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L7877777777 776i 7 7867 7`77 777777`x =(`(8`5775I7`B` 76`77`>J><;VU<)?<`8'x0|<&HhHh 8 8 8 8V&` aI꽌ɪVɭ&Y:&<&Y:&;: 꽌ɪ\8`&&꽌ɪɖ'*&%&,E'зЮ꽌ɪФ`+*xS&x'8*3Ixix&& 8 9: :' 9: :& :x)*++`FG8`0($ p,&"ųųೳŪŪųųij  !"#$%&'()*+,-./0123456789:;<=>?8  1 '" *"( (9"1 ( ,.(0# 2  /#0/#0 *?'#07#000'#07#0:"4<*55**5*%5)1)1)1)'#0/#0*5*75**5*:5/#0/#0'#07#0:::*::'#07#0"):$(%"%:$(%"%$$2%4%$$2%4%$(2()!)E(!8b $!H(+ "@H !D)"E` @ $ C ` DQ &J80^݌Hh < <݌ < < h < < < <`HJ>݌h Hh݌`葠葠ȔЖȔЖȠHIHHHHhHH݌hHhHh݌H6 (G FG HZXj 80x D9$xxH` >( Z>h Z>L=.xxH >hh@(LH>9L>HH/Hh/ H?-З( 8(& 8$8 H` *8HNx`* >x$50x*$50xL9JJJJ`HHjf5 >h $50x`HA>VD;;P >(ED Z> ?$0x8x D9- 8DD# H8`?E Vˆʎ55L $ 5 55555 &a*5`*5` "L&5_*b*JL%u**Lz%`** $  Q(lXJ̥KlV $  Q(lV eօ3L e3L &%R*L &%Q*L d' "L4% N'e*)n*5 5 &`@-e*f*f* 5 "L# "5f*`L %.* *t*Q*L$ %L&*L` "O**P**u** d' "L% N'e*)n*o*o*n* &8ɍ` ^&f\*555L& ^&NR* & "R*ΩL&)\*Z* ʽ LH*v 3h`0h8` " ['L & N'С55 &5`*A*@` +5L^6L65`  \* ?*0 '\* '  Q( ^&\*lZl^?*c*q)H c*h`f*5h*5j*555@O*AP*`u*@`@5&`Q*R*`E 'Ls' ' ' @DAE@u*`8` %@ @A@`@`**@*A`M5 ) "L&`8@AW*c*@8@-@HAȑ@hHȑ@ȑ@hHȑ@Ȋ@c*h8&ȑ@Hȑ@Ah@L'Hȑ@ȑ@* htphso`hMhL`9V*8U*897T*6S*67`INILOASAVRUCHAIDELETLOCUNLOCCLOSREAEXEWRITPOSITIOOPEAPPENRENAMCATALOMONOMOPRINMAXFILEFINBSAVBLOABRUVERIF!pppp p p p p`" t""#x"p0p@p@@@p@!y q q p@  LANGUAGE NOT AVAILABLRANGE ERROWRITE PROTECTEEND OF DATFILE NOT FOUNVOLUME MISMATCI/O ERRODISK FULFILE LOCKESYNTAX ERRONO BUFFERS AVAILABLFILE TYPE MISMATCPROGRAM TOO LARGNOT DIRECT COMMANč$3>L[dmx- (   ӠӠ734@~3!+,W,o,*--,,9,-.-~3~3,,,,~3~3,,,,~3_*3 j.5 *H*H`Lc3 (+L3 +55555 1^3_* )3J Q*L_3Ls3443 D23455545554 70 / 7 :/354545455454555535L^/5-5I5555 55` / 4/ 2-5! / 08555454 70L3 (+50+5B5C3 2 70L35 *H*H`Lg3L{3505 *H*H` 3 ,5L3 3 1 ,H 1hBL, 0 BH [1 1h`Lo3 35 ,L3 3 1B , 1L,H 0hB@ 55 [1L133 (+34) 34 70L3 3L3 (+ 055L- (+34L{33454445 70 ^/* / 3B0 HȱBh -355 -8 /L38 25` +5 /3 /. /. 3 E7D B. /. /. 0]34S0J4 4) 3 4D4E B. 4  /. 