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ӮʠӠΠu`8     8   m%!!!8! 8!! )8  m$imim$ LɍLɊLɉLI`ɈLH8$K - ,H# ,P,R,Wux {&~) `L%LLiL  $ȱ% $%  ` L *UU*ժ    L Ɍ SI SL$ɕ(ESɍм `Ɉɠ ɍ7)L Li؍ĠӍԍ׍٠̍ō č ԍ̠ҠŠө&cr[H HHHH123./-0 C012/ۭ3hhhh h m-iLm.L`L S ,9 c{  J L1 I1``Q`   mL"` ` & & 8e e ȱȱȱee -.)-#.)-%LL Н],I9` S ,轓 S , 'ؠ'?`f  C  C  C  C`8 I1``Q`888 L17/8DL CL8  C CL C CL`````],@ @ @ @ @ @ @ @ @ @ @H Mh`-)%!H)'Lq'h)I `HHHFf & Chhh`F S ,/* + '  + '- !!!!!"""""""#######$$$$$$$%%%%%%%&&&&&&&''''''' @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @      !!`(,LФ$(H,0 @))(N+ h`**$8n.۩) ,4L W,(,.0ɁϬ**,c0 ې II ,(Pɛ,.0@L,(?ɛ&,!$ 5ؠ0 <ڤ$LԤ$,.0ɕ +`( {8n4N+ >2ɧ >)ɧ-ɝ$LC <ڈL  2N3۩ <کEE I LE ֦CL$8f< 7N+E$<CC CE?AC8A 7L.$>I  8LӥE? ע L ֩? } 2 ٦EH,ۥ3ɾɪ$@,ɢE@@$@0 )ߝh` 7L֤EEɍHh`C$3P톸Eɍ$3p C L ED C` NL$= Бӗ Y ԗ0 : YL E  $L ԖF>JL őɠɰɺ8``ɯɍ`C葌ɮ NC`  CЅ$`CDԗӗ 0N Б +0I ԑ m ӗ [) ԗI]IƍID$3p CL ő(ɬ őɮ ɬ ɢ `ʨ`hh )N E$` L  ɠiɺ>F=E$3pDм5 I $`$3pE L3ɾ`Ŗ ED 3 u3N,pd O<=EM 0 <<=18<=L E )<)<L> D Ԗ ) H hߦ$! Ԗ-parallel"::"circuit with 4 resistors has two equal"::"valued series resistors and two unequal"::"valued parallel resistors. The value of";:: "each series resistor is 201}{0; the values";::"of the parallel resistors are 51}{0 and"::"1037240<REWRITE:,X(15),Y(18):" ":WRITE,X(1),Y(20):"RT^ for this circuit is 3.14 1}{0, which"::"we found by adding the resistor values."1000:p*PAGE18z7000:,X(1),Y(1)"Try this example. A series7:197,96197,12071,12071,92|Đ,X(9),Y(10):"-":::"+":,X(19),68:"21}{0":,X(30),Y(11):"RV^=1.141}{0"ΐ"3";:7:1:0:264,77:1130,51:16:1202,70:"0"x,X(15),Y(18):"Press RETURN.";:FROMOTHERYES:1000:RESPNSE$M$;:VSPACE,0:BOXIT,3:VSPACE,1:". Since resistance in a series":"circuit is additive, we add the values":"for RT^.":VSPACE,03:70,8470,56135,56:154,56196,56196,77:196,95196,12070,12070,927:71,8471,56136,56:155,56197,56197,7t step.";:FROMOTHERYES:1000:RESPNSE$M$362207D*PAGE17]7000:,X(1),Y(1)VSPACE,1:"Here's the redrawn circuit. Note that":"the original series resistor and the new";:"equivalent resistor are arranged in"RESET:" series "PACE,1:,0,148:"Now that we know equivalent resistance,":"we redraw the circuit by using ";:RESET:" one ":VSPACE,0:BOXIT,3:VSPACE,1r"resistor to stand for all the parallel":"resistors.":VSPACE,01|,X(6),Y(24):"Press RETURN for the nexnce."FDBCK$(3)"Sorry. You were to find the/equivalent resistance of only the/parallel branches.":FDBCK$(NMTCH)"Try 1.14 1}{0."AXPS0:AYPS130:XPS7:YPS144:,X(9),130:"1}{0"3000REWRITE:,0,130:" ":WRITEhVSES0:ALTYES:STPNOKANSWER$(1)"1.14":ANSWER$(2)"14":ANSWER$(3)"3.14"FDBCK$(1)"Yes. The 3 resistors in parallel/have an equivalent resistance/of 1.14 1}{0.":FDBCK$(2)"Sorry. Resistors in parallel are/not added to get the equivalent/resistaection. In this case, you first add":"the two series resistors in the outer":"branch and then compute the equivalent":"resistance of the parallel branches."Ҍ"Using the reciprocal method, what is RV^?":VSPACE,0܌QUESTIN1:LNGTH4:LEAVITNO:TRI35,5:CLR%/32,0:33,40:34,17:35,24:CLR%M32,0:33,40:34,0:35,24Ì,0,8:"3";:0:1:0:1179,115:"0":3:180,120207,120:REWRITE:,189,112:" ":,220,88:"8":WRITE:VSPACE,1Ȍ,0,8:" Next, compute RV^ for the parallel":"sesistor.":"The other consists of two series":"resistors that are in parallel with two":"other parallel branches.",X(6),Y(24):"Press RETURN for the next step.";:FROMOTHERYES:1000:RESPNSE$M$35240*PAGE16 32,0:33,40:34,0:0":,189,112:"31}{0":,77,68:"21}{0""3";:7:1:0:229,72:165,51:1179,115:16:1111,70:1167,70:1251,700:6133,56:6133,120:"0"t,X(1),Y(18):"This circuit has two sections. One is":"made up of the single series r6:90,56246,56246,77:246,95246,120204,120:185,12036,12036,87134,56134,72:106,77106,72162,72162,77:106,95106,104162,104162,95:134,104134,120,,21,80:"-":,21,96:"+":,80,88:"41}{0":,136,88:"21}{0":,220,88:"51}{69)256:IY(770)Y(1)1:IL0:109 FRFRNO:WRITE:n $RE$M$įREWRITE:,X(7),Y(24):27);:WRITE:x 81000~ 6 H1%:X1%(X1%(MOD(X1%)MOD(H1%))):X2%(X2%(MOD(X2%)MOD(H1%))):L11D1%S1%:X1%,Y1%X2%,Y1%X2%,Y2%X1%,Y2%X1%,YA1$(A1$,1,(A1$)1):(8);" F A1$""A2$""A$(A2$,1):80 (A2$)(A1$)A$(A2$,(A1$)1,1):A1$A1$A$:A$;: BEEP: NX9000:  REWRITE FRĹSWD%,72:,X(8),Y(24):"Press RETURN to continue.";" IX(768)(7(A2$)(A1$):C9A2$A1$(A2$,(A2$)(A1$))? dC9A2$A1$J nA$;: xRE$A1$:" ":L1(RE$)11:(RE$,1)" "RE$(RE$,1,L11): }(RE$,1,1)" "RE$(RE$,2):125 RE$""RL(RE$):NXYES::WRITE: BEEP:BEEP::20 A1$"" You are given the value of R2^/and you determined the value of V2^/from the previous question. Consider/Ohm's Law and try again."$iFDBCK$(3)"Sorry. Try 1.""%iQUESTIN3:NMTCH2:TRIES0:LNGTH2:ALTYES:STPYES:LEAVITNO:AXPS0:AYPS16:XPS7:YP16000:1000:#xi*PAGE7=#iX1%133:Y1%8:Z7$"I2":17000#iANSWER$(1)"1":ANSWER$(2)"2":FDBCK$(1)"Right. You know that V2^ equals 12/volts and R2^ equals 12 ohms. Applying/Ohm's Law I = V1!0R = 12V1!0121}{0 = 1A."$iFDBCK$(2)"Sorry.NMTCH3:FD$(2)FD$(3)-"eJUDGECRRECT26100L"e3000:JUDGECRRECT26090#eREWRITE:,141,105:"  ":WRITE:X1%141:Y1%106:Z7$"12":17000:REWRITE:,141,106:" ":WRITE:,142,103:"1":,147,103:"2":,145,111:"V":RD%9:X1%148:Y1%103:H1%7:d/remember the rule: the applied/voltage equals the sum of the voltages/in a circuit loop."|!eFDBCK$(3)"Sorry. Try 12."!eQUESTIN2:NMTCH2:TRIES0:LNGTH2:ALTYES:STPYES:LEAVITNO:AXPS0:AYPS16:XPS7:YPS28:,35,16:"V""e3000:JUDGECRRECT%8:Z7$"V2":17000 eANSWER$(1)"12":ANSWER$(2)"24":FDBCK$(1)"Right. Since you know the value of VA^/and V1^, you find V2^ by simply/subtracting V1^ = 12V from VA^ = 24V/to get V2^ = 12V."\!eFDBCK$(2)"Sorry. Look at the circuit again anRRECT25240*b3000:JUDGECRRECT25230bREWRITE:,39,154:"  ":WRITE:X1%38:Y1%155:Z7$"12":17000:REWRITE:,38,155:" ":WRITE:,39,152:"1":,44,152:"2":,42,160:"V":RD%9:X1%45:Y1%152:H1%7:16000:1000:e*PAGE6 eX1%133:Y1. Since both/values are given you used Ohm's Law to/compute V1^ = 2A x 61}{0 = 12V."fbQUESTIN1:NMTCH2:TRIES0:LNGTH2:ALTYES:STPYES:LEAVITNO:AXPS0:AYPS16:XPS7:YPS28:,35,16:"V"zb3000:JUDGECRRECTNMTCH3:FD$(2)FD$(3) bJUDGEC1%133:Y1%8:Z7$"V1":17000RbFDBCK$(2)"Sorry. Remember Ohm's Law./Look at the values given/and press RETURN.":FDBCK$(3)"Sorry. Try 12."Z\bANSWER$(1)"12":ANSWER$(2)"24":FDBCK$(1)"Right. The current I1^=2A flows/through resistor R1^=61}{0Y1%103:H1%7:160004bRD%9:X1%127:Y1%134:H1%7:16000:RD%9:X1%148:Y1%103:H1%7:16000:RD%15:X1%38:Y1%116:H1%7:16000:RD%15:X1%98:Y1%168:H1%7:16000>b1000:35,9:CLR%Hb35,24:,X(2),Y(1):"Type the value of and press RETURN.":X04,145:"V4":,28,180:"R1^=61}{0":,76,104:"R2^=121}{0" b,235,108:"R3":,235,148:"R4^=41}{0":,141,105:"V2"*bRD%9:X1%45:Y1%152:H1%7:16000:RD%9:X1%175:Y1%168:H1%7:16000:RD%9:X1%211:Y1%143:H1%7:16000:RD%9:X1%211:148,94:148,113148,118127,118:232,88211,88211,94:211,113211,118232,118:232,128211,128211,134:211,153211,158232,158Bb,28,113:"VA^= 24V":,39,154:"V1":,88,166:"I1^= 2A":,120,136:"I2":,168,170:"I3":,204,105:"V3":,294:232,112232,134:232,152232,168184,168:166,168113,168:83,16855,168:36,16815,16815,124b127,80127,94:127,112127,125:127,144127,168:15,9639,9639,101:39,13239,14015,140:29,16829,15235,152:54,15262,15262,168 b127,88148,88210,158231,158a"3";:7:1:0:28,109:130,163:6126,80:6126,168:6231,88:6231,118:6231,128:6231,158:6126,88:6126,118:628,168:661,168:614,96:614,140a16:1132,87:1237,87:1237,127:"0"ba7:15,11615,80232,80232,,94:126,112126,125:126,144126,168:14,9638,9638,101:38,13238,14014,140:28,16828,15234,152:53,15261,15261,168a126,88147,88147,94:147,113147,118126,118:231,88210,88210,94:210,113210,118231,118:231,128210,128210,134:210,153the sum of the/series resistors, you found/that RT^ = 43.31}{0."