)O1:C(K)C(Q)370 |K/ Q:C(5FS)AO(P)= E15FSZ F(E)((5FS)(5FS))1y KE101:F(K)F(E)395 K,E  ::JK$" "A$(AO(P)):195  JK$"@H A) "B$(C(F(1))):195 JK$"@H B) "B$(C(F(2))):195! J1NM:A$(J),B$(J):A$(J)"END"235/ J5 ? JJ1J I1J` AO(I)(J(J))1u NP(AO(I))1275 NP(AO(I))1:I 'FS0 ;SW38 ^P1J cN hQ15:C(Q)0: mQ14FS rC(Q)(J(J))1:C(Q)AO(P)370 wKQ10:N:::::"ONE MOMENT, PLEASE ....."2 NM35S AO(NM),A$(NM),B$(NM),NP(NM)\ 225x XK(0):(JK$)SW215 TSWO1:(JK$,T,1)" "210 T:215 L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195 W$JK$:W$: W$:( ACTPACK" 35326 NN ::::"TYPE YOUR NAME THEN PRESS ."[ ZF$"@H"c :j Iw NA$ZA$ "GOOD LUCK, ";NA$ :"PRESS ANY KEY." TIMER11E8 A(16384) A127SEEDTIMER:179 ( Z(SEED):16368, TEXT ARE USEFUL FOR THIS QUIZ. A HANDOUT IS REQUIRED. IF YOU DO NOT ALREADY HAVE THIS HANDOUT, SEE YOUR INSTRUCTOR." q: t"PRESS ." vN$ | }IR0 CR0 : 6:5:"ONE MOMENT, PLEASE....." (13);(4);"BRUN C026::F7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"eA" QUIZ #17"qZ:::n" SPECIAL INSTRUCTIONS:"o:::| p" THE TABLES OF MOLECULAR AND ATOMIC WEIGHTS ON THE INSIDE FRONT AND BACK COVERS OF THE          20:JK$" "(JK$,((JK$))T):1954 W$JK$:W$:> W$:h J1NM:A$(J),B$(J):A$(J)"END"235o Ju  JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I 'FS0 ;SW38 ^P1J cN hQ15:C(Q)0:16384)" A127SEEDTIMER:179( h Z(SEED):16368,0:N:::::"ONE MOMENT, PLEASE ....."r NM35 AO(NM),A$(NM),B$(NM),NP(NM) 225 XK(0):(JK$)SW215 TSWO1:(JK$,T,1)" "210 T:215# L$(JK$,T):W$L$:2:* 6:5:"ONE MOMENT, PLEASE....."I (13);(4);"BRUN ACTPACK"T 35326[ N ::::"TYPE YOUR NAME THEN PRESS ." ZF$"@H" : I NA$ZA$ "GOOD LUCK, ";NA$ :"PRESS ANY KEY." TIMER11E8 A([ C026::F7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"gA" QUIZ # 19"sZ:::n" SPECIAL INSTRUCTIONS:"o:::p" NONE"q::t"PRESS ."vN$|}IR0CR0       67 GRAMS OF THE SAMPLE ACCORDING TO EQUATION (@@C@@) OF THE HANDOUT?,17.86" @HW@@HAT IS THE PERCENT OF @@KNO@D3 @@IN A SAMPLE IF 30.19 M@@L@@ OF 0.3012 @@N KC@@L ARE NEEDED TO CONSUME 0.9345 GRAMS OF SAMPLE ACCORDING TO EQUATION (@@B@@) OF THE HANDOUTKNO@D3 @@ARE NEEDED TO CONSUME 0.7502 GRAMS OF THE SAMPLE ACCORDING TO EQUATION (@@D@@) OF THE HANDOUT?,21.83J! @HW@@HAT IS THE PERCENT OF @@N@@A@@C@@L@@O @@IN A SAMPLE IF 39.78 M@@L@@ OF A 0.1102 @@N@@ SOLUTION OF @@KNO@D3 @@ARE NEEDED TO CONSUME 0.45@ OF A 0.1820 @@N@@ SOLUTION OF @@KC@@L@@O@D3 @@ARE NEEDED TO CONSUME 0.3045 GRAMS OF SAMPLE ACCORDING TO EQUATION (@@E@@) OF THE HANDOUT?,32.43m  @HW@@HAT IS THE PERCENT OF @@N@@A@@C@@L@@O @@IN A SAMPLE IF 29.29 M@@L@@ OF A 0.1502 @@N@@ SOLUTION OF @@F @@K@D2SO@D4 @@IN A SAMPLE IF 35.01 M@@L@@ OF 0.1923 @@N KB@@R@@O@D3 @@SOLUTION ARE NEEDED TO CONSUME 0.7910 GRAMS OF SAMPLE ACCORDING TO EQUATION (@@F@@) OF THE HANDOUT?,74.16 @HW@@HAT IS THE PERCENT OF @@N@@A@D2@@SO@D4 @@IN A SAMPLE IF 30.56 M@@L@HE HANDOUT?,0.8312~ @HW@@HAT IS THE PERCENT @@SO@D3 @@IN A SAMPLE IF 45.69 M@@L@@ OF A 0.2011 @@N@@ SOLUTION OF @@KIO@D4 @@ARE NEEDED TO CONSUME 0.9308 GRAMS OF SAMPLE ACCORDING TO EQUATION (@@G@@) OF THE HANDOUT?,9.879 @HW@@HAT IS THE PERCENT O IT REACTS EXACTLY WITH 0.7722 GRAMS OF @@SO@D3 @@AS IN EQUATION (@@K@@) OF THE HANDOUT?,2.866t @HW@@HAT IS THE NORMALITY OF A SOLUTION OF @@KC@@L IF 39.89 M@@L@@ OF IT REACTS EXACTLY WITH 0.7849 GRAMS OF @@N@@A@D2@@SO@D4 @@AS IN EQUATION (@@J@@) OF T1.536` @HW@@HAT IS THE NORMALITY OF A SOLUTION OF @@KI@@ IF 18.34 M@@L@@ OF IT EXACTLY REACTS WITH 0.4520 GRAMS OF @@KNO@D3 @@AS IN EQUATION (@@L@@) OF THE HANDOUT?,1.219^j @HW@@HAT IS THE NORMALITY OF A SOLUTION OF @@N@@A@@B@@R IF 20.19 M@@L@@ OFCTS WITH 0.9123 GRAMS OF @@KI@@ AS IN EQUATION (@@L@@) OF THE HANDOUT?,0.5606V @HW@@HAT IS THE NORMALITY OF A SOLUTION OF @@N@@A@D2@@SO@D4 @@IF 34.97 M@@L@@ OF IT EXACTLY REACTS WITH 0.3923 GRAMS OF @@N@@A@@C@@L AS IN EQUATION (@@J@@) OF THE HANDOUT?,HAT IS THE NORMALITY OF A SOLUTION OF @@KIO@D4 @@IF 28.90 M@@L@@ OF IT EXACTLY REACTS WITH 0.5293 GRAMS OF PHOSPHORUS AS IN EQUATION (@@M@@) OF THE HANDOUT?,2.957ML @HW@@HAT IS THE NORMALITY OF A SOLUTION OF @@KNO@D3 @@IF 39.21 M@@L@@ OF IT EXACTLY REA IF IT IS TO BE USED AS IN EQUATION (@@P@@) OF THE HANDOUT?,1.038 @HW@@HAT IS THE NORMALITY OF A SOLUTION OF @@KB@@R@@O@D3 @@IF 34.23 M@@L@@ OF IT EXACTLY REACTED WITH 0.6012 GRAMS OF @@SO@D2 @@AS IN EQUATION (@@N@@) OF THE HANDOUT?,0.5483B @HW@@ MANY GRAMS OF @@P@D2O@D5 @@ARE REQUIRED TO PREPARE 300.0 M@@L@@ OF A 0.450 @@N@@ SOLUTION IF IT IS TO BE USED AS IN EQUATION (@@Q@@) OF THE HANDOUT?,1.92@. @HH@@OW MANY GRAMS OF PHOSPHORUS ARE REQUIRED TO PREPARE 500.0 M@@L@@ OF A 0.200 @@N@@ SOLUTIONLIGHT THAT HAS AN ENERGY OF 5.20 @@X@@ 10@U-@U1@U9 ERGS?,382 @@CM8 @HW@@HAT IS THE WAVE NUMBER OF LIGHT THAT HAS A WAVELENGTH OF 0.000345 CM?,2.9 X 10@U3 @@CM@U-@U1B @HW@@HAT IS THE WAVELENGTH OF LIGHT THAT HAS A WAVE NUMBER OF 6.92 @@X@@ 10@U7 Ce @HW@@HAT IS THE ENERGY OF LIGHT THAT HAS A WAVELENGTH OF 0.0945 CM?,2.10 X 10@U-@U1@U5 @@ERGS$ @HW@@HAT IS THE FREQUENCY OF LIGHT THAT HAS AN ENERGY OF 9.34 @@X@@ 10@U-@U2@U3 ERGS?,1.41 X 10 @U4 @@SEC@U-@U1A. @HW@@HAT IS THE WAVELENGTH OF OF 873 NM?,3.44 X 10@U1@U4 @@SEC@U-@U1 @HW@@HAT IS THE FREQUENCY OF LIGHT THAT HAS A WAVELENGTH OF 346 CM?,8.67 X 10@U7 @@SEC@U-@U1 @HW@@HAT IS THE ENERGY OF LIGHT THAT HAS A FREQUENCY OF 4.02 @@X@@ 10@U1@U3 SEC@U-@U1?,2.66 X 10@U-@U1@U3 @@ERGSH OF LIGHT THAT HAS A FREQUENCY OF 4.89 @@X@@ 10@U1@U2 SEC@U-@U1?,6.14 X 10@U-@U3 @@CM @HW@@HAT IS THE WAVELENGTH OF LIGHT THAT HAS A FREQUENCY OF 3.12 @@X@@ 10@U1@U4 SEC@U-@U1?,962 @@NM& @HW@@HAT IS THE FREQUENCY OF LIGHT THAT HAS A WAVELENGTH "ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"0DOE" QUIZ #19"UMR"***************************************"W0Y:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN,PRESS .