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If not look at ts "C(R4)" M.":" That of the second wave is "C(R5)" M.":" The sum is "R2" meters.":310o]XR10:R2XY]" If a wave has a velocity of "X" M/sec":"and a frequency of "Y" cycles/sec,":"then what is its wavelength?":670^" Sorry wrong ing":"for the result of the superposition of":"the two waves at position "R" meters.":" This is the sum of the displacements":"of the two waves at that point.":640]]" Wrong again "A$".":" The displacement of the first wave at";:R" meters iR2)[n" Two waves, as shown on the graph,":"are moving in the same medium.":" What will be the displacement from":"the undisturbed level of the resulting":"wave at horizontal position "R" meters?":670\x" Wrong answer. The question is ask T = 1/"X". Solving for T gives the":"answer of "R2" seconds.":310ZdA49R12:P4R110:W4R2:SY60:SX12:A57R3:P5R12:W54(R12):AMA5:PHP5:WLW5:R5E(R):AMA4:PHP4:WLW4:R4E(R):R2C(R4)C(R5)ZhR20TL.9993338:1390[jTL(1.5 for one complete vibration or pulse. Period is the inverse of frequency. Look at the equations if you need more help.":640GZ(" Your answer is still wrong. Equation two is time(T) = 1/frequency(F). Substituting in the formula gives Since frequency = "X"/"WL",":"frequency will equal "R2" cycles/sec.":310SXR2YX" If a wave has a frequency of "X:"cycles/sec., what is the period of that":"wave?":670Y" A wrong answer, "A$".":"Period is defined as the time it takessolve this problem.":640W" Wrong again. From the graph you should have noted that the wavelength is "WL" meters. Using the formula":"frequency = velocity / wavelength you should have obtained the answer of ":R2" cycles/sec."JX" find the wavelength of the wave. Recall that the wavelength is the distance between any two successive particles that have the same phase."W" Then knowing the relationship between velocity, wavelength, and frequency you can ed.":310EUAM10R12:PHR110:WLR:YR112:XWLY:R2Y:SY60:SX12U" If the wave in the graph has a speed":"of "X" meters/sec., then what is its":"frequency?":670V" Wrong answer, "A$".":"Here's some information that will help. Firstwavelength use the formula V= F X W to find the velocity.":640U~"Still wrong, "A$". The wavelength":"is "WL" meters. When this wavelength":"is multiplied by the frequency of "Y:"Hertz (cycles per second) the answer of":R2" meters/sec is obtain the velocity of the wave?":670Sj"Good try, "A$", but you are":"wrong. Here's a clue. First find the wavelength from the graph. Recall that the wavelength is the distance between corresponding parts of adjacent pulses."BTt"After you find the n the graph. This is the value of the crest of the wave. The amplitude determines the power of a wave.":310RVAM10R12:PHR110:WLR:YR112:R2WLY:SY60:SX12S`" The graph shows a wave with a fre-":"quency of "Y" cycles/sec.":" What isps a wrong answer, "A$".":"The amplitude of a wave is the maximum displacement of the vibrating particles from their normal rest position. Try again.":640oRBA$", the correct answer is":R2" meters. This is obtained by noting":"the maximum value ot the":"graph again. Notice that the distance between any two corresponding points of adjacent pulses is "R2" meters.":310PAM9R12:PHR110:WLR:R2AM:SY60:SX12P$" In the graph, what is the amplitude":"of the wave shown?":670Q."Whoostancefrom the crest of one wave to the crest of the next wave or from the trough of one wave to the trough of the next"O"wave. Note that the unit used is the meter.":640}P"Sorry but you are still wrong. The answer is "R2" meters. Look aR2999:R$"REFRACTION"Yn " In the diagram, what wave process is":"being shown?":670o>" Whoops, a wrong answer "A$".":"In the diagram the wave fronts are approaching the edge of a boundary between two different media. Notice thatwhendying come back and try this":"exercise again. See you soon!"Gm3000m::"You have completed "T3" questions. There":"were "N9T" questions that you have not":"answered. Try again.":m3000mA18:N(A)0:A:G1mEB0:N(T1)1mnP((C100)(CW))Dl:12:A$", your grade was "P" percent."::glZ$"ALL":TN9Z$(T3):1993vlP861980l"Excellent grade!! You know this":"material very well ."lP702000=m"It appears that you need to study more.":"After stuection,G,normal!@0  0@0@ BE4060yN8N81:N81ēX4,Y4=yX4,Y4.5(Y4(TEBE)2)RyY4TESL04090gyY4BESL04100yXXX3:YYY3:X3:ER,(TEBE)2A(XS):4110y(YSYY)SLXXLE,TE:4110y(YY)SLXXLE,BEyLE,BE:l":13:"Copyright 1983"~@ @ @ @ B< p@ ~p @?@ p@ ,xbDbZB$~` ? `D x D~~@ "< A `@ "@x< bC B @ @?< r@~ x"D@8 `x% !@ @ `G@ @ @ @ @ @ `G@ @ @ @ <@ @ @ @ @ @ @ @ @ @  !@ @ @ @ $@ @ D@@ @ @$ "B@!@ @ >@ @ @ 0@ @ @ @ 8@ @ @ <@ @ @@ @ @ @ B@ @ <@ @ <@ @ 0@!@ @ \8>0\D<< T<0<>@ @?@ x@ hp@ |Bb?@@p|B~p?@ `|B@BBb@ @~@ `0@ ~@ xx@ >B>R@DV@ r8  @@ "~8p@ WT@ `x@` ~@` p ~ ?`@@ "p"|  |@ "@"| `!D @ z <@B "@?D@~ @ x|@0: ?`8B<8>~BBB~p | <> @ >@`@ "x A ~@ "@@ "BB @ ժժ~@ B@B `D@ C@@(U@@gy@   @@   @G@(U0 @@   @p@(U@gsy@(U @@@   @<|@(Uȁ@@(U   @gsy@   @@(U@@(U@@@g~@   @x@(U@@(U @ @gy@   @*U*@P*@"U*@   @"Q(@P*00@(@   @ |~@ @px~@ժժժժժp@@ ~ժժժժժ@?@ @`@ ժժ~@ `@ ~@?@ pB~@@ @ @gsy@  "D `@@   @|y@ @ @ <0`@@gsy@B   @@ @ @@@P@#@@@   0>@|@ @ @@~A?00`J@ B@gy@   @(@FA@@ `@ @   @"U(@ @@*Q(@  8d@@*U*pa`` @ @@"U(@`` @*U*@   @ U*@@  @ B@ (@`  `@D@*U*@ @ @"Q(@  , @*U*@   @*T(@ @ ȈɈ@*U**U*U*U*U `@@"Q(@B   @*U*@ @ @*U*@p X`>@"U*@  @D@*T*@ @ @*U*@a H B@"U(@   @@C``@`@g@  @gsy@ 0`@@x@  8`@X0 0``@gy@ 0 0@@   @G@` 0 B@@ ! 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