!FDBCK$(2)"Sorry. Since R is additive/in a series circuit, add 1both0/values for the series/resistors to RV^. Try again."A"FDBCK$(3)"Sorry. Use P1!0S Method to/find RV^; 1}{0. Find RT^, type the answer and"::"press RETURN."b QUESTIN2:LNGTH4:LEAVITNO:ALTYES ANSWER$(1)"43.3":ANSWER$(2)"23.3"C!FDBCK$(1)"Correct. The combined/resistance of the parallel/resistors is 3.31}{0; by adding/this to 401}{0, correct answer is 6 amps./You should have added I2^ + I3^ + I4^."bAXPSX(1):AYPSY(17):XPSX(2):YPS155:STPYES:J1NMTCHINCRRECTb,X(8),Y(17):"A"b3000:(JUDGECRRECT)(FENMTCH)ıb25260e*PAGE6eCLRWIND,1,1,277,35e3NGTH4:LEAVEITNO:ALTYES<zbANSWER$(1)"6":ANSWER$(2)"16"rbFDBCK$(1)"Right. You added I2^ + I3^ + I4^."bFDBCK$(2)"Sorry. You shouldn't have added I1/and I5^, since these are series/resistors. Try again."DbFDBCK$(NMTCH)"Sorry. The 65,93<b0:6154,56:6224,56:6224,128:6154,128:"0" bRD%15:X1%128:Y1%55:H1%7:16000:RD%15:X1%155:Y1%77:H1%7:16000:RD%15:X1%225:Y1%77:H1%7:16000:RD%15:X1%260:Y1%77:H1%7:16000:RD%15:X1%203:Y1%127:H1%7:16000pbQUESTIN1:L9,76:"I4^= 2A":,193,124:"I5^= ?"a,64,88:"VA":,81,47:"R1":,161,112:"R2":,231,112:"R3":,264,112:"R4":,175,140:"R5":,42,80:"-":,42,96:"+"a"3";:7:1:0:172,51:1158,123:250,73:16:1160,93:1230,93:12ECRRECTNMTCH3:FD$(2)FD$(3)70hyJUDGECRRECT31100V0ry3000:JUDGECRRECT310900|yX1%249:Y1%108:Z7$"=81}{0":17000:1000:0@*PAGE200J70001TREWRITE:X11:Y12:,X(15),Y(3):" ":X1%97Y:Y1%14Y:X2%148Y:Y2%25Y:H1%5ou find that/R3^ = 8 ohms."R/6yFDBCK$(2)"Sorry. Use Ohm's Law and try again."q/@yFDBCK$(3)"Sorry. Try 8."/TyQUESTIN7:NMTCH2:TRIES0:LNGTH2:ALTYES:STPYES:LEAVITNO:AXPS0:AYPS16:XPS7:YPS28:REWRITE:,35,16:"1}{0":WRITE0^y3000:JUDG%107:Z7$"8V":17000:RD%9:X1%211:Y1%103:H1%7:16000:1000:M.y*PAGE11p."yX1%133:Y1%8:Z7$"R3":17000/,yANSWER$(1)"8":ANSWER$(2)"4":FDBCK$(1)"Right. You know that V3^ equals/8 volts and I3^ equals 1 amp. Using/Ohm's Law R = V1!0I, yTCH2:TRIES0:LNGTH2:ALTYES:STPYES:LEAVITNO:AXPS0:AYPS16:XPS7:YPS28:REWRITE:,35,16:"V":WRITE-vu3000:JUDGECRRECTNMTCH3:FD$(2)FD$(3)-uJUDGECRRECT30100-u3000:JUDGECRRECT30090@.uREWRITE:,204,105:"  ":WRITE:X1%204:Y12^./Since V4^ = 4V, V3^ = 8V according to/the rate of voltages across parallel/circuits.",NuFDBCK$(2)"Sorry. Study the circuit again. Note/that the sum of V3^ and V4^ are in/parallel with V2^.",XuFDBCK$(3)"Sorry. Try 8."i-luQUESTIN6:NM  ":WRITE:X1%204:Y1%147:Z7$"4V":17000:RD%9:X1%211:Y1%143:H1%7:16000:1000:c+0u*PAGE10+:uX1%133:Y1%8:Z7$"V3":17000^,DuANSWER$(1)"8":ANSWER$(2)"4":FDBCK$(1)"Right. V3^ and V4^ are in series with/one another and in parallel with Vy 4."*qQUESTIN5:NMTCH2:TRIES0:LNGTH2:ALTYES:STPYES:LEAVITNO:AXPS0:AYPS16:XPS7:YPS28:REWRITE:,35,16:"V":WRITE*q3000:JUDGECRRECTNMTCH3:FD$(2)FD$(3)*qJUDGECRRECT29100*q3000:JUDGECRRECT29090V+qREWRITE:,204,145:"DBCK$(1)"Right. You have I3^ = 1A^ going/through R4^ = 41}{0. Using Ohm's Law/V4^ = I3^ x R4^ = 1A x 41}{0 = 4V.")fqFDBCK$(2)"Sorry. You know the values/of R4^ and I3^. Try using Ohm's Law/to compute V4^."*pqFDBCK$(3)"Sorry. TrD$(3)(mJUDGECRRECT28100<(m3000:JUDGECRRECT28090(mREWRITE:,168,170:"  ":WRITE:X1%168:Y1%172:Z7$"1A":17000:RD%9:X1%175:Y1%168:H1%7:16000:1000:(Hq*PAGE9(RqX1%133:Y1%8:Z7$"V4":17000)\qANSWER$(1)"4":ANSWER$(2)"8":Fmmation rule/of currents in parallel circuits and/try again."\'mFDBCK$(3)"Sorry. Try 1."'mQUESTIN4:NMTCH2:TRIES0:LNGTH2:ALTYES:STPYES:LEAVITNO:AXPS0:AYPS16:XPS7:YPS28:REWRITE:,35,16:"A":WRITE(m3000:JUDGECRRECTNMTCH3:FD$(2)FPAGE8(&jmX1%133:Y1%8:Z7$"I3":17000&tmANSWER$(1)"1":ANSWER$(2)"2":FDBCK$(1)"Right. You know that I1^ = 2A/and I2^ = 1A, that leaves I3^ = 1A/going through the branch with the/R4^ and R3^ resistors."='~mFDBCK$(2)"Sorry. Remember the suS28:REWRITE:,35,16:"A":WRITEQ%i3000:JUDGECRRECTNMTCH3:FD$(2)FD$(3)i%iJUDGECRRECT27100%i3000:JUDGECRRECT27090%iREWRITE:,120,136:"  ":WRITE:X1%120:Y1%138:Z7$"1A":17000:RD%9:X1%127:Y1%134:H1%7:16000:1000:&`m*e closed loop and add/only the voltages in that loop./Try again."a*uFDBCK$(4)"Sorry. Try 12."*uAXPSX(2):AYPSY(17):XPSX(2):YPSY(19):TRIES0:NMTCH3*u,X(9),Y(17):"V"*u3000:JUDGECRRECTNMTCH4:30140*u*y*PAGE11+"y7000:^ and R2^ make a closed loop,/so you can add their voltages/to find VA^.")uFDBCK$(2)"Sorry. You shouldn't have added 1all0/of the voltages. Find the closed loop/and add only the voltages in that/loop. Try again."A*uFDBCK$(3)"Sorry. Find thge of this":"circuit? Type your answer and press":"RETURN."u(buX1%0:Y1%0:X2%279:Y2%28:H1%3:S1%1:D1%1:2000(lu-PAGE9.SCHEMATIC.ISSTILL.HERE(vuQUESTIN3:LNGTH4:LEAVEITNO:STPYES(uANSWER$(1)"12":ANSWER$(2)"21"M)uFDBCK$(1)"Right. R1'sX196266:6X,56:6X,56:X:Y56120:6266,Y:6266,Y:Y:X2661961:6X,120:6X,120:X:q'0u*PAGE10':u32,0:33,40:34,0:35,5:CLR%'Du32,0:33,40:34,17:35,24:CLR%'Nu32,0:33,40:34,0:35,24>(Xu,14,10:"What is the applied volta:X28126:6X,56:6X,56:X:D&rY56120:6126,Y:6126,Y:Y:&rX126281:6X,120:6X,120:X:Y120841:628,Y:628,Y:Y:& sX126196:6X,56:6X,56:X:&,112,42:"IT":,239,100:"5A":,211,100:"5A":,141,100:"5A":17,40217,48:217,66217,88:217,104217,12087:22,7222,4064,40:83,40109,40:128,40169,40:188,40246,40246,48:246,66246,88:246,104246,120201,120:175,120174,120:155,12022,12022,80*:148,40148,48:148,66148,88:148,104148,120:218ach loop is":"equal to VA^."43<}VSPACE,0:1000:A3耲*PAGE1337000:,X(7),Y(6):"To review voltage in a series-"::"parallel circuit, type R.":,X(7),Y(12):"Press RETURN to continue the":#4,X(7),Y(14):"lesson.";:FROMOTHERYES:100parate loops and then added":"the voltage across each resistor":"in any one of the loops."32}VSPACE,0:RX14:RY13:15000:,28,112:VSPACE,2:"VA^ equals the sum of any ";:RESET:VSPACE,0:" one ";:BOXIT,3:VSPACE,2:" loop,":"and the voltage of e7000<1}X1%96:Y1%3:X2%152:Y2%21:H1%5:S1%1:D1%2:20001}REWRITE:X16:,X(15),Y(2):" ":Y180:Y:,X(15),Y(2):"SUMMARY":X:WRITE\2(},X(5),Y(6):VSPACE,2:"To find applied voltage, you":"divided the circuit into closed":"se the voltage/of 1one0 loop. Try again."0yFDBCK$(NMTCH)"Sorry. Add R1^ and R2^, since/they make one loop. Their sum/is 4. Type it in now."0yAXPSX(1):AYPSY(20):XPSX(10):YPSY(20)0z,X(8),Y(20):"V"0z3000:0}*PAGE121 },X(2),Y(1)+,y"This circuit also has 3 paths for":"current. Current can flow through R1^":"and R2^, R1^ and R3^, or R1^ and R4^.",Jy3:28,6328,4058,40:77,40266,40266,61:266,79266,10428,10428,71:161,40161,56:126,66126,56196,5sistor is":"2V, find VA^. Type the answer and press";:"RETURN."}.yX1%0:Y1%118:X2%279:Y2%146:H1%3:S1%1:D1%1:2000.yQUESTIN4:LNGTH4:LEAVEITNO:STPNO:NMMF1.yANSWER$(1)"4":ANSWER$(2)"6":ANSWER$(3)"8":ANSWER$(4)"12"S/yFDBCK$(1)"Ye,Y(10):"+":,X(9),Y(7):"R1":,X(16),Y(10):"R2":,X(26),Y(10):"R3":,X(36),Y(8):"R4"-hy"3";:7:1:0:222,56:153,35:16:1132,59:1202,59:1272,54-ry0:6161,40:6161,104:"0"C.y,3,128:"If the voltage across each re6196,669,Ty126,84126,91196,91196,84:161,91161,104,Xy7:29,6329,4057,40:78,40267,40267,61:267,79267,10429,10429,71:162,40162,56:127,66127,56197,56197,66,Zy127,84127,91197,91197,84:162,91162,104i-^y,X(3),62:"-":,X(3),X(2),Y(1)+,y"This circuit also has 3 paths for":"current. Current can flow through R1^":"and R2^, R1^ and R3^, or R1^ and R4^.",Jy3:28,6328,4058,40:77,40266,40266,61:266,79266,10428,10428,71:161,40161,56:126,66126,56196,5D1%1:2000XɳREWRITE:X15:,248,11:" EA ":Y160:Y:,248,11:"EA":X:WRITEγ,X(2),Y(7):"A) Add the branch voltages."::"B) Add the voltages of any one":" closed loop."