\R$a6V @HW@@HAT IS THE WAVELENGT PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"o41::6"***************************************"89" ";NA$:<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">*CEN . IF NOT, PRESS 'N' THEN .=;ZF$"@H"E<G$U?G$"Y"125eDG$"N"800nS570t |*:,d/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE IRIR1 ICC1%C7535,P2B:::::W!LCRIR:L0L1v&" NUMBER CORRECT = "CR|+0" NUMBER WRONG = "IR5:" STUDENT SCORE = ";(CR100L);"%"0::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THA$"C"G3ZA$"D"G4,ZA$"E"G5DC(F(G))AO(P)515JK$" YOU ARE CORRECT! THE ANSWER IS: "B$(AO(P)):195:" PRESS ."CRCR1:525JK$"WRONG! THE CORRECT ANSWER IS: "B$(AO(P)):195:" PRESS ."A) "B$(C(F(1))):195; JK$"@H B) "B$(C(F(2))):195a JK$"@H C) "B$(C(F(3))):195 JK$"@H D) "B$(C(F(4))):195 JK$"@H E) NONE OF THESE":195 ZF$"@H" I A"@HA,B,C,D,E" ZA$"A"G1 ZA$"B"G2 Z mQ14FS4 rC(Q)(J(J))1:C(Q)AO(P)370S wKQ1O1:C(K)C(Q)370Z |Ko Q:C(5FS)AO(P)} E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 K,E  ::JK$" "A$(AO(P)):195  JK$"@H ?,24.60" @HW@@HAT IS THE PERCENT OF @@N@@A@@C@@L IN A SAMPLE IF 28.27 M@@L@@ OF 0.2303 @@N KNO@D3 @@ARE NEEDED TO CONSUME 0.6783 GRAMS OF SAMPLE ACCORDING TO EQUATION (@@A@@) OF THE HANDOUT?,9.349" END,ACT1QU1722ILVER IONS TO FORM SILVER METAL AND CERIUM(IV)?,-0.64 VOLTS. ASSUMING STANDARD CONDITIONS - WHAT IS THE E FOR A CELL IN WHICH IRON(III) REACTS WITH ZINC METAL TO FORM IRON(II) AND ZINC IONS?,+1.53 VOLTS8"IF THE E (UNDER STANDARD CONDITIONS) FOR TNG STANDARD CONDITIONS - WHAT IS THE E FOR A CELL IN WHICH MERCURY(II) IONS REACT WITH CERIUM(III) IONS TO FORM MERCURY METAL AND CERIUM(IV) IONS?,-0.59 VOLTS;$ ASSUMING STANDARD CONDITIONS - WHAT IS THE E FOR A CELL IN WHICH CERIUM(III) REACTS WITH S REACTS WITH IRON METAL TO FORM TIN(II) IONS AND FERRIC IONS?,+0.19 VOLTS ASSUMING STANDARD CONDITIONS - WHAT IS THE E FOR A CELL IN WHICH COPPER(II) IONS REACT WITH CHROMIUM METAL TO FORM COPPER METAL AND CHROMIUM(III) IONS?,+1.08 VOLTS ASSUMI,+2.15 VOLTS ASSUMING STANDARD CONDITIONS - WHAT IS THE E FOR A CELL IN WHICH IRON METAL REACTS WITH MANGANOUS ION TO FORM FERROUS ION AND MANGANESE METAL?,-0.62 VOLTSI ASSUMING STANDARD CONDITIONS - WHAT IS THE E FOR A CELL IN WHICH TIN(IV) ION***************"W0X\:"IF YOU WOULD LIKE TO SEE THE MENU AGAIN,PRESS ."`aR$gf6m  UNDER STANDARD CONDITIONS - WHAT IS THE E FOR A CELL IN WHICH NICKEL ION REACTS WITH MAGNESIUM METAL TO FORM MICKEL METAL AND MAGNESIUM ION?"***************************************"08E9" ";NA$K:<" HAS ACHIEVED A SCORE OF ";(CR100L);"%">C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #18"MR"************************ *:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::*6 NUMBER CORRECT = "CR+<0" NUMBER WRONG = "IRj5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570! THE ANSWER IS: "B$(AO(P)):195:" PRESS "HCRCR1:525:JK$" WRONG! THE CORRECT ANSWER IS: "B$(AO(P)):195:" PRESS "IRIR1 R$CC1C7ī535P::::!LCRIR:L0L1&" " D) "B$(C(F(4))):195& FS14754 