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PRINTER";:A$:A$"2"L2:110 dA$"1"90 nD$;"OPEN";FILE$:D$;"READ";FILE$:A$:D$;"CLOSE";FILE$ x180 D J& S SOFTWARE{ TO READ PHYSICS FILES 30 HOME : VTAB 10: HTAB 10: PRIN "STUDENT RECORDS": PRINT : P ::10:10:"STUDENT RECORDS"::(A$(200),B$(200),C(200),Z$(200)2300<D$(4):D$;"NOMON C,I,O":(37):8680 F   ` 0@|`~`0`0 @`0 L``@0@`0>Dp@@@# H4>8 `A@@  `0 0@ @@x 8@ ``80@@@Da0  B02@ dP 0@X0 @@N `@  @8  Dx1`D`b`a`@@B|q0 @p` 0``80@@ @0 @ :` @L4 D1@ @h@p4@A0 @0@D@`p@`@`0 @``@@0@@   0@`b0x@ @Fd 8pPA (@@@ @`@8a@X` @@|~|~@p 0 @F@@00AD` B X  @0 @ @ 0 `0p``@@0 @`@L0@` 0 @@ 0p @>``0@@ ` @@0 0```80@ 0@@X`1`@@ 0`` x|`~ ``@0@x@ 0@  `   P           ֪ժՁ @@@֪ժՁίЙժժՆ@@֪ժՂ՚ժ Ĉ՚ժ@Ղ֪ժι̅D`G"|pp#ЙժժՆ՚ժ8@|>ժժՂ 0 8@ԪժժժՆ ժժՂ՚ժ Ĉ՚ժ0 ՂԪժ"D"@ @" ժժՆժ՚$@ժժՂ  0&تժ~`̙?șժժՆ΃ժժՆ՚ժ @|՚ժ 0ت̃D"p@ @@"  ժժՆ@պՆ΃xժժՆ G@@պՆpl ժժՆժժՆ՚ժ |՚ժ@@|` "@xC"@@8 @`@ @ @@ @ @ @ @@@ @@@  "@@@DP "D!@D " @@@ @@"  @BDP @ @ @"D  $ @B"@D P  D @@@ @@@D( @@"(@@ @@D @@x @@ @~ @ @@ @@  @@D|q 2D>p!@D `"|@ @@x >@@   p#DD|q @ @ @"x  $ p#D"@x `P>  D @@ @@>Dx. @<@C @xD @@ @ @@ @ @ @ @@~ @@ 0` @@@p8D *D "aA@D "D B @@@H @@x0  "DDD @ @@@*@0  "Db@@ P" 0 D @@ @@"D1@)0@ (@D` @H8 @@@ @ @p@ @ @ @ @@@ @ @@@ @@ @@D8a &8 p!@8p`8h B @@P @p@@  `!D8a~ @@*8`  `!"C8 `PxpPA @@@ @@@8pPA)`@ D@  @PD @@ @ @@ @ @x @`@ @0 @`@0D @@ D "  @ @A @@` @@ D  D@ @@6  @ P @`@ @`@) @ "@`D @@ @ @p@ @ @ @ @@ @ @@ 8x >@p@p8 @ "` @>@ @p@@ @p@`>8 0F @ @ @p@" 0`@0P @@ @@ p @@8 @p@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @  @ @                     0L@` g RgƖ8PgPQhQghe Ӣi  g y  gh^_8^eP^ȱ^ eQ^^_Ll8ePeQ` "BF:F8 F5 ::"WHICH IS YOUR CHOICE";:A$N (A$)0(A$)B120f A((A$)):A$A$(A)s :ABĀ{ 18 C(A$):(40(12C))2::A$" IS LOADING.": D$(4):D$"RUN ";A$  A$(1)"ELECTRON STRUCTURE" .A$(2)"QUIT" 8J & S SOFTWARE"4 PA114:(A$,A,1);:B140:B,As Z:A$"PRESENTS":(15):A18:(A$,A,1);:B140:B:A:13 d(12):"CHEMISTRY MENU" nA11000:A x::7 :15:"MENU":: 1000 F18 7:F". "A$(F) A$(F)"QUIT J AND S SOFTWARER COPYRIGHT 1979 ILLEGAL TO COPY WITHOUT PERMISSION.Z:(A12:"XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX":A2A119:"X";39);"X":A<A12:"XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX":A F37,4::(12):A$"     WILL BE USED IN THIS PROGRAM."X:v 22:"PRESS ANY KEY TO SEE THE