02L3 Ν3 3`HD٤33DEEhiHLG.h ` /5B5-` /5B-` + X05I33383 33DH /4 E03744Ȍ7 X040 7 J7L35B5C`,5p` / R0-55`50` K/ R0-55`575755` 4/ K/ /( 55L/BȱBL/58` D2BH5BH :/ 75Bȭ5Bhh55 R0B5m55ȱB5m55` /LR0557755`*7*75LR0 E0(33 48`433 R0` E033LR0*7*7`777 555I7575757577** 7757`7 L35555f /55555555 ^/`855 i /B58` 41L 15ȱB5 /5555 /5`3 D23ȑB55B5 / 7 55`5555555555 5555`555`55BC55`5555`L3 /5B5C355 0Q340"B4 3` 02۰Ϭ33B438`3i#`3ЗLw35!50>5555`53 /3m3 3 3733i35 3583 /35ЉLw35`H /5h 25L/~43 533`55555555J5m55m5jn5n5n5ۭ55m5555m55m55`"L? 585H ~.(3` # d ֠z# u*`ύ΁̍΍ԍ΍̍čٍ΍΍ٍٍ̍Ս Ƞԍٍ֍׍ ٍˍōҍ΍Ӎō΍ō΍ōڍÍȍӍō ΍ҍōҍȍЍ̍ˍҍˍҍz #     îײ"î׳" נ"Ϡ" Š"Ġ"îӠ" ӠӠ1Ӯנ îױ"̍Ӎɠԍύ΍΍΍Ӎčҍ |@@JH@  @<  @ @D @ @8zq @|?~@ @@ E@ @ @ @ @@rx!@D @@@ |@ |@ @ @@ @ @ @ @@ |@( `@@~@ @ @ @zp@@zy @ @ |@| @ @x@ @ @@@@ @x @ @ @@!@ @ @@HHG @ |@@ @ @@@@`!@ @ @ aC@"!|CD @ @|@H @ @<@ @x @@@@"@ @| @z!@@Bx @D  @@H @ @@@ @|?@@@@bC |@ @ !@@ @|  @@H @ @@@ |@@@@@@ @ @  !@          @ ! @0@2`@@ @bp@y yqq@@`@@`@xq" @@ @B@@@@`@ "0@y !py@@@~?@ "@ X! @@@ @@@@ "~|xpH (!I@@@ @p@@@(*@(y!)q@~?@@ @@@@06@B ! @`@@ @2@ @`@ p"@b          b@p| ~@@xD@@@I@BHI`$ !d$``@``b@@ @@F`@@H@BHH $ !$$@ 0 AA`@`@``Cp@ @@ @HOHG d'dG#Dp@x` @C@@ 0pBAX@ @@ 2@@y@F@~@`bL@ @@ b@HOGH@ d'A#d` @L`@@`2F@ |@ @?@ BA@H@ BH $`!$ 0 p@xX @@ C@ @ p`@ C@L@ BH  & !$@p @@ pCA@ @@F @JGBH  e#!$E           ԠĮԠPUSH`ANY`KEY`TO`RETURNנ͠Ǡ٠ΠΠӠΠԠ ӠΠ̠ǠͯӯӠΠŠϠ`ԠŠΠԠԠŠŠΠ٩Ŭ٠ԠԠĠנΠԠӠ͠Ӡ&ӠԠԠĠŠΠԠ¬ΠנԠŠŠϠ٩`ĠנƠ͠ ԠנΠŠӠϠԠƠԠŠҠ͠Ơ̠ө    D:P:DD$;"CLOSE NEW"n $n ::Ln 12:10::"LOADING NEWTONS LAWS":rn DD$"BLOAD PIC.PHYSICS":16304,0n 22:14);"NEWTONS LAWS ":13:"COPYRIGHT 1981"n DD$"BLOAD EQUATIONS.NEW,A$800"n A16000::16303,0::n! 62450n& ND LAW TO FIND ACCELERATION":640m8 "WRONG AGAIN. THE NET FORCE IS ":P2N210" NEWTONS, AND THE ACCELERATION":"IS "R2" M/S/S.":310m D$(4):DD$;"NOMON C,I,O":(37):868:DD$;"OPEN NEW"m DD$;"APPEND NEW"m DD$;"WRITE NEW"n A$:A1$:Z$N THE MASS.":"WHAT IS THE ACCELERATION OF THE MASS?"jl "(UP VECTORS ARE + AND DOWN VECTORS ARE-)":670!m "WRONG "A$".":"YOU MUST FIND THE NET FORCE:":" NET FORCE = SUPPORTING FORCE + WEIGHT":"REMEMBER WEIGHT IS A NEGATIVE FORCE.":"THEN USE SECOCE OF FRICTION IS "R2" NEWTONS.":310vkP2(((R)8)21.5)10:N2(R12)1:P125P2:R2((P2N210)N2100.5)1005l "THE PICTURE SHOWS A "N2" KILOGRAM MASS":"SUSPENDED FROM A SPRING SCALE. THE":"SCALE INDICATES THE UPWARD FORCE BEING":"APPLIED O"NET FORCE = APPLIED FORCE + FRICTION":"(FRICTION IS ASSUMED TO BE NEGATIVE)":"THEREFORE:":"FRICTION = NET FORCE-APPLIED