SW40ĺU JK$" E) NONE OF THESE":195] G$m G$"A"G1} G$"B"G2 G$"C"G3 G$"D"G4 G$"E"G5 G1475 G5FS475 C(F(G))AO(P)5157:JK$" YOU ARE CORRECT(E)((5FS)(5FS))16 KE101:F(K)F(E)395A K,E:G h ::JK$" "A$(AO(P)):195n  JK$" A) "B$(C(F(1))):195 SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$ NP(AO(I))1275( NP(AO(I))1:I. "7 'FS0E 6HC1605O ;SW39d ^P1J:355:415j c~ hQ15:C(Q)0: mQ14FS rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(JK$)SW2150 TSWO1:(JK$,T,1)" "210< T:215x L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195 W$JK$:W$:135: W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1THIS QUIZ." r:::3 s" PRESS ANY KEY."D uTIMER11E8T wA(16384)o xA127SEEDTIMER:122u y zZ(SEED):16368,0 {:"ONE MOMENT, PLEASE, ";NA$ | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 F1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #18"Z:::n" SPECIAL INSTRUCTIONS:" q:" TABLE 2 IN CHAPTER 10 OF THE TEXT IS USEFUL FOR           6.76 X 10@U-@U1@U1 @@ERGS @HW@@HAT IS THE FREQUENCY OF LIGHT THAT HAS AN ENERGY OF 4.37 @@X@@ 10@U-@U1@U1 ERGS?,6.60 X 10@U1@U5 @@SEC@U-@U1 @HW@@HAT IS THE WAVELENGTH OF LIGHT THAT HAS AN ENERGY OF 4.91 @@X@@ 10@U-@U1@U2 ERGS?,404 @@NM[ @HAT HAS A WAVELENGTH OF 638 NM?,4.70 X 10@U1@U4 @@SEC@U-@U1~ @HW@@HAT IS THE ENERGY OF LIGHT THAT HAS A FREQUENCY OF 5.21 @@X@@ 10@U1@U5 SEC@U-@U1?,3.45 X 10@U-@U1@U1 @@ERGS @HW@@HAT IS THE ENERGY OF LIGHT THAT HAS A WAVELENGTH OF 0.00000294 CM?,HAT IS THE WAVELENGTH OF LIGHT THAT HAS A FREQUENCY OF 5.83 @@X@@ 10@U1@U3 SEC@U-@U1?,5.15 X 10@U3 @@NMj @HW@@HAT IS THE FREQUENCY OF LIGHT THAT HAS A WAVELENGTH OF 0.0000239 CM?,1.26 X 10@U1@U5 @@SEC@U-@U1:t @HW@@HAT IS THE FREQUENCY OF LIGHT THM@U-@U1?,1.45 X 10@U-@U8 @@CML @HW@@HAT IS THE WAVE NUMBER OF LIGHT THAT HAS A WAVELENGTH OF 539 NM?,1.86 X 10@U4 @@CM@U-@U1V @HW@@HAT IS THE WAVELENGTH OF LIGHT THAT HAS A FREQUENCY OF 7.39 @@X@@ 10@U1@U2 SEC@U-@U1?,4.06 X 10@U3 @@CMg` @HW@@NCENTRATION OF THE TIN IONS IS 0.01M?,-2.63 VOLTSD" END,ACT1QU182TEL METAL IF THE CONCENTRATION OF THE BERYLLIUM IONS IS 0.01M AND THE CONCENTRATION OF THE NICKEL IONS IS 0.10M?,-1.50 VOLTS1" WHAT IS THE E FOR A CELL IN WHICH SODIUM IONS REACT WITH TIN METAL IF THE CONCENTRATION OF THE SODIUM IONS IS 0.01M AND THE CO WHAT IS THE E FOR A CELL IN WHICH NICKEL IONS REACT WITH ZINC METAL IF THE CONCENTRATION OF THE ZINC IONS IS 0.00001M AND THE CONCENTRATION OF THE NICKEL IONS IS 0.0001M?,+0.56 VOLTS{! WHAT IS THE E FOR A CELL IN WHICH BERYLLIUM IONS REACT WITH NICKONCENTRATION OF THE MERCURY IONS IS 0.001M?,+0.84 VOLTS WHAT IS THE E FOR A CELL IN WHICH COPPER METAL REACTS WITH MANGANOUS IONS IF THE CONCENTRATION OF THE COPPER IONS IS 0.0001M AND THE CONCENTRATION OF THE MANGANOUS IONS IS 0.01M?,-1.31 VOLTS TIONS ARE: CERIUM(IV) IONS - 0.01M, CERIUM(III) IONS - 0.001M, AND SILVER IONS - 0.01M?",+0.76 VOLTS7 WHAT IS THE E FOR A CELL IN WHICH MERCURY