س:"C) Add the series voltages to the":" values ofbegin.";:FROMOTHERYES:1000:RESPNSE$M$450206毱C*PAGE267000:,3,11:"Which method would you use to find":"in a series-parallel circuit? Type the";:"letter of your choice and press RETURN." ijX1%0:Y1%0:X2%279:Y2%36:H1%3:S1%1:000:FILE$"SERIES-PARALLEL.2.1":135003ȯ*PAGE25ү7000:,X(6),Y(4):"This practice set consists of 7"::"questions. To complete the"::"lesson successfully, you need"::"to answer 5 questions correctly."0ܯ,X(6),Y(13):"Press RETURN to T1$:PR$".":CM$",":SP$" ":NG$"-"GNLS$"WELCOME.SERIES-PARALLEL.2"i N*CONTROL*SERIES-PARALLEL.2.4t*N450004N46000>N47000HN48000RN49000\N50000fN51000pN52000zN(RIGHT5)153000,54000NRESPNSE$EXIT$11000&N1327)@LJJU0:NR1:LS2:QTNR:LENO:CR1:IN0:IG3:G04:RI0:WR0VJMA3:MF4:AN$(MA):FD$(MF2):FD(MA2,2):NMMF1:DNMF2:J1MA1:FD(J1,1)IGtJMOD(A)(A2)A2JCLR%809:SWD%803:HP%812JI$(9):QU$(34)#JB1$"0":T1$"9":B2$B1$:T2$(R(૲*PAGE24(꫰7000:,X(6),Y(5):"It's time to practice computing"::"values for IT^, EA^, and RT^ in"::"series-parallel circuits."(,X(6),Y(13):"To review the lesson first,"::"type R.">),X(6),Y(18):"Press RETURN to pra0. By adding this value/to 6.01}{0, the sum of the series/resistances, you would have found that/RT^ = 91}{0."'>AXPSX(1):AYPSY(15):XPSX(2):YPS134:STPYES:NMTCH2'C,X(7),Y(15):"1}{0";(H3000:JUDGECRRECTNMTCH3:STPNO:43080m of the series/resistances."&*FDBCK$(2)"Sorry. Find RE^ for the parallel/resistors; then add this value to/the series resistances. Try again."u'4FDBCK$(3)"Sorry. If you had used the Like/Method to find RE^, the value would/have been 3.01}{:OH$:,126,88:OH$:,189,56:OH$:,189,88:OH$:,252,72:"61}{0":,X(21),Y(15):OH$w%,X(21),Y(15):OH$%QUESTIN3:LNGTH3:LEAVITNO:ALTYES%ANSWER$(1)"9"& FDBCK$(1)"Right. RE^ = 3.01}{0. You then added/this value to the su,32183,43:183,61183,75:183,93183,104$ "3";:7:1:0:6119,32:6182,32:6182,104:6119,104:215,57:154,27:154,99:1136,99:16:1125,36:1125,68:1188,36:1188,68:1251,52:"0"]%OH$"31}{0":,56,48:OH$:,56,96:OH$:,126,56119,32119,43:119,61119,75:119,93119,104:182,32182,43:182,61182,75:182,93182,104#7:22,6422,3260,32:79,32246,32246,59:246,77246,104161,104:142,10479,104:60,10422,10422,72)$ 120,32120,43:120,61120,75:120,93120,104:183Y(17):"V":WRITE"t3000:+"*PAGE23"7000:,X(2),Y(1):"What is the RT^ for this circuit?":"Type your answer and press RETURN.""3:21,6421,3259,32:78,32245,32245,59:245,77245,104160,104:141,10478,104:59,10421,10421,72]#2)"Sorry. Add the voltages of 1one0 of/the paths. Try again."!VFDBCK$(NMTCH)"Sorry. Using path 2 we find that/1V + 21}{0x2A + 11}{0x3A = 8V = VA./The answer is 8."!`AXPSX(1):AYPSY(17):XPSX(2):YPSY(19):STPNO"jREWRITE:,X(8),,115:16:1153,41:1223,41:1251,41:"0"T .QUESTIN2:LNGTH4:LEAVITNO:ALTYESw 8ANSWER$(1)"8":ANSWER$(2)"12" BFDBCK$(1)"Right. The sum of each separate path/is equal to the sum of every other/separate path and is equal to VA^."B!LFDBCK$(246,88:246,104246,120199,120:179,120174,120:155,12022,12022,80*148,40148,48:148,66148,88:148,104148,120:218,40218,48:218,66218,88:218,104218,120, ,"3";:7:1:0:6147,40:6217,40:6217,120:6147,120:215,65:158,35:114940245,48:245,66245,88:245,104245,120198,120:178,120173,120:154,12021,12021,80&147,40147,48:147,66147,88:147,104147,120:217,40217,48:217,66217,88:217,104217,120G(7:22,7222,4064,40:83,40109,40:128,40246,40246,48:246,66PSY(16):XPSX(2):YPSY(18)G"ǯREWRITE:,X(9),Y(16):"A":WRITES"ǰ3000:`" ˲*PAGE32q"%˹34,16:CLR%"*˹34,0:REWRITE:X15:,56,9:" RT ":Y160:Y:,56,9:"RT":X:WRITEh#>˯REWRITE:,52,72:"21}{0":,147,34:".51}{0":,119,7 ":WRITE!QUESTIN6;!ANSWER$(1)"18":ANSWER$(2)"27"!FDBCK$(1)"Right. IT^ equals the sum of the/parallel branch currents."!FDBCK$(2)"Sorry. Don't add the series current./Try again."!FDBCK$(NMTCH)"Sorry. Try 18.""AXPSX(2):AY34,0:REWRITE:X15:,56,9:" IT ":Y160:Y:,56,9:"IT":X:WRITE LǺ"3";:0:1:0:1151,35:"0":3:147,40182,40 !VǯREWRITE:,59,72:"2A":,147,34:" ":,126,72:"7A":,175,72:"5A ":,245,72:"4A ":,149,117:"9A":,7,72:" h."eFDBCK$(2)"Sorry. You shouldn't add alternate/current paths. Add only one path./Try again."FDBCK$(NMTCH)"Sorry. Try 5."AXPSX(2):AYPSY(16):XPSX(2):YPSY(18)ï,X(9),Y(16):"V"İ3000:8Dz*PAGE31=ǹ34,16:CLR%J B99:16:183,54:1153,54:1174,54:1244,54RÒ7:0:6112,40:6112,104:"0"pQUESTIN5:LNGTH4:ALTYESANSWER$(1)"5":ANSWER$(2)"10":ANSWER$(3)"6.5"FDBCK$(1)"Right. EA^ is equal to the sum of the/voltages of any 1one0 current pat148,56148,61:78,7978,88148,88148,79:113,88113,104ï,21,64:"-":,21,80:"+":,59,72:"5V":,147,34:"2.5V":,126,72:"5V":,175,72:"1.5V":,245,72:"1.5V":,149,117:"1V"ï,7,72:"VA"-ú"3";:7:1:0:229,56:1151,35:1144,:77,6177,56147,56147,61:77,7977,88147,88147,79:112,88112,104Ò7:36,6336,40155,40:176,40204,40204,56:169,61169,56239,56239,61:169,79169,88239,88239,79:204,88204,104168,1048Ó148,10436,10436,71:113,40113,56:78,6178,56D1%1:2000TnïREWRITE:X15:,56,9:" VA ":Y160:Y:,56,9:"VA":X:WRITEÒ3:35,6335,40156,40:175,40203,40203,56:168,61168,56238,56238,61:168,79168,88238,88238,79:203,88203,104168,104FÓ149,10435,10435,71:112,40112,56ing":" to the resistor."*QUESTIN4MFDBCK$(1)"Sorry. Try again."dFDBCK$(2)"Right."p3000:}Pò*PAGE30Zð7000:,21,9:"Find for this circuit, type your":"answer, and press RETURN." dX1%0:Y1%0:X2%279:Y2%22:H1%3:S1%1:pe its":"letter and press RETURN."Z|X1%0:Y1%0:X2%279:Y2%36:H1%3:S1%1:D1%1:2000,X(3),Y(7):"A) Subtract the sum of the other":" series resistors from IT^.":"B) Add the branch currents."::"C) Add the branch currents flowllel circuit. Try again."1ƻFDBCK$(3)"Right."aлAXPSX(2):AYPSY(15):XPSX(2):YPSY(18)mڻ3000:zh*PAGE29#r7000:,3,11:"What method would you use to find the":"value of I for any series resistor in"::"a series-parallel circuit? Ty.":Q"B) Add all the values for current."::"C) Add the branch currents."_QUESTIN3FDBCK$(1)"Sorry. The last resistor may not/receive all of the current in/the circuit. Try again."FDBCK$(2)"Sorry. You could only do this/in a para Try again."<޷AXPSX(2):AYPSY(18):XPSX(8):YPSY(18)H跰3000:U*PAGE2817000:REWRITE:X15:,248,11:" IT ":Y160:Y:,248,11:"IT":X:WRITE,X(3),Y(7):"A) Add the branch currents flowing":" into the last resistore of the":" parallel branches to the series":" resistances.":"B) Add the resistances of all the":" resistors."::"C) Add the resistances of each of":" the current paths."QUESTIN2ʷFDBCK$(1)"Right." ԷFDBCK$(2)"Sorry. ry. Try B."1FDBCK$(NMTCH)"Type A, B, or C."aAXPSX(2):AYPSY(16):XPSX(2):YPSY(18)m(3000:z*PAGE2717000:REWRITE:X15:,248,11:" RT ":Y160:Y:,248,11:"RT":X:WRITED,X(3),Y(7):"A) Add equivalent resistanc all parallel voltages."PQUESTIN1:LNGTH1:LEAVITNO:STPNO:J1NMTCHINCRRECTANSWER$(1)"A":ANSWER$(2)"B":ANSWER$(3)"C"FDBCK$(1)"Sorry. This would only be the case/in a series circuit. Try again."FDBCK$(2)"Right."  FDBCK$(3)"Sor202,91:16:1174,50:1251,50:0:6168,40:6168,96:"0"%cq,X(12),Y(7):"R1^":,X(26),Y(8):"R2^":,X(37),Y(8):"R3^":,210,109:"R4^":,160,50:"A":,160,93:"B"%eq,X(5),Y(7):"-":,X(5),Y(10):"+"4&fq,X(14),Y(15):"Pre40:93,40245,40245,57:245,75245,96226,96:207,9642,9642,67:168,40168,57:168,75168,96$`q7:43,5943,4075,40:94,40246,40246,56:246,75246,96231,96:208,9643,9643,67:169,40169,57:169,76169,96;%aq"3";:7:1:0:236,52:169,35:11)#\qVSPACE,1:"Be careful about current in this type of";:"circuit. In the example below I4^ does":RESET:VSPACE,0:" not ";:BOXIT,3:VSPACE,1:" equal I1^, even though both are in":"series!":VSPACE,0#^q*SCHEMATIC.8.A_$_q3:42,5942,4074,GTH1:STPNO:LEAVEITYES:"mANSWER$(1)"A":ANSWER$(2)"B""mFDCK$(1)"Sorry. IT^ equals the sum of the/branch currents. Try again.""mFDBK$(2)"Right.""mAXPS8:AYPS165"mXPSX(7):YPSAYPS"m3000:1000:"Hq*PAGE8.A#Rq7000:,X(1),Y(,3:" currents ";:RESET:" only ";:RESET:".";!i1000:G!`m*PAGE8R!tm17000!~m,14,118:"Which statement best describes IT^?":,14,129:"Type its letter and press RETURN."