FORCE."j"USE THE SECOND LAW TO FIND THE NET FORCE":640%k"WRONG AGAIN "A$".":"THE NET FORCE IS "P2N2" NEWTONS.":"THE FOR((P2N2)(R11)100.5)100:P2N2ī2200:iY.12200i"THE PICTURE SHOWS A "R11" KILOGRAM MASS":"WITH AN APPLIED FORCE AS SHOWN ON THE":"SCALE. THE ACCELERATION OF THE MASS IS":Y" M/S/S.":"WHAT IS THE FORCE OF FRICTION?":670j"WRONG.":FORCE IS FOUND BY":"SUBTRACTING THE FRICTIONAL FORCE FROM":"THE APPLIED FORCE.":640hf"WRONG AGAIN. THE NET FORCE IS":P2N2" NEWTONS. USING THE SECOND LAW":"THE ACCELERATION IS "R2" M/S/S.":310+iN2(R1)2:P2.5((R)10):P114010P2:R2N2:YWHICH GIVES A FRICTIONAL FORCE OF":N2" NEWTONS. THE APPLIED FORCE":"IS SHOWN ON THE SCALE. THE MASS IS":R11" KILOGRAMS"g "WHAT IS THE ACCELERATION OF THE MASS?"g 670Vh>"WRONG "A$".":"FRICTION ALWAYS OPPOSES THE APPLIED":"FORCE, SO THE NET THAT YOU HAVE NOT DONE":"COMPLETE THIS UNIT ANOTHER DAY."Ef3000^fA18:N(A)0:A:G1ofEB0:N(T1)1uffN2(R1)2:P2.5((R)10):P114010P2:R2((P2N2)(R11)100.5)100:P2N2ī2050{g"THE PICTURE SHOWS A MASS ON A SURFACE":"!! YOU KNOW THIS":"MATERIAL VERY WELL ."8eP702000e"IT APPEARS THAT YOU NEED TO STUDY MORE.":"AFTER STUDYING COME BACK AND TRY THIS":"EXERCISE AGAIN. SEE YOU SOON!"e2000;f::"YOU COMPLETED "T3" QUESTIONS. THERE WERE":N9T" QUESTIONS "A$"!!!":1920/dl"GREAT!!!!!!":1920Vdv"EXCELLENT ANSWER, "A$"."`d::pd34,0:N913dP((C100)(CW))d:12:A$", YOUR GRADE WAS "P" PERCENT."::dZ$"ALL":TN9Z$(T3):1993dP861980)e"EXCELLENT GRADEc .25,2c .5,4c 1,5*c 2,104c 4,1>c 5,5Ic& 10,4Tc0 20,2c::::8:R1860,1860,1870,1880,1890,1900cD"VERY GOOD, "A$"!!":1920cN"EXCELLENT!!!!!!":1920cX"CORRECT, "A$"!!":1920db"SUPER100:P2N2ī1720b670b"WRONG "A$".":"FIRST FIND THE NET FORCE, THEN USE":"EQUATION 2 TO FIND THE ACCELERATION.":"BE CAREFUL OF THE SIGN.":640b"WRONG AGAIN.":"THE NET FORCE IS "P2N2" NEWTONS AND":"THE ACCELERATION IS "R2" M/S/S.":310 ONLESS PLANE WITH TWO FORCES,":"A AND B APPLIED.":"IF THE MASS IS "R1" KILOGRAMS AND THE":"THE FORCES ARE AS SHOWN, WHAT IS THE"a"ACCELERATION OF THE MASS?"bN2.5((R)10)2:P2.5((R)10)2:P119510P2:N18510N2:R2((P2N2)R1100.5) PARTLY CANCEL OUT LEAVING A NET FORCE.":640`"WRONG AGAIN "A$".":"THE FORCE TO THE RIGHT(+) IS":P2" NEWTONS, AND THE FORCE TO THE":"LEFT(-) IS "N2" NEWTONS":"THE ANSWER IS "R2" NEWTONS.":310a"THE PICTURE SHOWS MASS M RESTING ON A":"FRICTI22.5((R)6)2:P2N2((R)6)2:P119510P2:N18510N2:R2P2N2:P2N2ī1660[_670.