IONS REACT WITH IRON METAL (TO FORM FERRIC IONS) IF THE CONCENTRATION OF THE FERRIC IONS IS 0.01M AND THE CLL IN WHICH TIN(II) IONS REACT WITH MAGNESIUM METAL TO GIVE TIN METAL WHEN THE CONCENTRATIONS ARE: MAGNESIUM IONS - 0.01M, TIN(II) IONS - 0.001M?",+2.21 VOLTSd "WHAT IS THE E FOR A CELL IN WHICH CERIUM(IV) IONS REACT WITH SILVER METAL IF THE CONCENTRAM?",-2.75 VOLTSt "IF THE E (AT STANDARD CONDITIONS) FOR THE REACTION OF MAGNESIUM IONS WITH MERCURY METAL IS -3.23 V., WHAT IS THE E IF THE CONCENTRATIONS ARE: MAGNESIUM IONS - 0.0001M, MERCURY IONS - 0.001M?",-3.20 VOLTS~ "WHAT IS THE E FOR A CENS - 0.01M, FERROUS IONS - 0.0001M?",-2.30 VOLTSj "IF THE E (UNDER STANDARD CONDITIONS) FOR THE REACTION OF K IONS WITH TIN METAL IS -2.78 V., WHAT IS THE E IF THE CONCENTRATION OF THE K IONS IS 0.10M AND THE CONCENTRATION OF THE TIN(II) IONS IS 0.001 WHAT IS THE E IF THE CONCENTRATION OF ALL IONS INVOLVED IS 0.001M?",+1.57 VOLTS0` "IF THE E (AT STANDARD CONDITIONS) FOR THE REACTION OF SODIUM IONS WITH IRON METAL (TO GIVE FERROUS IONS) IS -2.30 V., WHAT IS THE E IF THE CONCENTRATIONS ARE: SODIUM IOERRIC IONS) IS +0.03 VOLTS, WHAT IS THE E IF THE CONCENTRATIONS OF ALL THE IONS INVOLVED ARE EQUAL AT 0.01M?",-0.09 VOLTSPV "IF THE E (UNDER STANDARD CONDITIONS) FOR THE REACTION OF CHROMIUM METAL WITH FERRIC IONS (TO GIVE FERROUS IONS) IS +1.51 VOLTS,IONS WITH COPPER METAL IS -3.39 VOLTS, WHAT IS THE E IF THE LITHIUM ION CONCENTRATION IS 0.10M AND THE COPPER ION CONCENTRATION IS 0.001M?",-3.36 VOLTSyL "IF THE E (UNDER STANDARD CONDITIONS) FOR THE REACTION OF SILVER IONS WITH FERROUS IONS (TO GIVE FHE REACTION OF ZINC IONS WITH IRON METAL (TO GIVE FERRIC IONS) IS -0.72 V, WHAT IS THE E IF THE ZINC ION CONCENTRATION IS 0.01M AND THE FERRIC ION CONCENTRATION IS 0.001M?",-0.72 VOLTSB"IF THE E (UNDER STANDARD CONDITIONS) FOR THE REACTION OF LITHIUM EQUAL TO 1.00E-7 CM.,NANOMETER`B THIS UNIT OF DISTANCE IS EQUAL TO 1.00E-10 METERS.,ANGSTROML A LIGHT WAVE THAT HAS A SHORTER WAVELENGTH THAN EITHER INFRARED OR ULTRAVIOLET MIGHT BE A(N),X-RAYGV A LIGHT WAVE THAT IS INTERMEDIATE IN ENERGY BETWAGNETIC WAVEj$ IN COMPARING BLUE LIGHT TO RED LIGHT - ONE PARAMETER THAT IS THE SAME FOR BOTH IS,SPEED. THIS LIGHT PARAMETER IS THE RECIPROCAL OF THE WAVELENGTH AND IS DIRECTLY PROPORTIONAL TO FREQUENCY.,WAVE NUMBER8 THIS UNIT OF DISTANCE IS PARTICLES EACH OF WHICH IS CALLED A(N),PHOTON  THE WAVE THEORY OF LIGHT STATES THAT LIGHT CONSISTS OF A WAVELIKE DISTURBANCE THAT HAS BOTH A MAGNETIC COMPONENT AND AN ELECTRIC COMPONENT. FOR THIS REASON WE DESCRIBE A LIGHT WAVE AS BEING A(N),ELECTROMS THAT PASS A FIXED POINT IN ONE SECOND?,FREQUENCY WHAT LIGHT PARAMETER IS DEFINED MATHEMATICALLY AS THE PRODUCT OF PLANCK'S CONSTANT AND THE FREQUENCY?,ENERGY- THE PARTICLE THEORY OF LIGHT STATES THAT A BEAM OF LIGHT IS COMPOSED OF A STREAM OF E THE MENU AGAIN, PRESS ."