!m:" A) IT^ = I1^ + I4^ B) IT^ = I2^ + I3^""mQUESTIN2:LN,10633,106:32,10632,84:31,10631,84:28,8731,8434,87 i7:96,10534,105:96,10434,104:96,10634,106:33,10633,84:32,10632,84:29,8732,8435,87/!i,X(18),Y(19):"IT^ equals the sum of":,X(1),Y(21):"the ";:RESET:" branch ";:BOXIT178,105181,108Yi7:254,84254,104181,104:254,105181,105:182,102179,105182,108i,X(1),Y(15):"Now the current flows together again at"::"B, so I4^ equals IT^, just as in a"::"series circuit.": i3:95,10533,105:95,10433,104:95ust as in a"::"series circuit."ti3:165,105113,105:165,104113,104:165,106113,106:114,102111,105114,109i7:166,105114,105:166,104114,104:166,106114,106:115,102112,105115,109i3:253,84253,104180,104:253,105180,105:181,102e7:181,32254,32:181,31254,31254,48:253,46254,48256,46e,X(1),Y(21):"I3^ since the two resistors are parallel."f1000:xi*PAGE7i17000!i,X(1),Y(15):"Now the current flows together again at"::"B, so I4^ equals IT^, jWRITEOe,X(17),Y(19):"Now IT^ equals I2^ ";:RESET:" plus ":BOXIT,3be*VECTOR.SPLITe3:158,52158,83:156,81158,83160,81e7:159,52159,83:157,81159,83161,81e3:180,32253,32:180,31253,31253,48:252,46253,48255,46>";:FROMOTHERYES:1000:RESPNSE$M$26068`eREWRITE:,X(14),Y(20):" ":WRITEe,X(10),Y(17):" Part of it goes to R2^; part of";:,X(1),Y(19):"it goes to R3^.":X1250:XeREWRITE:,X(24),Y(15):RESET:"A";:BOXIT,0:REWRITE:,X(24),Y(15):RESET:" A ";:BOXIT,3:WRITEGe*FLOW.TO.Ae3:112,31161,31:112,32161,32:112,33161,33:158,28161,32158,36e7:113,31162,31:113,32162,32:113,33162,33:159,28162,32159,36*e,X(14),Y(20):"Press RETURN. ":WRITEa,X(21),Y(17):"At this point, I1^ is":,X(1),Y(19):"equal to IT^, just as it is in a series"::"circuit."b1000:e*PAGE6e17000e,X(1),Y(15):"Next, current flows to A, where it"::"divides.":X1250:X7e3,3294,32:33,3194,31:91,2894,3291,36a7:35,4535,32:34,3234,45:34,3395,33:34,3295,32:34,3195,31:92,2895,3292,36a,X(14),Y(19):"Press RETURN.";:FROMOTHERYES:1000:RESPNSE$M$25084 aREWRITE:,X(14),Y(19):" through R1^, "%a*FLASH.RESISTOR2aLX112Fa"3";:3:1:0Sa169,35iaLX:YZ1300:YZzaLX1225072a"0";a,X(33),Y(15):"which is";::,X(1),Y(17):"a series resistor."*a3:34,4534,32:33,3233,45:33,3394,33:32:"61}{0":,175,72:"31}{0":,245,72:"61}{0":,149,117:".51}{0":,52,72:"61}{0":WRITE~#H˒0:156,40175,40#R˺"3";:3:1:0:1151,35:"0"#zQUESTIN7#ANSWER$(1)"1.5"#FDBCK$(1)"Right."{$FDBCK$(2)"Sorry. Find RE^ fo ":WRITE5ˆ17000:,0,100:"Which statement describes RT^? Type its":,0,110:"letter and press RETURN."5̈,17,122:"A) RT^ = R1^ + R2^ + R3^ + R4^"5ֈ,17,134:"B) RT^ = R1^ + RC^ + R4"6,17,146:"C) RT^ ="circuit, we compute RC^ for the parallel"Z4:"part of the circuit (R2^ and R3^)."4:"We then compute RT^ as if we had a series";::"circuit composed of R1^, RC^, and R4^."4 1000:4*PAGE125REWRITE:,0,110:" ,X(12),Y(6):"R1^":,X(26),Y(7):"R2^":,X(37),Y(7):"R3^":,X(16),Y(10):"R4^":,159,42:"A":,159,86:"B"3ᄯ,X(5),Y(6):"-":,X(5),Y(9):"+":RXPS14:RYPS14:15000,4䄯,X(1),Y(14):"To find the total resistance for this"::168,32168,49:168,67168,882݄7:43,5143,3275,32:94,32246,32246,49:246,67246,88122,88:103,8843,8843,59:169,32169,49:169,67169,882߄"3";:7:1:0:236,44:169,27:197,83:16:1174,42:1251,42:7:0:6168,32:6168,88:"0"}3*PAGE111ڄ7000:,1,8:RESET:" Resistance ";:BOXIT,3:" in this circuit is like that":,1,19:"in a series ";:RESET:" and ";:BOXIT,3:" a parallel circuit."2܄3:42,5142,3274,32:93,32245,32245,49:245,67245,88121,88:102,8842,8842,59::X2%163X:Y2%25X:H1%3:S1%1:D1%1:2000V0Y190:Y:,X(16),Y(3):" "0 X:,X(16),Y(3):"REMEMBER":WRITE0,X(6),Y(10):"Applied voltage equals the sum"::"of the voltages in any separate"::"current path."0$1000:1Є/one path. Try again."G/Z}FDCK$(3)"Yes. VA^ = V1^ + V3^ + V4^."k/d}FDBK$(NMTCH)"Type A, B, or C."/n}AXPS2:AYPS165/x}XPS36:YPSAYPS/}3000:1000:/耲*PAGE10A/7000:REWRITE+0X16:,X(16),Y(3):"REMEMBER":X1%104X:Y1%15X^ + 2V4^ + V2^"?.(},16,148:"C) VA^ = V1^ + V2^ + V4^"h.2}QUESTIN3:LNGTH1:STPNO:LEAVEITYES.<}ANSWER$(1)"A":ANSWER$(2)"B":ANSWER$(3)"C".F}FDCK$(1)"No. V is additive in series./Try again."/P}FDCK$(2)"No. VA^ equals the voltage inESET:" either ";:BOXIT,3:" path."0-hy1000:>-} *PAGE10- }17000:,7,102:"Which statement describes VA^? Type its":,7,112:"letter and press RETURN."-},16,124:"A) VA^ = V1^ + V2^ + V3^ + V4^".},16,136:"B) VA^ = 2V1^ + 2V3As we saw, current has two paths: one"::"is through R1^, R2^, and R4^;",Jy,X(28),Y(17):"the other is":,X(1),Y(19):"through R1^, R3^, and R4^."$-^y,X(26),Y(19):"Thus, VA^ equals";:,X(1),Y(21):"the sum of the voltages in ";:R,42:7:0:6168,32:6168,88:"0"+2y,X(12),Y(6):"R1^":,X(26),Y(7):"R2^":,X(37),Y(7):"R3^":,X(16),Y(10):"R4^":,159,42:"A":,159,86:"B"+4y,X(5),Y(6):"-":,X(5),Y(9):"+":RXPS14:RYPS15:15000L,6y,X(1),Y(15):"45,67245,88121,88:102,8842,8842,59:168,32168,49:168,67168,88*.y7:43,5143,3275,32:94,32246,32246,49:246,67246,88122,88:103,8843,8843,59:169,32169,49:169,67169,88#+0y"3";:7:1:0:236,44:169,27:197,83:16:1174,42:1251y7000)"y,X(1),Y(1):RESET:" Voltage ";:BOXIT,3:" in this circuit equals the sum":,0,17:"of the voltages in any ";:RESET:" one ";:BOXIT,3:" complete path";:"for current."),y*SCHEMATIC.9E*-y3:42,5142,3274,32:93,32245,32245,49:21:20003(NuY190:Y:,X(16),Y(3):" "](SuX:,X(16),Y(3):"REMEMBER":WRITE(Xu,X(6),Y(10):"Total current in a series-"::"parallel circuit equals the sum"::"of the branch, or parallel,"::"currents."(lu1000:(y*PAGE.9)ESET:" Current in a series resistor equals the ";:BOXIT,3v'q::RESET:" current flowing into it ";:BOXIT,3:"."'q1000:'0u*PAGE8.B':u7000:REWRITE(DuX16:,X(16),Y(3):"REMEMBER":X1%104X:Y1%15X:X2%163X:Y2%25X:H1%3:S1%1:D1%ss RETURN.";:FROMOTHERYES:1000:RESPNSE$M$29030j&pqREWRITE:,X(14),Y(15):" ":WRITE&zq,X(1),Y(16):"Why is this? IT^ ";:RESET:" divides ";:BOXIT,3:" at A, so only"::"current flowing through R3^ flows to R4^.";'q:R0:34,0:35,4:CLR%1a32,0:33,40:34,0:35,24<a17000a,1,9:RESET:" Current flow ";:BOXIT,3:" in this circuit is like":,0,18:"that in a series ";:RESET:" and ";:BOXIT,3:" a parallel circuit."a,X(1),Y(15):"Current first flows:ANSWER$(2)"B"V^FDCK$(1)"Sorry. 1 and 4 are in series./B is the correct answer."l^FDBK$(2)"Right."^FDBK$(NMTCH)"Type A or B."^AXPS14:AYPS167.^XPSX(8):YPSAYPS8^3000:a*PAGE5a*CLEAR.TEXT.LEAVE.GRAPHICSa32,0:33,4:"+":RXPS14:RYPS15:15000],X(3),Y(15):"Which resistors are arranged in":"parallel? Type the letter of":"your answer and press RETURN."]:" A) R1^ and R4^ B) R2^ and R3^]QUESTIN1:LNGTH1:STPNO:LEAVEITNO]ANSWER$(1)"A"0:236,52:169,35:197,91:16:1174,50:1251,50:7:0:6168,40:6168,96:"0"],X(12),Y(7):"R1^":,X(26),Y(8):"R2^":,X(37),Y(8):"R3^":,X(16),Y(11):"R4^":,159,50:"A":,159,94:"B"],X(5),Y(7):"-":,X(5),Y(10)w]3:42,5942,4074,40:93,40245,40245,57:245,75245,96121,96:102,9642,9642,67:168,40168,57:168,75168,96]7:43,5943,4075,40:94,40246,40246,57:246,75246,96122,96:103,9643,9643,67:169,40169,57:169,75169,96U]"3";:7:1:arallel circuit."Z1000:)]*PAGE4]7000:,17,11:"This series-parallel circuit has":,17,20:"resistors arranged in a series ";:RESET:" and ":BOXIT,3:"in parallel."]X1%14:Y1%0:X2%262:Y2%30:H1%3:S1%1:D1%1:2000]*SCHEMATIC.4S:1000:RESPNSE$M$23045Q ZREWRITE:,X(14),Y(17):" ":WRITE Z,X(1),Y(15)::"Each circuit has the characteristics and";::"obeys the laws of its type. In the next";::"step, you'll see the two combine to"::"make a series-p96aY7:162,63162,40267,40267,61:267,79267,96162,96162,71:211,40211,61:211,79211,96Z"3";:7:1:0:2155,56:16:1216,54:1272,54:"0"Z,X(22),Y(8):"-":,X(22),Y(10):"+"Z,X(14),Y(17):"Press