`"A WRONG RESPONSE. AN OBJECT WILL NOT MOVE IF THE FORCES ARE EQUAL BUT OPPOSITE. THATS WHY THE SIGNS ARE DIFFERENT IN THE PICTURE. THE FORCES IS "N2" NEWTONS":"THE ANSWER IS +"R2" NEWTONS.":310^r"THE PICTURE SHOWS MASS M RESTING ON A":"FRICTIONLESS PLANE WITH TWO FORCES,":"A AND B APPLIED.":"IF THE MASS IS "R1" KILOGRAMS AND THE":"THE FORCES ARE AS SHOWN, WHAT IS THE NET FORCE?"R_|N AT REST UNLESS A FORCE IS APPLIED TO IT TO MAKE IT MOVE."]"NOTE THAT THERE ARE NOT EQUAL FORCES ON EACH SIDE. ALSO BE CAREFUL OF THE SIGN.":6406^6"WRONG AGAIN "A$".":"THE FORCE TO THE RIGHT(+) IS":P2" NEWTONS, AND THE FORCE TO THE":"LEFT(-)AMS AND THE":"THE FORCES ARE AS SHOWN, WHAT IS THE NET FORCE?"\P22.5((R)6)2:N2P2((R)6)2:P119510P2:N18510N2:R2P2N2:P2N2ī1530\670=]"SORRY, WRONG ANSWER, "A$".":"NEWTON'S FIRST LAW STATES THAT AN OBJECTAT REST WILL REMAINTRY AGAIN.":640{["WRONG AGAIN "A$".":"SINCE THE FORCES ARE EQUAL BUT OPPOSITE,";:"THE NET FORCE IS 0 NEWTONS.":310?\"THE PICTURE SHOWS MASS M RESTING ON A":"FRICTIONLESS PLANE WITH TWO FORCES,":"A AND B APPLIED.":"IF THE MASS IS "R1" KILOGR":"THE FORCES ARE AS SHOWN, WHAT IS THE NET FORCE?"iZR20:N18510(R12.5):P119510(R12.5):670["WRONG ANSWER, "A$". FIRST":"OF ALL READ NEWTONS LAWS VERY CAREFULLY.HERE'S A CLUE THAT SHOULD HELP. TAKE ACCOUNT OF THE SIGN OF THE FORCES. ASSES, THE THIRD LAW TELLS US THAT THE":"FORCES WILL BE EQUAL BUT OPPOSITE.":"THE ANSWER IS "R2" NEWTONS.":3104Z"THE PICTURE SHOWS MASS M RESTING ON A":"FRICTIONLESS PLANE WITH TWO FORCES,":"A AND B APPLIED.":"IF THE MASS IS "R" KILOGRAMS AND THES THE CAR EXERT ON THE TRUCK?"3XnR210R1R:670Xx"WRONG ANSWER, "A$". YOU NEED":"TO BECOME MORE FAMILIAR WITH NEWTON'S LAWS, ESPECIALLY THE THIRD LAW. READ THEM CAREFULLY AND THEN TRY AGAIN.":640qY"WRONG AGAIN. DESPITE THE DIFFERENT":"MS NEGATIVE BECAUSE IT IS A FORCE";:"DIRECTED DOWNWARD.":310Wd"A TRUCK WITH A MASS OF "R4852000" KILOGRAMS":"COLLIDES WITH A CAR OF "R11001000" KILOGRAMS.":"IF THE TRUCK APPLIES A FORCE OF":R1R10" NEWTONS ON THE CAR, HOW MUCH FORCE"Xi"DOEON THEN ON THE EARTH. THE GREATER THE GRAVITATIONAL"zV"ATTRACTION THE MORE THE OBJECT WILL WEIGH. TRY AGAIN.":640V("WRONG AGAIN "A$".":"THE ANSWER IS "R2" KILOGRAMS."