*\R$1f67 WHAT LIGHT PARAMETER IS DEFINED AS THE DISTANCE FROM A POINT ON ONE WAVE OF LIGHT TO THE SAME POINT ON THE NEXT WAVE?,WAVELENGTH2 WHAT LIGHT PARAMETER IS DEFINED AS THE NUMBER OF LIGHT WAVE ";NA$:J<" HAS ACHIEVED A SCORE OF ";(CR100L);"%"P>C"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"DE" QUIZ #20"MR"***************************************"W0"Y:"IF YOU WOULD LIKE TO SEDRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::6"***************************************"89"= "IR35:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 *:/" PLEASE REMOVE THE DISK FROM THE CRCR1:525d:JK$" WRONG! THE CORRECT ANSWER IS: "B$(AO(P)):195:" PRESS "pIRIR1x R$CC1C10ī535P::::!LCRIR:L0L1&" NUMBER CORRECT = "CR+0" NUMBER WRONG JK$" E) NONE OF THESE":195% G$5 G$"A"G1E G$"B"G2U G$"C"G3e G$"D"G4u G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 :JK$" YOU ARE CORRECT! THE ANSWER IS: "B$(AO(P)):195:" PRESS " K,E: 0 ::JK$" "A$(AO(P)):1956 V JK$" A) "B$(C(F(1))):195d SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ 6HC1605 ;SW39, ^P1J:355:4152 cF hQ15:C(Q)0:T mQ14FSy rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215@ L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195V W$JK$:W$:135:f W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0TIMER11E8 wA(16384)7 xA127SEEDTIMER:122= yV zZ(SEED):16368,0x {:"ONE MOMENT, PLEASE, ";NA$~ | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #20"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u        A WAVE NUMBER OF 3.19 @@X@@ 10@U4 CM@U-@U1?,9.57 X 10@U1@U4 @@SEC@U-@U1Y END,ACT2QU12W@@HAT IS THE WAVE NUMBER OF LIGHT THAT HAS A WAVELENGTH OF 632 NM?,1.58 X 10@U4 @@CM@U-@U1 @HW@@HAT IS THE WAVE NUMBER OF LIGHT THAT HAS A FREQUENCY OF 1.31 @@X@@ 10@U1@U2 SEC@U-@U1?,43.7 @@CM@U-@U1G @HW@@HAT IS THE FREQUENCY OF LIGHT THAT HAS IS CHARACTERISTIC OF THE ABSORPTION OF LIGHT BY A(N),MOLECULE A LINE ABSORPTION SPECTRUM IS CHARACTERISTIC OF THE ABSORPTION OF LIGHT BY A(N),ATOM END,ACT2QU22OOMS OVER A PARTICULAR WAVELENGTH RANGE IS CALLED A(N),LINE SPECTRUM AN ABSORPTION SPECTRUM REPRESENTING THE ABSORPTION BEHAVIOR OF MOLECULES OVER A PARTICULAR WAVELENGTH RANGE IS CALLED A(N),CONTINUOUS SPECTRUM= A CONTINUOUS ABSORPTION SPECTRUM ANSITION THE GENERAL NAME FOR A PLOT OF ABSORPTION VS WAVELENGTH SHOWING THE ABSORPTION BEHAVIOR OF A SAMPLE OVER A PARTICULAR WAVELENGTH RANGE IS CALLED A(N),ABSORPTION SPECTRUMC AN ABSORPTION SPECTRUM REPRESENTING THE ABSORPTION BEHAVIOR OF AT AN ENERGY TRANSITION THAT INVOLVES ROCKING AND BENDING MOTIONS OF BONDS WITHIN A MOLECULE IS CALLED A(N),VIBRATIONAL TRANSITION AN ENERGY TRANSITION IN ATOMS AND MOLECULES THAT IS CAUSED BY ULTRAVIOLET AND VISIBLE LIGHT IS CALLED A(N),ELECTRONIC TRLIGHT AND CAUSES ELECTRONIC ENERGY TRANSITION IN ATOMS AND MOLECULES IS A(N),ULTRAVIOLET WAVEt A LIGHT WAVE THAT IS CONSIDERED TO BE A RELATIVELY LOW