CHART.";:CC$::PIC1~: :10:10::"CHART IS LOADING":: DD$"BLOAD PIC.CHART":: 16304,0: 23:7:"PRESS ANY KEY TO CONTINUE";:CC$:: 16303,0: PRINCIPAL ENERGY LEVELS, NUMBER AND TYPE OF SUBLEVELS,"9X "NUMBER OF ORBITALS IN A SUBLEVEL, TOTAL NUMBER OF ORBITALS IN AN ENERGY LEVEL AND THE MAXIMUM NUMBER OF ELECTRONS IN EACH ENERGY LEVEL.":b :"STUDY THESE RELATIONSHIPS CAREFULLY AS THEY12:10::"LOADING ELECTRON STRUCTURE":B8 DD$"BLOAD PIC.CHEM"P8 16304,08 22:11:"ELECTRON STRUCTURE":13:"COPYRIGHT 1981"8 A15000::16303,0::8& 6245080 99N :5:"THE FOLLOWING CHART ILLUSTRATES THE RELATIONSHIP BETWEEN CE"^7t "IT HAS 15 ELECTRONS AND THEREFORE 15 PROTONS GIVING IT AN ATOMIC NUMBER OF 15."g7~ 3107 DD$;"NOMON C,I,O":(37):868:DD$;"OPEN ELE"7 DD$;"APPEND ELE"7 DD$;"WRITE ELE"7 A$:A1$:Z$:P:DD$;"CLOSE ELE"7 7 ::)8 5906` R4ĺ"SORRY, WRONG AGAIN. SINCE THE ELEMENT HAS IN ITS LAST ENERGY LEVEL 2 - 3S ELECTRONS AND 3 - 3P ELECTRONS IT HAS A TOTAL OF FIVE VALENCE ELECTRONS.":3107j "WHOOPS, STILL WRONG. THE ELEMENT IS":"PHOSPHOROUS. IT CAN BE IDENTIFIED SIN5R2999:R$"PHOSPHORUS":6205"WRONG ANSWER, "A$". AN ELEMENT":"CAN BE IDENTIFIED BY ITS VALENCE ELECTRONS OR BY ITS TOTAL NUMBER OF ELECTRONS."5 R4ĺ"THE VALENCE ELECTRONS ARE THE NUMBER OF ELECTRONS IN THE LAST ENERGY LEVEL."6 IS MADE OF ORBITALS. THE 3RD ENERGY LEVEL OF THIS ELEMENT HAS 5 VALENCE ELECTRONS. IT CAN HOLD A TOTAL OF 8 ELECTRONS."4z3104R4R25:"HOW MANY VALENCE ELECTRONS DOES THIS ELEMENT HAVE.":6204"WHAT IS THE NAME OF THE ELEMENT."ONG, "A$". THE ELEMENT":"HAS "R2" ELECTRONS IN ITS ";:D$"."3fR1R3ĺ" RECALL THAT A P SUBLEVEL CONTAINS 3 P ORBITALS HAVING THE EXACT SAME SHAPE BUTORIENTED IN DIFFERENT DIRECTIONS.":3104p" AN ENERGY LEVEL IS MADE OF SUBLEVELS WHICH IN TURNST COLUMN GIVES THE ELECTRON CONFIGURATION OF THE S ORBITAL WHILE THE THREE RIGHT COLUMNS GIVE THE"24"ELECTRON CONFIGURATION OF THE P ORBITALSAN X IN A CIRCLE MEANS THE ORBITAL IS FILLED WITH TWO ELECTRONS."2H5902RR32400=3\" STILL WRD$"3RD ENERGY LEVEL":R25:1R3D$"2P SUBLEVEL":R261 "GIVEN THE ELECTRON CONFIGURATION SHOWN IN THE DIAGRAM, HOW MANY ELECTRONS DOES THIS ELEMENT HAVE IN ITS":D$"."16201 R32300f2*"WRONG ANSWER, "A$". HERE'S A":"CLUE. THE LEFT MO"IT APPEARS THAT YOU NEED TO STUDY MORE.":"AFTER STUDYING