=W2"EQUATION 4 CAN BE SOLVED FOR MASS:":" M = W/(-10)":"WEIGHT ICTED DOWNWARD.":310oUXR16R:"AN OBJECT HAS A WEIGHT OF "X" NEWTONS.":"WHAT IS ITS MASS?":R2X10:6704V"INCORRECT "A$". THE WEIGHT OF":"AN OBJECT DEPENDS UPON THE GRAVITATIONALFORCE. FOR EXAMPLE THE ABOVE OBJECT WILL WEIGH LESS ON THE MO. YOU SHOULD HAVE USED THE FORMULA, WEIGHT = MASS TIMES THE ACCELERATION DUE TO GRAVITY (W=MG). THE ANSWER IS "R2" NEWTONS."U"THE SOLUTION IS: W = "X" X (-10)":"THE WEIGHT IS NEGATIVE INDICATING":"THAT THE WEIGHT IS A FORCE THAT IS":"DIREWHAT IS THE OBJECTS WEIGHT?":R2X10:670S"WHOOPS A WRONG ANSWER "A$".":"RECALL THAT WEIGHT IS THE FORCE DUE TO GRAVITY. IN SOLVING THIS PROBLEM THE SIGN (+ OR -) FOR ACCELERATION DUE TO GRAVITY IS IMPORTANT. TRY AGAIN.":640T"STILL WRONGOPORTIONAL. TRY AGAIN.":640VR~"STILL WRONG "A$".":"THE ANSWER IS "R2" KILOGRAMS."R"NEWTON'S SECOND LAW CAN BE GIVEN AS:":" M=F/A":"THE SOLUTION IS: M = "X"/"Y:310*SXR1R5:"THE MASS OF AN OBJECT IS FOUND TO BE":X" KILOGRAMS.":"G IT AN ACCELERATION";:"OF "Y" M/S/S.":"WHAT IS THE MASS OF THE OBJECT?":R2R15:670Rj"INCORRECT ANSWER. NOTE THAT IF THE OBJECT WERE TO GET HEAVIER IT WOULD TAKE MORE FORCE TO ACCELERATE IT. THUS FORCE AND ACCELERATION ARE DIRECTLY PRCCELERATION ARE DIRECTLY PROPORTIONAL. THE ANSWER IS "R2" M/S/S."PL"NEWTON'S SECOND LAW CAN BE STATED AS:":" A=F/M":"THE SOLUTION IS: A = "X"/"R15:310WQVXR15(R1.5):YR1.5:"A NET FORCE OF "X" NEWTONS IS APPLIED":"TO AN OBJECT , GIVINR4:670O."SORRY, WRONG ANSWER "A$".":"WITHOUT LOOKING AT THE FORMULAS SEE IF YOU CAN FIGURE OUT THE RELATIONSHIPS. FOR EXAMPLE: WHAT WILL AN INCREASE IN ACCELERATION DO TO THE FORCE? TRY AGAIN.":640APB"WRONG AGAIN "A$". FORCE AND":"AAIN. THE ANSWER IS "R2" NEWTONS"N"NEWTON'S SECOND LAW CAN BE STATED AS:":" F = MA":"THE SOLUTION IS:F = "R15"X"R4:310 OXR15(R4):"THE NET FORCE ON A "R15" KILOGRAM":"OBJECT IS "X" NEWTONS.":"WHAT IS THE ACCELERATION OF THE