ENERGY LIGHT THAT CAUSES VIBRATIONAL ENERGY TRANSITIONS IN MOLECULES WOULD BE A(N),INFRARED WAVE~EEN AN ULTRAVIOLET WAVE AND AN INFRARED WAVE WOULD BE A(N),VISIBLE WAVE` A LIGHT WAVE THAT HAS THE LOWEST ENERGY OF ALL LIGHT WAVES IN THE ELECTROMAGNETIC SPECTRUM IS A(N),RADIO OR TV WAVE]j A LIGHT WAVE THAT HAS A SHORTER WAVELENGTH THAN VISIBLE /MOLE CM, THE PATHLENGTH IS 1.00 CM, AND THE CONCENTRATION IS 0.000187 M?",0.886L "WHAT IS THE % TRANSMITTANCE WHEN THE MOLAR ABSORPTIVITY IS 1.86 E 2 L/MOLE CM, THE PATHLENGTH IS 1.00 CM AND THE CONCENTRATION IS 0.000427 M?",83.3{V "WHAT IS THE MABSORBANCE IS 0.504?",8038 "WHAT IS THE PATHLENGTH IN CM WHEN THE MOLAR ABSORPTIVITY IS 1.32 E 3 L/MOLE CM, THE CONCENTRATION IS 0.0000923 M, AND THE ABSORBANCE IS 0.493?",4.05PB "WHAT IS THE TRANSMITTANCE WHEN THE MOLAR ABSORPTIVITY IS 2.81 E 2 L THE CONCENTRATION IN MOLARITY IF THE MOLAR ABSORPTIVITY IS 1.29 E 3 L/MOLE CM, THE PATHLENGTH IS 1.00 CM AND THE ABSORBANCE IS 0.340?",0.000264. "WHAT IS THE MOLAR ABSORPTIVITY WHEN THE CONCENTRATION IS 0.000628 M, THE PATHLENGTH IS 1.00 CM, AND THE S 0.293?,0.509Y WHAT IS THE % TRANSMITTANCE GIVEN THAT THE ABSORBANCE IS 0.702?,19.9 "WHAT IS THE ABSORBANCE GIVEN THAT THE ABSORPTIVITY IS 2.30 E 4 L/MOLE CM, THE PATHLENGTH IS 1.00 CM, AND THE CONCENTRATION IS 0.0000453 M?",1.04$ "WHAT ISU AGAIN, PRESS ."!\R$(f6.x WHAT IS THE ABSORBANCE GIVEN THAT THE TRANSMITTANCE IS 0.657?,0.182 WHAT IS THE ABSORBANCE GIVEN THAT THE % TRANSMITTANCE IS 46.3%?,0.334 WHAT IS THE TRANSMITTANCE GIVEN THAT THE ABSORBANCE I";NA$ :A<" HAS ACHIEVED A SCORE OF ";(CR100L);"%"G>vC"ON ANALYTICAL CHEMISTRY FOR TECHNICIANS"|DE" QUIZ #21"MR"***************************************"W0Y:"IF YOU WOULD LIKE TO SEE THE MENVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::6"***************************************"9" IR05:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 *:/" PLEASE REMOVE THE DISK FROM THE DRICRCR1:525b:JK$" WRONG! THE CORRECT ANSWER IS: "B$(AO(P)):195:" PRESS "nIRIR1v R$CC1C7ī535P::::!LCRIR:L0L1&" NUMBER CORRECT = "CR+0" NUMBER WRONG = "K$" E) NONE OF THESE":195# G$3 G$"A"G1C G$"B"G2S G$"C"G3c G$"D"G4s G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 :JK$" YOU ARE CORRECT! THE ANSWER IS: "B$(AO(P)):195:" PRESS "K,E: . ::JK$" "A$(AO(P)):1954 T JK$" A) "B$(C(F(1))):195b SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ J6HC1605 ;SW39* ^P1J:355:4150 cD hQ15:C(Q)0:R mQ14FSw rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 15> L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195T W$JK$:W$:135:d W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0 IMER11E8 wA(16384)5 xA127SEEDTIMER:122; yT zZ(SEED):16368,0v {:"ONE MOMENT, PLEASE, ";NA$| | 180 NM30 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:2L1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #21"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONEr:::s" PRESS