RETURN.";:FROMOTHERYE85,40127,40127,96111,96:92,9629,9629,71vY"3";:7:1:0:222,56:160,35:186,91:6210,40:6210,96:"0"Y,X(3),Y(8):"-":,X(3),Y(10):"+"Y3:161,63161,40266,40266,61:266,79266,96161,96161,71:210,40210,61:210,79210,AGE3 Y7000:,FX(1),Y(1):"Here are two circuits. The one on your":"left is a series circuit; the other is":"a parallel circuit." Y*SCHEMATIC.3 Y3:28,6328,4065,40:84,40126,40126,96110,96:91,9628,9628,71-Y7:29,6329,4066,40:RIES-PARALLEL.1.1 *N23000' 4N240002 >N25000= HN26000H RN27000S \N28000^ fN29000i pN30000t zN31000 N32000 N33000 N34000 N35000 N36000 N37000:RESPNSE$"R"20010 N13000:FILE$"SERIES-PARALLEL.1.2":13500 Y*PFD$(MF2):FD(MA2,2):NMMF1:DNMF2:J1MA1:FD(J1,1)IGS tJMOD(A)(A2)A2q JCLR%809:SWD%803:HP%812 JI$(9):QU$(34) JB1$"0":T1$"9":B2$B1$:T2$T1$:PR$".":CM$",":SP$" ":NG$"-" NLS$"WELCOME.SERIES-PARALLEL.1" N*CONTROL*SELOADSCHEMATIC.SYMBOLS.1,A"AD",D1":ADDR,3,(115)((116)4)256\ 3 612000-6103,1:104,80:16302,0:18:*P.R.:,X(RX),Y(RY):"Press RETURN.";:FROMOTHERYES:1000:RESPNSE$M$15010:,X(RX),Y(RY):REWRITE:" ":WRITE:hB*PARTIAL.ERASE|B32,0:33,40:34,14:35,24:CLR%# B32,0:                             1,54:7:0:6133,40:6133,96:"0"],X(12),Y(7):"R1^":,X(21),Y(8):"R2^":,X(37),Y(8):"R3^":,X(28),Y(11):"R4":,X(5),Y(8):"-":,X(5),Y(11):"+"],X(4),Y(15):"A) RT^ = R1^ + RC^ of R2^ and (R3^ + R4^)"(]:45,79245,96205,96:186,9635,9635,75:133,40133,61:133,79133,96]7:36,6736,4072,40:91,40246,40246,61:246,79246,96206,96:187,9636,9636,75:134,40134,61:134,79134,96$]"3";:7:1:0:229,60:166,35:1181,91:16:1139,54:12520:";:FROMOTHERYES:1000:RESPNSE$M$RESPNSE$"R"37020:ing"::"the practice set, type R.";,X(4),Y(13):"To practice, press RETURN.";:FROMOTHERYES:1000:RESPNSE$M$RESPNSE$"R"37020:$M$RESPNSE$"R"37020:370ed":" resistance of the parallel branches.";:1000:H:*PAGE14:7000:,X(4),Y(5):"It's time to check your knowledge!":::"To review the lesson before doing"::"the practice set, type R.":;,X(4),Y(13):"To practice, press RETURN.RXPS14:RYPS13:150009܌,X(1),Y(13):"3. Total voltage equals the sum of the":" voltages in any separate current":" path.":RXPS14:RYPS17:15000/:振,X(1),Y(17):"4. Total resistance equals the series":" resistance plus the combinARY":WRITE8Ȍ,X(1),Y(6):"1. A series-parallel circuit has":" resistors arranged in series and in":" parallel.":RXPS14:RYPS10:150009Ҍ,X(1),Y(10):"2. Total current equals the sum of the":" currents in the parallel branches.":XPS2:AYPS162"70XPS36:YPSAYPS47:3000:1000:A7*PAGE13T77000:REWRITE7X16:,X(16),Y(3):"SUMMARY":X1%104X:Y1%15X:X2%155X:Y2%25X:H1%3:S1%1:D1%1:20007Y190:Y:,X(16),Y(3):" " 8ÌX:,X(16),Y(3):"SUMM R1^ + R2^ + R3^"=6QUESTIN4:LNGTH1:STPNO:LEAVEITYESn6ANSWER$(1)"A":ANSWER$(2)"B":ANSWER$(3)"C"6FDCK$(1)"No. Remember this is a series/parallel circuit. Try again."6FDCK$(2)"Right. RC^ is the combined R/of R2^ and R3^."7&ARETURN to begin.";:FROMOTHERYES:1000:RESPNSE$M$22040:Aeristics of both"::"a series and a parallel circuit." V,X(8),Y(24):"Press RETURN to begin.";:FROMOTHERYES:1000:RESPNSE$M$22040:@:"to define and identify this type of"::"circuit." V,X(8),Y(24):"Press RETURN to begin.";:FROMOTHERYES:1000:RESPNSE$M$22040::"circuit has the characteristics of both"::"a series and a parallel circuit."< V,X(8),Y(24):"Press ghij ":" lmnopq 0" NR1000:, U*PAGE2E U7000:,X(1),Y(5) V" Hi! This lesson, which is about 20";::"minutes long, introduces you to the"::"series-parallel circuit. When you have"6 V:"completed the lesson, you should be able";:allel":,84,71:"Circuits, Part 1" !RX1%28:Y1%7:X2%254:Y2%78:H1%1:S1%2:D1%3:2000:X1%29:Y1%8:X2%254:Y2%79:H1%2:S1%2:D1%3:2000 0R,57,106:"CONVERGENT SYSTEMS, INC." :R,106,128:"2 ABCDEF ":" HIJKLM ":"OPQRSTUV":"WXYZabcd":" efE.SERIES-PARALLEL.1  %NWRITE* *N210005 4N22000B 9NREWRITEp >N13000:FILE$"SERIES-PARALLEL.1.1":13500 RTITLEPAGE# R7000:,X(7),Y(3):" BASIC ELECTRONICS"::"FUNDAMENTALS OF DC CIRCUITRY":" DISK #3":,84,62:"Series-Par 612000-6103,1:104,80:16302,0:1A8JINITIALIZATIONBJZ9815:YE1:NO0:BOYE:A$"":A1$A2$:G$(7):M$(13):D$M$(4):EX$(27)VJMOD(A)(A2)A2tJCLR%809:SWD%803:HP%812NLS$"WELCOME.SERIES-PARALLEL.1" N*CONTROL*WELCOM     31,45:231,63231,78142,78:123,78111,78:97,7828,7828,55:91,3291,45:91,6391,78:161,32161,45:161,63161,78a7:29,4729,32232,32232,45:232,63232,78143,78:124,78112,78:98,7829,7829,55:92,3292,45:92,6392,78:162,32162,45:162,63^AXPS7:AYPS174+.^XPSX(7):YPSAYPS=8^3000:1000:Ja*PAGE18a7000:,9,11:"What does the ammeter measure? Type":,9,19:"its letter and press RETURN."aX1%0:Y1%0:X2%266:Y2%22:H1%3:S1%1:D1%1:2000ua3:28,4728,32231,322"B) RT^ = R4^ + RC^ of R2^ and R3^"G]:"C) RT^ = R1^ + R4^"p]QUESTIN2:LNGTH1:STPNO:LEAVEITYES]ANSWER$(1)"A":ANSWER$(2)"B":ANSWER$(3)"C"^FDBCK$(1)"Right."^FDBCK$(2)"Sorry. Try again."^FDBCK$(NMTCH)"Type A, B, or C."-----+M)M)+M)M)+M)M)+M)M)IIIq'%557'?---ۛ$< 878??LIa %$  ; ; * ; ; ; ----- ---  )-  - --mI mII)MII kIII MIIIMIIIMIIIMII mII)mI --II q66+@T'/9T  ) - ) ??;??? -- ) - -) )- ?;? )  ; ; ; ??? ????? ??? ????? ;,"ӱ"54040,"ӱthe":,ӯ,X(5),Y(23):"lesson or press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"54040,"ӱHcore was"::RIGHT" correct answers out of 7)."+ӯ,X(5),Y(19):"Don't shoot yourself, either."::"Instead, type R to review the":+ӯ,X(5),Y(23):"lesson or press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"54040"lesson or press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"54040e*"ӱ,X(9),Y(6):CHARMODE,3:COL,2:"OH NO...":COL,3:CHARMODE,0/+ӯ,X(5),Y(12):"Don't shoot the messenger! (I just"::"deliver the news--your sHARMODE,0)ӯ,X(5),Y(12):"Don't shoot the messenger! (I just"::"deliver the news--your score was"::RIGHT" correct answers out of 7).")ӯ,X(5),Y(19):"Don't shoot yourself, either."::"Instead, type R to review the":_*ӯ,X(5),Y(23):re was "RIGHT" correct out of 7."W(ӯ,X(5),Y(14):"Type R to review the lesson,":(ӯ,X(5),Y(16):"or press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"54040("ӱ09),Y(6):CHARMODE,3:COL,2:"OH NO...":COL,3:Completed this lesson"::"successfully."'0ϯ,X(5),Y(18):"Press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$53040':ϱ'Ҳ*PAGE34'Ұ7000:,X(9),Y(6):CHARMODE,3:COL,2:"SORRY.":COL,3:CHARMODE,0!(ӯ,X(5),Y(12):"Your scoCRRECT52180A&˭JUDGECRRECTNMTCH3:3000:JUDGEIGNREī52170G&˱T&ϲ*PAGE33&ϰ7000:,X(9),Y(6):CHARMODE,3:COL,2:"GOOD WORK!":COL,3:CHARMODE,0&ϯ,X(5),Y(12):"Your score was "RIGHT" correct out of 7!"('&ϯ,X(5),Y(14):"You've crs is 31}{0. The rightmost 4/resistors have an effective resistance/of 31}{0."%AXPSX(2):AYPSY(15):XPSX(2):YPSY(17):STPYES:NMTCH2:LNGTH3%˯REWRITE:,X(1),Y(16):" ":,X(8),Y(15):"1}{0":WRITE &TRIES0:3000:JUDGEr the parallel/resistors; then add this value to the/series resistances to get the/equivalent resistance of one branch."S%FDBCK$(3)"Sorry. The total resistance of the/circuit is 1.51}{0. The effective/resistance for the leftmost parallel/resisto) The sum of the voltages in any":" one current path equals the":" applied voltage.""i:"C) The sum of the voltages of all":" of the current paths equals the":" applied voltage.""iQUESTIN5:LNGTH1:STPNO:LEAVEITYES6#iFDBCK$(1)"Sorryent is true of a series-":,8,19:"parallel circuit? Type its letter and";:,8,27:"press RETURN."!iX1%3:Y1%0:X2%277:Y2%30:H1%3:S1%1:D1%1:2000!i,X(2),Y(6):"A) Applied voltage equals the sum of":" the individual voltages."Z"i:"B"No. This would result in a sum/that was more than the total/current. Try again." eFDBCK$(3)"Sorry. Current is constant/in a series circuit only./Try again." eAXPSX(2):AYPSY(18) f3000:1000: xi*PAGE20e!i7000:,8,11:"Which statements plus the combined":" current of the parallel branches."e:"C) Total current in a series-parallel":" circuit equals the current at any":" point in the circuit."eQUESTIN4:LNGTH1:STPNO:LEAVEITYESeFDBCK$(1)"Right."T eFDBCK$(2)%22:H1%3:S1%1:D1%1:2000e,X(2),Y(5):"A) Total current in a series-parallel":" circuit equals the sum of the":" parallel branch currents."