COME BACK AND TRY THIS":"EXERCISE AGAIN. SEE YOU SOON!"030000A18:N(A)0:A:G000R(5((1)))1:Z(R)120000Z(R)10R322000R1D$"3P SUBLEVEL":R231R2TN9Z$(T3):"YOU HAVE ANSWERED "T3" QUESTIONS. THERE":"WERE "N9T" QUESTIONS THAT YOU DID NOT":"ANSWER. TRY TO COMPLETE THIS LESSON":"LATER.":3000/XP861900/b"EXCELLENT GRADE!! YOU KNOW THIS":"MATERIAL VERY WELL "A$"."/lP701920u0vOTASSIUM",9,19,1,"FOURTH","4P","SELENIUM",6,6,"CARBON",20,"IVA","2P",6,4,1.0 "ARGON",9,18,0,"FIRST","2P","BORON",3,3,"STRONTIUM",20,"IIA","5S",38,2,6.:34,0.DP((C100)(CW)).N:12:A$", YOUR GRADE WAS "P" PERCENT."::/ST3CW:Z$"ALL":- "ALUMINUM",6,13,1,"THIRD","3P","PHOSPHORUS",5,5,"CALCIUM",61,"IIA","3P",20,2,1-"OXYGEN",3,8,2,"SECOND","3D","TITANIUM",4,2,"CHLORINE",50,"VIIA","3P",17,7,4- "MAGNESIUM" ,6,12,0,"FIFTH","2P","FLUORINE",7,7,"SODIUM",21,"IA","2S",11,1,2J.&"P, "NITROGEN",2,7,3,"SECOND","3P","SILICON",4,4,"ARSENIC",30,"VA","4P",33,5,3, "SULFUR",7,16,2,"THIRD","3D","VANADIUM",5,2,"BROMINE",61,"VIIA","3P",35,7,4,"FLUORINE",4,9,1,"FIRST","4P","GALLIUM",3,3,"SULFUR",40,"VIA","3P",16,6,5SDS WITH":"GROUP IIA WHILE THE P SUBLEVEL ENDS":"WITH GROUP VIIIA. TRY AGAIN."X+590o+Z$"S":F11Z$""+"STILL WRONG, "A$". "C$:"HAS "F1" ELECTRON"Z$" IN ITS LAST":"SUBLEVEL. NOTE THE GROUP IT BELONGS":"TO IN THE PERIODIC TABLE."+310W"WRONG, "A$". THE ORDER IS 1S2S2P3S3P4S":"3D4P AND SO ON. THE "E2$" FILLS AFTER":"THE "E1$"."i*310*"HOW MANY ELECTRONS ARE IN THE LAST":"SUBLEVEL OF "C$"."*R2F1:620O+"WRONG ANSWER. THE PERIODIC TABLE":"IS THE CLUE. THE S SUBLEVEL END.")rR2999:R$E2$:620)|"WRONG! LOOK AT THE PERIODIC TABLE AND":"FIGURE OUT THE ORDER OF FILLING. GROUPS":"IA AND IIA FILL S ORBITALS WHILE IIIA":"TO VIIIA FILL P ORBITALS. THE")"TRANSITION ELEMENTS FILL D ORBITALS.":"TRY AGAIN.":590`*EMENT HAS "R2" ELECTRONS (K=2,":"L=8, M="R") AND "R2" PROTONS. ITS"g(T"ATOMIC NUMBER IS "R2".":310(^ES$"1S2S2P3S3P4S3D4P5S":E1$(ES$,((2R))1,2):E2$(ES$,((2R))3,2))h"WHAT SUBLEVEL GETS ELECTRONS NEXT AFTER":" THE "E1$" SUBLEVEL IS FILLENERGY LEVEL IS":"FILLED WITH 8 ELECTRONS. THE 3RD ENERGY":"LEVEL CAN HOLD A TOTAL OF 18 ELECTRONS."w'6"TRY AGAIN."'