OBJECT?":R2HAT IS THE NET FORCE ON THE OBJECT?":R2R15(R4):670M"WRONG ANSWER, "A$". EXAMINE":"NEWTON'S LAWS TO SEE WHICH ONE APPLIES. NOTE THE UNITS IN THE RATE. YOU ARE GIVEN MASS AND ACCELERATION AND NEED TO FIND FORCE. TRY AGAIN.":640 N"WRONG AG020,1090,1150,1220,1320,1420,1500,1590,1690,1750,2150,2280,2360,2460RLA11310dL W1W11:WW1L*Q1000,1070,1130,1200,1300,1400,1480,1540,1670,1740,2110,2250,2330,24307M"A MASS OF "R15" KILOGRAMS ACCELERATES":"AT A RATE OF "R4" M/S/S.":"WPIC0ľCC$::PIC1:CV:16303,0:958:650KZ91A99PIC1Ĺ16304,0:23:"PRESS ANY KEY TO RETURN TO QUESTION";:CC$::CV:16303,0:958:650K((AR2)(A.001)).05770K1850KA10760KCC1:W10K310KA11ī790DL Q1X1,88X1,86X,84:XP1:X,84X1,86X1,88X,90X1,88X1,86X,84J(Q11Q12)PIC0XP1:X,69X2,73X2,77X,81X2,77X2,73X,69JQ13PIC0XP1:137,X2143,X2:135,X1145,X1:133,X147,X:135,X1145,X1:137,X2143,X2,KZ91A9928?I(AA$)0(AA$)64Ė5::"TYPE IN A NUMBER ONLY"::650IZ91A99PIC0ğ:15:9:"PICTURE IS LOADING"::DD$"BLOAD";PIC$:16304,0:23:"PRESS ANY KEY TO RETURN TO QUESTION";I3CJ(Q7Q8Q9Q10)PIC0XN1:X,84X1,86X1,88X,907):34,CV:CVCV1HT3T31.HR2999710MHB$::(B$,3)(R$,3)730}HB$"999"Ĺ16299,0:CC$:16300,0:CV:650HB$"99"A99HZ91A99718H770HAA$""HAA$:A(AA$)::A999Ĺ16299,0:CC$:16300,0:CV:650IA997270,1380,1460,1520,1650,1700,2050,2200,23006G:A11fG"WHAT IS THE ANSWER, "A$;:CV1(37):868nGA0wG680GZ91Ė5::"TYPE 99 TO SEE PICTURE":G4::" TYPE 999 TO SEE EQUATIONS":H"--------------------------------------":CV(3:M(Q)1:PIC0:ZZ0:EB0 FZ90.FQ6Z91:"NUMERICAL ANSWERS WILL BE CONSIDERED":"CORRECT IF THEY ARE WITHIN + OR - 5%":"OF THE PROGRAMMED ANSWER.":BF"QUESTIONS ANSWERED INCORRECTLY WILL BE"BP"REPEATED, BUT WITH DIFFERENT VARIABLES."BZ::DD0:EE0:OY35 CE":16384:DD$(4)A#M(14)(A&3050HA(34,0::10:"NEWTONS LAWS"PA2:B<"DO YOU KNOW HOW TO APPLY NEWTON'S THREE":"LAWS OF MOTION TO SOLVE PROBLEMS":"INVOLVING FORCE, ACCELERATION, MASS":"AND WEIGHT? THIS EXERCISE WILL HELP YOU":"GAIN SKI.@@ J AND S SOFTWARE NEWTONS LAWS@ 140 REID AVENUE PORT WASHINGTON, N.Y. 11050@ WRITTEN BY G.J. KUNKEL REVISED 9/27/81@ COPYRIGHT 1981 ILLEGAL TO COPY WITHOUT PERMISSIONA(4)"BRUN MOV                P*U*U*U*UP*U*U*U*U@P*U*A*P*U@ԀЪP*U*A*P*UP*U*U*U*U0@P*U* P*U`@@ @pԊP*U*U*U*UP*U*U*U*U@P*U*A P*U@ԀЪP*U*A*P*U@P*U*U*U*U`@@`@xqP*U* P*U @@ @ԊP*U*U*U*UP*U*U*U*U@ĀP*U*A P*U@рP*U*A*P*U@P*U*U*U*U@`@ P*U*A*P*U0@P*U*U*U*UP*U*U*U*U@ĀP*U*A P*U@рP*U*A*P*U@P*U*U*U*U~?