?e:"B) Total current in a series-parallel":" circuit equals the sum of the":" series currowing into R4^."6aFDBCK$(NMTCH)"Type A, B, or C."QbAXPSX(2):AYPSY(18)hbXPSX(7):YPSAYPSz b3000:1000:e*PAGE19e7000:,11,10:"Which statement is true? Type its":,11,18:"letter and press RETURN."eX1%0:Y1%0:X2%266:Y2the ammeter. Try again."aFDBCK$(2)"Sorry. Current flowing out of a/resistor in a series-parallel/circuit equals the current/flowing into it. Try again."aFDBCK$(3)"Right. The ammeter only measures/the amount of current that has/rejoined before fl(31),Y(7):"R3^"(a,119,90:"R4^"QaVSPACE,5:,X(4),Y(13):"A) IT^"na"B) I2^ + I3^ + I4^"a"C) I2^ + I3^":VSPACE,0aQUESTIN3:LNGTH1:STPNO:LEAVEITYESaFDBCK$(1)"Sorry. The currents don't/completely rejoin until after/162,78%a"3";:7:1:0:4102,72a222,40:1118,73:16:197,38:1167,38:1237,38:7:0:691,32:691,78:6161,32:6161,78:"0"a,21,74:"+":,21,40:"-":,101,81:"A"a,X(11),Y(7):"R1^"a,X(21),Y(7):"R2^"a,Xs RETURN to begin.";:FROMOTHERYES:1000:RESPNSE$M$22030B Vr lessons.":::" You'll need about 15 minutes to"::"complete the lesson." V,X(6),Y(20):"Press RETURN to begin.";:FROMOTHERYES:1000:RESPNSE$M$22030 VAneed about 15 minutes to"::"complete the lesson."< V,X(6),Y(20):"Pres1000: U*PAGE2 U7000:,0,21:" Welcome! In this lesson on"::"series-parallel circuits, you will have"::"an opportunity to analyze, or "(34)"trouble-"::"shoot,"(34)" this type of circuit by using"Q V:"what you have learned in othes, Part 3"v !RX1%28:Y1%7:X2%254:Y2%77:H1%1:S1%2:D1%3:2000:X1%29:Y1%8:X2%254:Y2%78:H1%2:S1%2:D1%3:2000 0R,57,106:"CONVERGENT SYSTEMS, INC." :R,106,128:"2 ABCDEF ":" HIJKLM ":"OPQRSTUV":"WXYZabcd":" efghij ":" lmnopq 0" NRE.SERIES-PARALLEL.3 *N21000) 4N22000W >N13000:FILE$"SERIES-PARALLEL.3.1":13500f RTITLEPAGE R7000:,X(7),Y(3):" BASIC ELECTRONICS"::"FUNDAMENTALS OF DC CIRCUITRY":" DISK #3":,84,62:"Series-Parallel":,84,71:"Circuit 612000-6103,1:104,80:16302,0:1A8JINITIALIZATIONBJZ9815:YE1:NO0:BOYE:A$"":A1$A2$:G$(7):M$(13):D$M$(4):EX$(27)VJMOD(A)(A2)A2tJCLR%809:SWD%803:HP%812NLS$"WELCOME.SERIES-PARALLEL.3" N*CONTROL*WELCOM     z#?8   Ůӭ̮ ӭ̮6 ӭ̮% خٮ ӭ̮. Ůӭ̮!ӭ̮#"ӭ̮&Ůӭ̮îӮ ̭٠ӮԠ ĮٮٮٮҠӭ̮ ӭ̮-ٮǮԠ Ϡ ԮŠŮ Ůà"ŠŠŮʠ tatement describes RT^? The":,3,22:"parallel resistors are equal. Type the":,3,32:"letter of your choice and press RETURN."]X1%0:Y1%0:X2%279:Y2%35:H1%3:S1%1:D1%1:2000]*SCHEMATIC.17E]3:35,6735,4071,40:90,40245,40245,61:2has resistors arranged/in parallel and in series."nZZFDCK$(3)"No. This is a parallel/circuit. Try again."_ZFDBCK$(NMTCH)"Type A, B, or C."dZAXPSX(2):AYPSY(20)nZXPSX(7):YPSAYPSxZ3000:1000:]*PAGE17]7000:,3,10:"Which s26),Y(6):"-":,X(26),Y(10):"+"R&Z,X(4),Y(13):"-":,X(4),Y(17):"+"{(ZQUESTIN1:LNGTH1:STPNO:LEAVEITYES2ZANSWER$(1)"A":ANSWER$(2)"B":ANSWER$(3)"C"FZFDCK$(1)"Sorry. This is a series circuit./Try again."2PZFDCK$(2)"Right. It 109:84,12784,136 Z7:29,11129,96117,96:136,96148,96148,109:148,127148,13629,13629,119:85,9685,109:85,12785,136"Z"3";:7:1:0:222,104:1111,91:16:190,102:1153,102:"0"$Z,X(4),Y(6):"-":,X(4),Y(10):"+"$%Z,X(274,75274,80183,80183,67:225,40225,57:225,75225,80uZ"3";:7:1:0:2176,52:16:1230,50:1279,50:"0"Z,X(2),Y(16):"B)"Z*SCHEMATIC16.BZ3:28,11128,96116,96:135,96147,96147,109:147,127147,13628,13628,119:84,9684,0:222,49:148,35:170,75:7:6224,40:6224,80:684,96:684,136:"0"g Z,X(24),Y(8):"C)"{ Z*SCHEMATIC16.C Z3:182,59182,40273,40273,57:273,75273,80182,80182,67:224,40224,57:224,75224,809 Z7:183,59183,40274,40274,57:%15:Y1%0:X2%268:Y2%29:H1%3:S1%1:D1%1:2000JY,X(2),Y(8):"A)"^Y*SCHEMATIC16.AY3:28,5628,4053,40:72,40147,40147,8094,80:75,8028,8028,64Y7:29,5629,4054,40:73,40148,40148,8095,80:76,8029,8029,64MY"3";:7:1:ed"::"to correctly answer 4 of them." V,X(6),Y(16):"Press RETURN to begin.";:FROMOTHERYES:1000:RESPNSE$M$22020: Y*PAGE16 Y7000:,18,10:"Which of these is a series-parallel":"circuit? Type its letter and press":"RETURN."1YX125000 HN26000 RN27000& \N28000C fN(RIGHT4)129000,30000] pNRESPNSE$EXIT$11000y zN13000:FILE$LS$:13500 U*PAGE15' U7000:,X(6),Y(6):"This practice set contains 6"::"questions. To complete the"::"lesson successfully, you neIG tJMOD(A)(A2)A29 JCLR%809:SWD%803:HP%812O JI$(9):QU$(34) JB1$"0":T1$"9":B2$B1$:T2$T1$:PR$".":CM$",":SP$" ":NG$"-" NLS$"WELCOME.SERIES-PARALLEL.1" N*CONTROL*SERIES-PARALLEL.1.2 'N22000 *N23000 4N24000 >N4)256$ Ҥˤ^B ؠؠ^°ùàŹùĠİưĠĠàưčİǍ̷ ʛ˛͛=ɛڕڝڝڝڝǍǍ@峳@˨˨610رٱزٲȱӱ԰ܢŠéΠΠֳ"\_Tҧ̭ @Р̧ĺŹù婍, N \,LLL/Hh( Q՗$`h Y,LL,0`,HHɓ4ɛ0ɐ,Ƀ ɘ )L՗hh`, b:/8`Ԡƌ0c L` 0 H h`hNNɝ``? D ? 0`? H h0ED Lɠj,LH)? h`, 3ɍNɖ HH hh`,0ɍ3 ɛɓ 8I)I h`$8n ,L -,,0ɁϬ,c0 ې II ,Pɛ,0@L,?ɛ&,! ŗ0̗ $L$,0ɕ ڔ`( Q8nN 2ɧ )ɧɝ$Lj ) O,I LE CL$8f< NE$<CC CE?AC8A  L$>I Ԗ8LE? L ? ?L CC ` LH@ɠ$@ ɢE@@EE=h`(,L$(H,0 @))(N CEEɛ@ . L٪ $ .`DH )hhhNCLȎHH$`ʩ L ɠE .CH $h L\ $>N ґ  ԖEH3ɾɪ$@ɢE@@$@0 )ߝh` LcEEC Lؓ N EE ڔ`n ,8`0 őɢɢLԗ8ӗ ԗ )` EHӗȹɿh` h` Eɠ`AɀeE*EEA ʽAIE EA`C  LE `N F?p``p?p``p?xxx F ww pw!!;oG@`00p`ACGN\\ @`p88pp8p8`p8`p88p` 8888Ccs;xLLx /0 ?p88pGN \0000 ?DEFx xxx F!!8x8x@`00p`??xLLx /0 ?p88p}||0000 ?DE= R4^ + RC^ of R2^ and R3^">]:"C) RT^ = R1^ + R4^"g]QUESTIN2:LNGTH1:STPNO:LEAVEITYES]ANSWER$(1)"A":ANSWER$(2)"B":ANSWER$(3)"C"^FDBCK$(1)"Right."^FDBCK$(2)"Sorry. Try again."^FDBCK$(NMTCH)"Type A, B, or C." ^AXPS* :):(4)"BRUN HELLO":2"FUNDAMENTALS OF DC CIRCUITRY"::-:6:"Press any key (except E) to":6:"start lesson."::::6:"Press E to Edit lesson.";2A$:A$"E"ĺ:(4)"BRUNHELLO":<:(4)"RUNBOOT.PLE":practice set, type R."H+,X(4),Y(13):"To practice, press RETURN."7),Y(19):"Press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"30040:RYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"30040:REXIT$RESPNSE$"R"30040:E$"R"30040:: lesson before doing"::"the THERYES:NXNO:1000:RESPNSE$EXIT$29030::)0u*PAGE23w):u7000:,X(7),Y(6):CHARMODE,3:"Sorry...":CHARMODE,0)Du,X(7),Y(11):"Your score was "RIGHT" correct"::"out of 6.")Nu,X(7),Y(16):"To review the lesson now, type R."b*Xu,X(:1000:(Hq*PAGE.22V(Rq7000:,X(10),Y(4):CHARMODE,3:"FANTASTIC!":CHARMODE,0(\q,35,79:"Your score was ";:RIGHT" correct"::"out of 6."::"You have completed this lesson"::"successfully."-)fq,X(6),Y(22):"Press ESC to leave.";:FROMOLNGTH1:STPNO:LEAVEITYEST'mFDBCK$(1)"Sorry. This statement is true./Try again."'mFDBCK$(2)"Right. The statement is false/because current flowing through/R3^ must also flow through R4^."'mAXPSX(2):AYPSY(19)'mXPSX(7):YPSAYPS(m3000,X(11),Y(7):"R1^"2&m,X(21),Y(7):"R2^"N&m,X(31),Y(7):"R3^"d&m,119,90:"R4^"&m,21,74:"+":,21,40:"-"&mVSPACE,5:,X(4),Y(13):"A) VA^ = V1^"&m"B) VA^ = V2^ + V4^"&m"C) VA^ = V3^":VSPACE,0'mQUESTIN6:m7:29,4729,32232,32232,45:232,63232,78143,78:124,7829,7829,55:92,3292,45:92,6392,78:162,32162,45:162,63162,78%m"3";:7:1:0:222,40:1118,73:16:197,38:1167,38:1237,38:7:0:691,32:691,78:6161,32:6161,78:"0"&mType its":,14,19:"letter and press RETURN."f$tmX1%11:Y1%0:X2%269:Y2%22:H1%3:S1%1:D1%1:2000x$~m*SCHEMATIC21$m3:28,4728,32231,32231,45:231,63231,78142,78:123,7828,7828,55:91,3291,45:91,6391,78:161,32161,45:161,63161,78%. V is additive in series/circuits only. Try again."M#iFDBCK$(2)"Right."#iFDBCK$(3)"Sorry. The sum along any one/current path equals VA^."#iAXPSX(2):AYPSY(18)#i3000:1000:#`m*PAGE21.$jm7000:,14,10:"Which statement is false? ·ĥرٱȱDZŠέṷ̆Ԣ Ġӭ̮1ӅŠ̄1Šӭ̮.