ANY KEY." uT!! ! ! ! ! !!!!!!!!!""" " " *:/" PLEASE REMOVE THE DISK FROM THE DRIVE AND TURN OFF THE COMPUTER, MONITOR AND PRINTER. ADVANCE THE PAPER IN THE PRINTER, TEAR OFF THE PAPER AT THE PER- FORATION AND TAKE IT TO YOUR INSTRUCTOR.SEE YOU NEXT TIME!"41::#6"*****ER CORRECT = "CR+50" NUMBER WRONG = "IRc5:" STUDENT SCORE = ";(CR100L);"%"::"IF YOU WANT TO DO THE QUIZ AGAIN, PRESS 'Y' THEN . IF NOT, PRESS 'N' THEN .;W$DW$"Y"ĬIW$"N"800S570 ETE THE FOLLOWING: ":7:JK$" "A$(AO(P)):195:Z:"THE CORRECT ANSWER IS: ":y:JK$" "B$(AO(P)):195::"PRESS ." IRIR1 R$CC1C10ī535P::::!LCRIR:L0L1&" NUMB::"YOU ARE CORRECT - NONE OF THESE!"::"TO COMPLETE THE FOLLOWING: "::JK$" "A$(AO(P)):195:::"THE CORRECT ANSWER IS: "::JK$" "B$(AO(P)):195::"PRESS ."CRCR1:525::"YOU ARE WRONG!":"TO COMPLJK$" E) NONE OF THESE":195% G$5 G$"A"G1E G$"B"G2U G$"C"G3e G$"D"G4u G$"E"G5 G1475 G5FS475 C(F(G))AO(P)515 G5506 :"YOU ARE CORRECT!THE ANSWER IS: ";G$:"PRESS .":510J K,E: 0 ::JK$" "A$(AO(P)):1956 V JK$" A) "B$(C(F(1))):195d SW40ĺ JK$" B) "B$(C(F(2))):195 SW40ĺ JK$" C) "B$(C(F(3))):195 SW40ĺ JK$" D) "B$(C(F(4))):195 FS1475 SW40ĺ 6HC1605 ;SW39, ^P1J:355:4152 cF hQ15:C(Q)0:T mQ14FSy rC(Q)(J(J))1:C(Q)AO(P)370 wKQ1O1:C(K)C(Q)370 |K Q:C(5FS)AO(P) E15FS F(E)((5FS)(5FS))1 KE101:F(K)F(E)395 215@ L$(JK$,T):W$L$:220:JK$" "(JK$,((JK$))T):195V W$JK$:W$:135:f W$::135: J1NM:A$(J),B$(J):A$(J)"END"235 J JJ1 I1J AO(I)(J(J))1 NP(AO(I))1275 NP(AO(I))1:I " 'FS0TIMER11E8 wA(16384)6 xA127SEEDTIMER:122< yU zZ(SEED):16368,0w {:"ONE MOMENT, PLEASE, ";NA$} | 180 NM110 AO(NM),A$(NM),B$(NM),NP(NM) 225 (JK$)SW215 TSWO1:(JK$,T,1)" "210 T:1011,100C0&:(" WHAT IS YOUR NAME?"C*NA$I2v7" ANALYTICAL CHEMISTRY FOR TECHNICIANS"A" QUIZ #25"Z:::n" SPECIAL INSTRUCTIONS:"q:" NONE"r:::s" PRESS ANY KEY." u" """""""""    L/MOLE CM AND THE CONCENTRATION IS 0.0000923 M?",0.0234J END,ACT2QU32LHAT IS THE PATHLENGTH IN CM WHEN THE % TRANSMITTANCE IS 36.0, THE MOLAR ABSORPTIVITY IS 4.29 E 4 L/MOLE CM, AND THE CONCENTRATION IS 0.0000821 M?",0.1258 "WHAT IS THE PATHLENGTH IN CM WHEN THE TRANSMITTANCE IS 0.692, THE MOLAR ABSORPTIVITY IS 7.39 E 4, THE PATHLENGTH IS 1.00 CM, AND THE MOLAR ABSORPTIVITY IS 5.28 E 4 L/MOLE CM?",0.00000787~ "WHAT IS THE PATHLENGTH IN CM WHEN THE ABSORBANCE IS 0.482, THE MOLAR ABSORPTIVITY IS 5.65 E 4 L/MOLE CM, AND THE CONCENTRATION IS 0.0000465 M?",0.183 "W IS 5.63 E 3 L/MOLE CM?",0.0000285j "WHAT IS THE MOLAR ABSORPTIVITY WHEN THE TRANSMITTANCE IS 0.369, THE PATHLENGTH IS 1.00 CM AND THE CONCENTRATION IS 0.0000419 M?",1.02 E 4Zt "WHAT IS THE CONCENTRATION IN MOLARITY WHEN THE TRANSMITTANCE IS 0.384OLAR ABSORPTIVITY WHEN THE % TRANSMITTANCE IS 56.2, THE PATHLENGTH IS 1.00, AND THE CONCENTRATION IS 0.0000748 M?",3.35 E 3"` "WHAT IS THE CONCENTRATION IN MOLARITY WHEN THE % TRANSMITTANCE IS 69.1, THE PATHLENGTH IS 1.00 CM, AND THE MOLAR ABSORPTIVITY