@590D(J"WRONG AGAIN. THE TOTAL NUMBER OF":"ELECTRONS MUST EQUAL THE NUMBER OF":"PROTONS IN A NEUTRAL ATOM. THEREFORE":"THIS EL"GIVE THE ATOMIC NUMBER OF THE ELEMENT":"THAT HAS ITS INNER ENERGY LEVELS FILLED":"AND HAS "R" ELECTRONS IN THE 3RD ENERGY":"LEVEL."&"R210R:620e',"WRONG, "A$"! THE FIRST OR K":"ENERGY LEVEL IS FILLED WITH 2 ELECTRONS":"WHILE THE 2ND OR L ELEVEL":"FILLS, ONE ELECTRON GOES INTO EACH":"ORBITAL BEFORE THEY PAIR UP. TRY AGAIN."`%590w%Z$"S":F11Z$""%"SORRY, WRONG AGAIN! "C$" HAS":F1" ELECTRON"Z$" IN ITS LAST SUBLEVEL. THIS":"RESULTS IN "F" HALF FILLED ORBITAL"Z$"."%310& DOES":C$" HAVE." $R2F:620$"WRONG ANSWER. "C$" HAS AN":"ATOMIC NUMBER OF "E". THUS IT HAS "E:"ELECTRONS. USE YOUR PERIODIC TABLE TO":"LOCATE "C$". DETERMINE THE"W%"NUMBER OF ELECTRONS IT HAS IN ITS LAST":"SUBLEVEL. RECALL THAT WHEN A SUBE. TRY AGAIN."#590#"STILL WRONG, "A$". THE ELEMENT":"HAS A TOTAL OF "M" ELECTRONS, WITH "K1:"IN THE LAST ENERGY LEVEL. THE ELEMENT":"WITH "K1" VALENCE ELECTRONS IS IN"#"GROUP "H$" AND IS "G$"."#310$"HOW MANY HALF FILLED ORBITALS"QUESTION. ONE WAY IS TO COUNT THE TOTAL":"NUMBER OF ELECTRONS. THIS EQUALS THE"#"ATOMIC NUMBER. THE OTHER WAY IS TO NOTE":"THE LAST SUBLEVEL FILLED AND IF THE":"ELEMENT IS IN THE GROUND STATE FIND":"THAT SUBLEVEL AND GROUP ON THE":"PERIODIC TABLEVEL BEGAN, IT MUST HAVE "K:"ELECTRONS IN THE "L$" SUBLEVEL."G!n310!x"WHAT IS THE NAME OF THE ELEMENT THAT":"HAS THE ABOVE ELECTRON STRUCTURE."!R2999:R$G$:620Q""WRONG! THIS INFORMATION SHOULD HELP.":"THERE ARE TWO WAYS TO SOLVE THIS":":590 ZK11ĺ"NOTE THAT THIS SUBLEVEL MUST BE FILLED,":"SINCE THE LAST ELECTRONS ARE IN A LATER":"SUBLEVEL. THE "L$" ORBITALS HOLD A TOTAL":"OF "K" ELECTRONS.":310>!d"WRONG, "G$" IS IN GROUP "H$".":"SINCE IT IS ELEMENT # "K" SINCE THAT":"SUBL<R2(K10):K1K(R210):KR2:620F"NO, "A$"! USING THE PERIODIC TABLE":"FIND WHERE THAT SUBLEVEL IS LOCATED.":"COUNT THE NUMBER ELEMENT IT IS SINCE":"THE SUBLEVEL STARTED. IF IT IS IN THAT":"SUBLEVEL THAT NUMBER IS YOUR ANSWER." P"TRY AGAIN.(E$,1)"D"ĺ" D ELECTRONS ARE NOT IN THE LAST":"ENERGY LEVEL AND DON'T COUNT AS VALENCE":"ELECTRONS. IN THIS CASE ONLY THE OUTER":(((E$,1)))1"S ELECTRONS COUNT."(3102"HOW MANY TOTAL ELECTRONS DOES "G$:"HAVE IN ITS "L$" ORBITALS."