ôø¹Ʋ³ưà ŶİŶƲİ ôǠİG ŶİŶƲİ ôǠİǍӠŢ ϻҽӺ±Ť>Ҥˤ^ ؠؠ^ӽӽ±ͪ BԬب٨ӃǍǍˠڝڝZˠڝڝZ@峳@ŠڝڝZ˨˨610  رٱزٲȱӱı²ôø¹Ʋ³ưàűű \_Tҧ̭ @Р̧ĺŹù°ùàŹùĠİưĠĠàưčİǍ̷ ʛ˛͛=ɛڕڝڝڝڝ @@@ @ H$ "H"A"@ >A>`0> ē@c2iO  %GA G$<@c@pPDaPH @pERG$G$qdG$@$Oy‡@ H$H$ HRQH$< @pC>q E@>y8#q>A #q8@A@@@  J'H#y@ qH$8>#>#@q"'@p80" @ "J%"I%H$q#Hȣ<y>@ "H$q":AHOV]dkry @  &A@@@AQ!‡@@ ALeq_ ")07>ELSZahov} %,3P0HH-#$-  $#-hh`( &H(h`H#) c)h Hh` J ɠɍɘɈɕ ɛɃک./ ?.`L ` ` )!) !` `LLLR LX  m!8!` )` J 0 ?`$H$ h$`% $(&)m,'`,#P $&! `'i'`"% %%#LX  0 >H h`,# 릡`67 `6789 `    L`` -` ! "!  "蘝`     ` ) 8  8m$ imi8 %8mߠ:)p):=pLȘe::HH`UNHOOREHOOCLRWINWRITREWRITEXADDRESEBOXIHSPACVSPACCHARMODLMARGIPAGEPAGENMCOBEE$KQW^ ,69N<q{ {808$m$imi`%J!8!`ɖ%Jm`ɇ |`ɕ `Ɇ `ɠ`m%mm%8%%m! !` Š ԠŠ ˠŠ ԠŠ ˠŠ ̠ŠŠŠ͠ŠŠ: ŠԠE ĠŠ ŠԠ ˠɯϠ |Aȑȩȑȩȑ |AfLAȩEY ȩ |A |ALAɍ`BH h0`  6uX fG nALA,E,C,D}*bRESPNSE$" "į,X(5),Y(7CHOICE2):REWRITE:RESET:CHOICE5". "I$(CHOICE,0);:BOXIT,0:,X(5),Y(18):99)" ":250704bWRITE:FILE$I$(CHOICE,1):HOICE2):REWRITE:RESET:(9)CHOICE5". "I$(CHOICE,0)(9);HbBOXIT,3 b,X(5),Y(17)::"Press RETURN to take this lesson":"or press the SPACE bar to choose":"another.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$" "RESPNSE$M$25120l:16302,0:LMARGIN,0:WRITE:((#7-#EW(SWD%)2#SWD%,8:UNHOOK:::32,5:33,30:5:1:" YOU ENDED THE LESSON IN THE":"MIDDLE."::" DO YOU WANT TO:"::5)"1. GO BACK TO WHERE":9)"YOU LEFT OFF?"J#:5)"2. START THIS LESSON":9)"FROMTWRITE:$QUQIĮ:QI0QIQI1:L1QIQU:FD(0,0),FD(0,2):L21FD(0,0):FD(L2,0),FD(L2,1),FD(L2,2):::QIQU:pz3(UL0):UX,UY1UX(UL)((775)(804))1,UY1:3:XbHP%,32:SWD%,72:32,0:33,40:34,0:35,24:CLR%":OC$"*"FEFE1:4020!OC$;X1%(777)(778)2563:Y1%(779)Y(1)3:X2%(780)(781)256X(2)3:Y2%(782)(776)3:D1%1:S1%1:H1%(JUCR)41:2000J(LE)JUCRİ1000:X1%X1%1:X2%X2%2:Y1%Y1%1:Y2%Y2%1:CLRWIND,X1%,Y1%,X2%,Y2% R1JUIGJUG0)RIRIJU:WRWRJU@ STP(JUIGJUIN)3030[ ,AX,AY:" ":WRITE:amFE0ıRESET:,XP,YPOU$FD$(FE):LO(OU$)1:OU$""JUG0:L11LO:OC$(OU$,L1,1):OC$"/"ĺOC$;:L1LOĺM$;:OC$(OU$,1)1FD(0,0):RE$AN$(L1)ĂT (L1FD(0,0))ALTāL11FD(0,0):(RE$)(AN$(L1))Ă  L1FD(0,0)JUFD(L1,1):FOYE:FEFD(L1,2(FD(0,2)TR)):QTLSFD(L1,0)DN:FD(L1,2)DN:FD(L1,1)IG b FOFENM(LN0):JUFD(J1,1) l 4000:JUIGTRTR1# (T1%:X1%X1%S1%:Y1%Y1%S1%:X2%X2%S1%:Y2%Y2%S1%::< ^ REWRITE:TRTRST:QU05000 Z(0):FONO:,AX,AY:"1?0";:SWD%,684SH:ILLN:IXAXX(3ZX%):IYAY:UXIX:UYIY:ULLN:6000 ALT110,14000:,IX,IY:RE$(IL(RE$))(IL0));:L1 @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @  !!!!!!!"""""""#######$$$$$$$%%%%%%%&&&&&&&''''''' @ @ @PPPPPPP                         @ @ @ @ @ @ @ @ @ @ @ ((((((((((((((((((((((((((((((((PPPPPPPPPPPPPPPPPPPPPPPPP @ @ @ @ @ @ @ @  !!!""""###$$$$%%%&&&&'''@ @ @ @ @ @ @ @ @`Q`ZV21F{   !!!!"""####$$$%%%%&&&'''' @ @ @ @ @ @ @ @ @ @ @ @08F8`LoHJJJ` J J JJ4JJJ H J J H JJ`N Jn JNJnJJJ I J ILpILKL M J9 JJ3KKJ LI1 I1`HLOH;KL M J$NO MN I1``Q` H`I88 Iei -Ie I8 -Iei8 I8 -Ie Iei -I 8e     of the voltages in any":" one current path equals the":" applied voltage.""i:"C) The sum of the voltages of all":" of the current paths equals the":" applied voltage.""iQUESTIN5:LNGTH1:STPNO:LEAVEITYES,#iFDBCK$(1)"Sorry. V is ade of a series-":,8,19:"parallel circuit? Type its letter and";:,8,27:"press RETURN."!iX1%3:Y1%0:X2%277:Y2%30:H1%3:S1%1:D1%1:2000!i,X(2),Y(6):"A) Applied voltage equals the sum of":" the individual voltages."P"i:"B) The sum is would result in a sum/that was more than the total/current. Try again." eFDBCK$(3)"Sorry. Current is constant/in a seris circuit only./Try again." eAXPSX(2):AYPSY(18) f3000:1000: xi*PAGE20[!i7000:,8,11:"Which statement is tru the combined":" current of the parallel branches."e:"C) Total current in a series-parallel":" circuit equals the current at any":" point in the circuit."eQUESTIN4:LNGTH1:STPNO:LEAVEITYESeFDBCK$(1)"Right."K eFDBCK$(2)"No. Th3:S1%1:D1%1:2000e,X(2),Y(5):"A) Total current in a series-parallel":" circuit equals the sum of the":" parallel branch currents."6e:"B) Total current in a series-parallel":" circuit equals the sum of the":" series currents pluso R4^."-aFDBCK$(NMTCH)"Type A, B, or C."HbAXPSX(2):AYPSY(18)_bXPSX(7):YPSAYPSq b3000:1000:~e*PAGE19e7000:,11,10:"Which statement is true? Type its":,11,18:"letter and press RETURN."eX1%0:Y1%0:X2%266:Y2%22:H1%er. Try again."aFDBCK$(2)"Sorry. Current flowing out of a/resistor in a series-parallel/circuit equals the current/flowing into it. Try again."aFDBCK$(3)"Right. The ammeter only measures/the amount of current that has/rejoined before flowing int):"R3^"a,119,90:"R4^"HaVSPACE,5:,X(4),Y(13):"A) IT^"ea"B) I2^ + I3^ + I4^"a"C) I2^ + I3^":VSPACE,0aQUESTIN3:LNGTH1:STPNO:LEAVEITYESaFDBCK$(1)"Sorry. The currents don't/completely rejoin until after/the ammeta"3";:7:1:0:4102,72a222,40:1118,73:16:197,38:1167,38:1237,38:7:0:691,32:691,78:6161,32:6161,78:"0"a,21,74:"+":,21,40:"-":,101,81:"A"a,X(11),Y(7):"R1^"a,X(21),Y(7):"R2^" a,X(31),Y(71,63231,78142,78:123,78111,78:97,7828,7828,55:91,3291,45:91,6391,78:161,32161,45:161,63161,78a7:29,4729,32232,32232,45:232,63232,78143,78:124,78112,78:98,7829,7829,55:92,3292,45:92,6392,78:162,32162,45:162,63162,78 circuit,"::"type R."&T,X(6),Y(13):"Press RETURN to continue.";:FROMOTHERYES:1000:RESPNSE$"R"RESPNSE$M$40020&^0((((((((PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP                     $%%%&&&&'''@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ ((((((((((((((((((((((((@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @  !!!""""###$$$LCLLLLLLLXLLLLLLLLLLLL,W,P`,Q`,S`,R` ,`@,`,T`,U`L  !!!!"""####$$$%%%%&&&'''' @       (Hq*PAGE.22L(Rq7000:,X(10),Y(4):CHARMODE,3:"FANTASTIC!":CHARMODE,0(\q,35,79:"Your score was ";:RIGHT" correct"::"out of 6."::"You have completed this lesson"::"successfully."#)fq,X(6),Y(22):"Press ESC to leave.";:FROMOTHERYES:NPNO:LEAVEITYESJ'mFDBCK$(1)"Sorry. This statement is true./Try again."'mFDBCK$(2)"Right. The statement is false/because current flowing through/R3^ must also flow through R4^."'mAXPSX(2):AYPSY(19)'mXPSX(7):YPSAYPS'm3000:1000: Y(7):"R1^"(&m,X(21),Y(7):"R2^"D&m,X(31),Y(7):"R3^"Z&m,119,90:"R4^"z&m,21,74:"+":,21,40:"-"&mVSPACE,5:,X(4),Y(13):"A) VA^ = V1^"&m"B) VA^ = V2^ + V4^"&m"C) VA^ = V3^":VSPACE,0'mQUESTIN6:LNGTH1:ST29,32232,32232,45:232,63232,78143,78:124,7829,7829,55:92,3292,45:92,6392,78:162,32162,45:162,63162,78%m"3";:7:1:0:222,40:1118,73:16:197,38:1167,38:1237,38:7:0:691,32:691,78:6161,32:6161,78:"0" &m,X(11),¯,14,19:"letter and press RETURN."\$tmX1%11:Y1%0:X2%269:Y2%22:H1%3:S1%1:D1%1:2000n$~m*SCHEMATIC21$m3:28,4728,32231,32231,45:231,63231,78142,78:123,7828,7828,55:91,3291,45:91,6391,78:161,32161,45:161,63161,78v%m7:29,47hed the end of"::"this lesson.":::"To review the lesson, type R."3<,X(6),Y(13):"Press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$"R"RESPNSE$EXIT$410203FH|>p ~>@ `0|>1 $ $@ |>p8?8|> y` `>1|<|vۮLeq1 $ $@ >@ #q0@@ ` 0D( ʦ|>``8|>s8> %,3:AHOV]dkry  P>@@@Tq ‡@@  0@ `0_ ")07>ELSZahov}H$ "H"A"@ >A>`0> ē@c2iO  %GA G$:@c@pPDaPH @pERG$G$qdG$N$Oy‡@ H$H$ HRQH$< @pC>q E@>y8#q>A #q8@p0 qDD$$J'H#y@ qH$8>#>#@q"'@p80" @ "J%"I%H$q#Hȣ<y>@ "H$q":AHOV]dkry    @@@AQ!‡@@  "#Leq_ ")07>ELSZahov} %,3     s.":RXPS13:RYPS16:15000:,X(1),Y(15):"Whenever you have to take measurements,"::"using your troubleshooting skills will":2|"help you figure out which values to"::"calculate."21000:2(*PAGE21F327000:,X(6),Y(5):"You have reac:S1%1:D1%1:2000D1^,X(15),Y(3):"SUMMARY":2000:Y:X:WRITE1h,X(1),Y(7):" By using your knowledge of series-"::"parallel circuits, along with the"::"information on the schematic, you were"2r:"able to find all the missing value"3. You redrew the circuit into a":" simplified form."