@ P*U*A*P*U@&P*U*U*U*UP*U*U*U*U@P*U*U*U*UԀԂЪP*U*A P*U@@ @ĀՂĀP*U*A*P*U@P*U*U*U*U@@ ՀԊP*U*A*P*U~|cpP*U*U*U*U@P*U*U*U*UԀԂЪP*U*A P*U@@ @pĀՂĀP*U*A*P*U@P*U*U*U*U@@(ՀԊP*U*U*U*U@AP*U*U*U*U@P*U*U*U*UP*U*A P*U~?@@ @ԀĀԂЊP*U*A*P*U@P*U*U*U*U@@0P*U*U*U*U@ՀԂP*U*U*U*U@P*U*U*U*UP*U* P*U`@@ @ԀĀԂЊP*U*A*P*U@ P*U*U*U*U@`@ pP*U*U*U*U@2ՀԂQ"""!!! ! ! ! ! !!!!!!!!!          :"STUDENT RECORDS HAVE BEEN DELETED!", "J ,216,0:D$;"DELETE";FILE${ 6:"NO STUDENTS HAVE TAKEN THIS PROGRAM YET" @DFILE$D6:"NO STUDENTS HAVE TAKEN THIS PROGRAM YET"D@D-" A1D1< A$(A)" ";B$(A);27);Z$(A);35);C(A);"%"I L2270 A18(A18)ĺ:"PRESS ANY KEY TO CONTINUE ";:Z$: A 0:34,0& :"DO YOU WISH TO DELETE STUDENT RECORDS FOR THIS PROGRAM";:A$:(A$,1)"Y"ĺ(4)"DELETE";FILE$:$;"OPEN";FILE$# D$;"READ";FILE$+ D1G A$(D),B$(D),Z$(D),C(D)V DD1:160a 216,0y D$;"CLOSE";FILE$: L2Ċ1 10);NAME$::34,3 "NAME";24)"QUESTIONS";35)"GRADE" 24)"COMPLETED" "----";24)"---------";35)"----"WHAT IS THE NAME OF THE PHYSICS ":"PROGRAM";L PNAME$:FILE$(NAME$,3) Z:"ARE YOU PRINTING ON THE 1. SCREEN":(27):"2. PRINTER";:A$:A$"2"L2:110 dA$"1"90 nD$;"OPEN";FILE$:D$;"READ";FILE$:A$:D$;"CLOSE";FILE$ x180 D J& S SOFTWARE{ TO READ PHYSICS FILES 30 HOME : VTAB 10: HTAB 10: PRIN "STUDENT RECORDS": PRINT : P ::10:10:"STUDENT RECORDS"::(A$(200),B$(200),C(200),Z$(200)2300<D$(4):D$;"NOMON C,I,O":(37):8680 F""""""0L@` g RgƖ8PgPQhQghe Ӣi  g y  gh^_8^eP^ȱ^ eQ^^_Ll8ePeQ`L" "  .A$(3)"QUIT" 8ABF:F8 F4 ::"WHICH IS YOUR CHOICE";:A$M (A$)0(A$)B120e A((A$)):A$A$(A)r :ABĀz 22 C(A$):(40(12C))2::A$" IS LOADING.": D$(4):D$"RUN ";A$  A$(1)"NEWTONS LAWS" .A$(2)"QUIT" 8N""J & S SOFTWARE"5 PA114:(A$,A,1);:B140:B,At Z:A$"PRESENTS":(15):A18:(A$,A,1);:B140:B:A:13 d(14):"PHYSICS MENU" nA11000:A x::7 :15:"MENU":: 1000 F18 7:F". "A$(F) A$(F)"QUIT" J AND S SOFTWARES COPYRIGHT 1981 ILLEGAL TO COPY WITHOUT PERMISSION.[:(A12:"XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX":A2A119:"X";39);"X":A<A12:"XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX":A F37,4::(12):A$""" " "