#:"ELECTRONS IN THE LAST ENERGY LEVEL.":"THE BEST WAY OF DETERMINING THIS IS BY":"THE PERIODIC TABLE. GROUP A ELEMENTS" "HAVE THE SAME NUMBER OF ELECTRONS AS":"THE GROUP NUMBER. TRY AGAIN.":590"STILL WRONG. "F$" HAS "J:"VALENCE ELECTRONS.(E$,1))1:"HAS TWO ELECTRONS IN IT. THIS ELEMENT"i"MUST BE # "H" IN THE 4TH PERIOD. IT":"IS "F$"."r310"HOW MANY VALENCE ELECTRONS DOES":F$" HAVE."R2J:620y"INCORRECT, "A$". THE NUMBER":"OF VALENCE ELECTRONS ARE THE NUMBER OF""STILL WRONG! THIS ELEMENT MUST HAVE A":"TOTAL OF "H" ELECTRONS IN ENERGY LEVEL":"# "(E$,1)". THEREFORE IT MUST BE "F$".":3102"STILL WRONG! REMEMBER THE D SUBLEVEL":"FILLS AFTER THE S AND IT IS ONE ENERGY":"LEVEL BACK. THUS ENERGY LEVEL # "(STION. IA AND IIA ELEMENTS HAVE":"THEIR LAST ELECTRONS GOING INTO AN S":"SUBLEVEL, WHILE GROUPS IIIA TO VIIIA""HAVE THEIRS GOING INTO A P SUBLEVEL.":"TRANSITION ELEMENTS ARE FILLING THE D":"SUBLEVEL. TRY AGAIN."590(E$,1)"D"1230 ORBITALS ARE FILLED."~310"WHAT IS THE NAME OF THE ELEMENT WHOSE":"LAST ELECTRON WAS THE "D$" ELECTRON":"TO GO INTO THE "E$" SUBLEVEL."R2999:R$F$:620p"WHOOPS, WRONG ANSWER, "A$"!":"YOUR PERIODIC TABLE IS NECESSARY FOR":"THIS QUE ORBITAL CAN HOLD ONLY TWO":"ELECTRONS. TRY AGAIN."=`590WjZ$"ARE":F1Z$"IS"t"WRONG AGAIN! "C$" HAS A TOTAL":"OF "E" ELECTRONS. "F" OF THESE ELECTRONS":Z$" UNPAIRED. THIS MEANS THAT "EF:"ELECTRONS MUST BE IN FILLED ORBITALS.":"THUS "D":"ANSWER OF "R2"."8310qB"HOW MANY COMPLETELY FILLED ORBITALS":"DOES "C$" HAVE IN THE GROUND":"STATE."LR2D:6204V"WRONG, "A$". RECALL THAT WHEN":"A SUBLEVEL FILLS ONE ELECTRON MUST GO":"INTO EACH ORBITAL BEFORE THEY CAN PAIR":"UP. AN":"ANSWER. N REPRESENTS THE NUMBER OF THE":"ENERGY LEVEL OR SHELL.""IN USING THE ABOVE FORMULA, FIRST":"SQUARE N AND THEN MULTIPLY BY 2. TRY":"AGAIN."$590."STILL WRONG! N IS "R1". SQUARING N AND":"THEN MULTIPLYING THIS BY 2 GIVES THE"2 10 6 2"1"1S 2S 2P 3S 3P 4S 3D 4P 5S":"THEORETICALLY, WHAT IS THE MAXIMUM":"NUMBER OF ELECTRONS THE NUMBER "R1:"ENERGY LEVEL CAN HOLD."R22(R1)(R1):620E"SORRY, WRONG ANSWER, "A$".":"USE THE FORMULA 2N SQUARED TO FIND THE3D 4P": " 2 2 6 2 4"8"1S 2S 2P 3S 3P":R" 2 2 6 2 6 2"m"1S 2S 2P 3S 3P 4S":" 2 2 6 2 5""1S 2S 2P 3S 3P":" 2 2 6 1""1S 2S 2P 3S":" 2 2 2""1S 2S 2P": " 2 2 6 2 6 RRECT, "A$"!!":850>4"SUPER ANSWER "A$"!!!":850Y>"RIGHT!!!!!!":850yH"FANTASTIC "A$"!"R::\" 2 2 6 2 6 2 10 3"f"1S 2S 2P 3S 3P 4S 3D 4P":p" 2 2 6 2 6 2 10 5" z"1S 2S 2P 3S 3P 4S W1W11:WW1TQ1040,1110,1180,1280,1350,1420,1500,1580,1660,1720,2080,2080:::8:R3(7((1)))1:R780,790,800,810,820,830,840 "VERY GOOD, "A$"!!":850"GREAT !!!":850 "EXCELLENT!!!!!!":850*"CO4ė:16304,0:23:"PRESS ANY KEY TO RETURN TO QUESTION";:CC$:::16303,0:600o(AR2)(A.01).02720x770A10710CC1:W10310A11ī740Q1070,1130,1210,1300,1370,1450,1530,1610,1680,1740,2130,2130A11310C0ğ:15:9:"PICTURE IS LOADING"::DD$"BLOAD";PIC$:16304,0:23:"PRESS ANY KEY TO RETURN TO QUESTION";:CC$::PIC1::16303,0:600A99PIC1Q10ė:16304,0:23:"PRESS ANY KEY TO RETURN TO QUESTION";:CC$:::16303,0:600RA99PIC1TB$,3)(R$,3)680-B$"99"Q10A99:667HB$"99"T4A99:667Q720\AA$""kCV(37)1AA$:A(AA$):AA$""Ģ(CV):"WHAT IS THE ANSWER, "A$;:664(AA$)0(AA$)64Ė5::"TYPE IN A NUMBER ONLY"::600Q10A99PI00 N:A11,X"WHAT IS THE ANSWER, "A$;5b630elMAX10Ė5:"TYPE 99 TO SEE ELECTRON CHART"nQ10MAX12Ğ:"TYPE 99 TO SEE ELECTRON CONFIGURATION":q"--------------------------------------":CV(37):34,CVvR2999660B$::(((1)))1:N(R1)1480) N(R1)1:RAR15 A1R1c C$,D,E,F,D$,E$,F$,H,J,G$,K,H$,L$,M,K1,F1j Ap ~ Q6580 &32,6: 0R1860,880,900,920,940,960,980,1000 :32,0D:Q1020,1090,1160,1260,1330,1400,1480,1560,1630,1700,2000,20Q11Q12W10 W11420. T3MAX12= T4PIC0_ Q(MAX((1)))1:M(Q)1400} Q11Q12PIC$"PIC.ORB" TT1:W10:M(Q)1:T3MAX12: A10 R(6((1)))2:RRR430 RRR GG1 G7İ1930 N(RA)1 R1(8R ESC TO STOP";@ LQ10ĺ" OR TYPE * TO SEE PICTURE AGAIN.";K OCC$:U T34,0d ^T12370x cQ11Q12W10 hW111850 r(CC$)271850 w(CC$)42Q10ė:16304,0:22:"PRESS ANY KEY TO CONTINUE";:CC$:::16303,0:330 | ENCE ELECTRONS." d:" 34,0E "WHAT IS YOUR FIRST NAME?";A$U A$(A$,12){ ":"WHAT IS YOUR LAST NAME? ";A1$ $N912 '3150 ,380 6W12330 @:A$", YOU BETTER STUDY THIS":"TYPE OF PROBLEM." J:"HIT ANY KEY TO CONTINUE O::11:"ELECTRON STRUCTURE"::::MAX10 F"THIS EXERCISE RELATES AN ATOMS ELECTRON":"STRUCTURE TO ITS LOCATION ON THE":"PERIODIC TABLE. BY THE TIME YOU ARE":"FINISHED WITH THIS EXERCISE YOU":"WILL BE A WHIZ WITH ORBITALS," P"SUBLEVELS, AND VAL2A J AND S SOFTWARE - HIRES VERSION ELECTRON STRUCTURE 140 REID AVENUE PORT WASHINGTON, N.Y. 11050 COPYRIGHT 1981 ILLEGAL TO COPY WITHOUT PERMISSION.#(4)"BRUN MOVE":16384:DD$(4)(M(13):3050) 234,0::4                 z#      ҠŠ ΠŠ4 Ϡ Š îԠ" î͠"î "