%RXPS14:RYPS19:15000:,X(3),Y(19):"4. You added RV^ to the series":" resistance."%1000:%@*PAGE20&J7000:,X(6),Y(5):"To review resistance in a"::"series-parallel"1. You sectioned the circuit,":" starting with the branch":" farthest from the voltage":" source.":RXPS14:RYPS13:15000;%,X(3),Y(13):"2. You computed RV^ for the parallel":" branches.":RXPS14:RYPS16:15000:,X(3),Y(16):4:38110#蔱#X*PAGE19%#b7000]#lX1%94:Y1%4:X2%150:Y2%20:H1%5:S1%1:D1%3:2000#vREWRITE:X16:,X(15),Y(2):" ":Y180:Y:,X(15),Y(2):"SUMMARY":X:WRITE#,X(6),Y(5):"To find total resistance,"$,X(3),Y(8):then add this/combined value to the series/values. Try again."h"ʔFDBCK$(4)"Sorry. Try 43.31}{0""ԔAXPSX(1):AYPSY(17):XPSX(11):YPSY(17):TRIES0:STPYES:NMTCH3:J1NMTCHINCRRECT"ٔ,X(8),Y(17):"1}{0"#ޔ3000:JUDGECRRECTNMTCHNT,A$4000":D$"BLOAD CIRCLE.OBJ"5>NFILE$LS$:13500A" N*CONTROL*CIRCUITRY.1.MRj*ND$"BLOAD ALL-BINARY":D$"BLOAD ALTS.FONT,A$4000":D$"BLOAD CIRCLE.OBJ">NFILE$LS$:13500:3):D$M$(4):EX$(27)dKCLR%809:SWD%803:HP%812,LLS$"INDEX.CIRCUITRY.2" *ND$"BLOAD ALL-BINARY":D$"BLOAD ALTS.FOive 1 and make sure"::"that the drive door is"::"closed.":NXNO:1000:13500\612000r6103,1:104,72:1x8JVJZ9815:YE1:NO0:BOYE:A$"":A1$A2$:G$(7):M$(13):D$M$(4):EX$(27)dKCLR%809:SWD%803:HP%812,LLS$"INDEX.CIRCUITRY.24103,80:104,95(4D$"RUN "FI$",D1"4412000q47000:,63,40:"Please put the diskette"::"marked - "5:(9)24)" ":" BASIC ELECTRONICS ":24)" ":" FUNDAMENTALS OF ":" DC CIRCUITRY "525)(9)PH5:"in dr):,X(6),Y(16):" Press CTRL-RESET to start over.":16384,0H2T2UNHOOK216301,0:32,0:33,40::23:2:"** PREPARING LESSON--PLEASE WAIT. **";2REHOOK:,0,8:44135504D$"BLOAD ID.CIRCUITRY.1,D1"4D$"MAXFILES1"16384,0.%.(222)255Č64166I.32,0:33,40:34,0:35,24:CLR%.,35,39:"ERROR TYPE = ";(222):"LINE NO. = ";(218)(219)256:,X(6),Y(10)B/(9)31)(0):" Please report this to your ":" instructor. ":31)(900:FI$LS$:13500##A$"3"11000.#115004*+7000:,X(10),Y(9):"Going to the menu."::"Please wait one moment." +FI$"INDEX.CIRCUITRY.2":13500,*BYE NOW,7000:,X(9),Y(10):"BYE NOW --"::" come back soon!":16368,0: THE BEGINNING?"::5)"3. GO TO THE MENU?"::5)"4. STOP THIS LESSON?"j#:" TYPE 1, 2, 3, OR 4."#20:23:A$:A$"1"A$"4"9130#16300,0:16297,0:16302,0:16304,0:SWD%,EW:REHOOK:32,0:33,40:34,0:35,24:A$"1"ı#A$"2"İ130ed the end of"::"this lesson.":::"To review the lesson, type R."2<,X(6),Y(13):"Press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$"R"RESPNSE$EXIT$410202F"g values. At";::"times you may have to take measurements,";:1|"but if you use the method we just"::"studied, you should be able to tell"::"which values to measure or calculate."11000:1(*PAGE21E227000:,X(6),Y(5):"You have reachpractice set, type R."H+,X(4),Y(13):"To practice, press RETURN.""Press ESC to leave.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"30040:;:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"R"30040:REXIT$RESPNSE$"R"30040:E$"R"30040:: lesson before doing"::"the XNO:1000:RESPNSE$EXIT$29030:0)0u*PAGE23m):u7000:,X(7),Y(6):CHARMODE,3:"SORRY...":CHARMODE,0)Du,X(7),Y(11):"Your score was "RIGHT" correct"::"out of 6.")Nu,X(7),Y(16):"To review the lesson now, type R."X*Xu,X(7),Y(19):H|>p ~>@ `0|>1 $ $@ |>p8?8|> y` `>1|<|vۮLeq1 $ $@ >@ #q0@@ ` 0D( ʦ|>``8|>s8> %,3:AHOV]dkry  P>@@@Tq ‡@@  0@ `0_ ")07>ELSZahov}H$ "H"A"@ >A>`0> ē@c2iO  %GA G$:@c@pPDaPH @pERG$G$qdG$N$Oy‡@ H$H$ HRQH$< @pC>q E@>y8#q>A #q8@p0 qDD$$J'H#y@ qH$8>#>#@q"'@p80" @ "J%"I%H$q#Hȣ<y>@ "H$q"0:RESPNSE$"R"RESPNSE$M$33020)4=<103,1:104,80:80256,0::(4)"RUN CIRCUITRY.1.MR":,`x|~~:~|xp`@cq89;;q`8?8@```@` ` `` ` `@@@2`@@ @` ` `Aaq9aAAa}9q`@01100100c `c?p`p?A@Ap ` p| p| wGGG||| 8~;8xxx8;~~~xxx8D?9t  t ?\bBBBcAAAc>pppp $aqcbB`CC||| t0H>`8DD8! p p  @ KREWRITExA1$"":A2$"":,IX,IY:IL1);:,IX,IY#16368,0(A$:50:402TY(Z9):ILĭNXTY5RE$A$:130<TY120,140,150,170,200F(A1$)IL190. PA1$A1$A$:C9      "branch farthest from the voltage source."3:35,7935,5670,56:89,56245,56245,77:245,95245,120203,120:184,12035,12035,87ꈓ133,56133,72:105,77105,72161,72161,77:105,95105,104161,104161,95:133,104133,120D7:36,7936,5671,5X(6),Y(20):"3. Redraw the circuit.":RXPS14:RYPS22:15000:,X(6),Y(22):"4. Add series and RV."t1000:*PAGE15ˆ7000:,X(1),Y(1)*̈"Let's find RT^ for this circuit. Section";::"or divide the circuit, starting with the";::,X(6),Y(13):"1. Section the circuit, starting":" with the branch farthest from":" the voltage source.":RXPS14:RYPS17:15000:,X(6),Y(17)h"2. Compute equivalent resistance":" of the parallel branches.":RXPS14:RYPS20:15000:,PAGE14ڄ7000:,X(1),Y(3)䄺" Total resistance in series-parallel"::"circuits equals the series resistance"::"plus the equivalent resistance of the"::"parallel branches. Follow these steps":"to find RT^:":RXPS14:RYPS13:15000:T1$:PR$".":CM$",":SP$" ":NG$"-"HNLS$"WELCOME.SERIES-PARALLEL.2"j N*CONTROL*SERIES-PARALLEL.2.2u*N340004N35000>N36000HN37000RN38000\N39000fN40000:RESPNSE$"R"20010pN13000:FILE$"SERIES-PARALLEL.2.3":13500Є*(27)A LJJU0:NR1:LS2:QTNR:LENO:CR1:IN0:IG3:G04:RI0:WR0 VJMA3:MF4:AN$(MA):FD$(MF2):FD(MA2,2):NMMF1:DNMF2:J1MA1:FD(J1,1)IG tJMOD(A)(A2)A2 JCLR%809:SWD%803:HP%812 JI$(9):QU$(34)$JB1$"0":T1$"9":B2$B1$:T2$#-2(5) F2, F1,1,,2,0,1 8JINITIALIZATION :JAD(115)((116)4)256::(4)"BLOAD SCHEMATIC.SYMBOLS.1,A"AD",D1":ADDR,3,(115)((116)4)256 N25000HN26000RN27000\N28000fN29000pN30000zN31000N40000N41000 NRE$CR1:IN0:IG3:GO4:RI0:WR0oVJMA3:MF2:AN$(MA):FD$(MF2):FD(MA2,2):NMMF1:DNMF2:J1MA1:FD(J1,1)IG`JRADIUS27:MODE28:C031:XLOW249:XHIGH250:YLOW251tJMOD(A)(A2)A2JCLR%809:SWD%803:HP%812JI$(9):QU$(34)8JB1$"0"NITIALIZATIONt:JAD(115)((116)4)256::(4)"BLOAD SCHEMATIC.SYMBOLS.1,A"AD",D1":ADDR,3,(115)((116)4)256-CIRCLE.DRAW >RADIUS,RD%:MODE,0:C0,H1%:XHIGH,(X1%256):XLOW,X1%((X1%256)256):YLOW,Y1%:18432 > hB-FLASH.STRING rBREWRITE:X112:,X1%,Y1%:" "Z7$;:Y150:Y:X:WRITE: PF*QUESTION-DATA (8); F72 P7A1$""A2$""A$(A2$,1):14070l Z7(A2$)(A1$)A$(A2$,(A1$)1,1):A1$A1$A$:A$;:x d7BEEP: n7NX9000: :*ADD.ON.PRESS.RETURN :,X(RXPS),Y(RYPS):"Press RETURN.";:FROMOTHERYES:1000:RE$M$15010:REWRITE:,X((A1$)) 7C9A2$A1$$ 7A$;:g 7RE$A1$:" ":L1(RE$)11:(RE$,1)" "RE$(RE$,1,L11): 7(RE$,1,1)" "RE$(RE$,2):14110 (7RE$""RE(RE$):RL(RE$):NXYES::WRITE: 27BEEP:BEEP::14010 <7A1$""A1$(A1$,1,(A1$)1): 6(A1$)IL14180m 6A$"H"SL%IL:SX%IX:SY%IY:24000:17000:15000:6000::ILSL%:IXSX%:IYSY%:14010 6C1(B1$A$)(A$T1$):C2(B2$A$)(A$T2$):C3(A$PR$)(A$NG$) 6(C1C2C3)ı 6A1$A1$A$:C9(A2$)(A1$):C9A2$A1$(A2$,(A2$)+ 612000-6103,1:104,80:16302,0:1K6*ALTERNATE INPUT ROUTINE6REWRITE:,IX,IY:IL1)"";:A1$"":A2$"":JD$"":,IX,IY616368,06A$:14040:140306TY(Z9):ILĭNXTY5RE$A$:141206TY14100,14130,14140,14160,14190               you first add":"the two series resistors in the outer":"branch and then compute the equivalent":"resistance of the parallel branches."Ҍ"Using the reciprocal method, what is RE^?":VSPACE,0܌QUESTIN1:LNGTH5:LEAVITNO:TRIES0:ALTYES:STPNO53,40:34,17:35,24:CLR%632,0:33,40:34,0:35,24Ì,0,8:"3";:0:1:0:1179,115:"0":3:180,120207,120:REWRITE:,189,112:" ":,220,88:"8":WRITE:VSPACE,1Ȍ,0,8:" Next, compute RE^ for the parallel":"section. In this case, onsists of two series":"resistors that are in parallel with two":"other parallel branches.",X(6),Y(24):"Press RETURN for the next step.";:FROMOTHERYES:1000:RESPNSE$M$35240*PAGE1632,0:33,40:34,0:35,5:CLR%32,0:3":,77,68:"21}{0"h"3";:7:1:0:229,72:165,51:1179,115:16:1111,70:1167,70:1251,700:6133,56:6133,120:"0"],X(1),Y(18):"This circuit has two sections. One is":"made up of the single series resistor.":"The other c246,95246,120204,120:185,12036,12036,87134,56134,72:106,77106,72162,72162,77:106,95106,104162,104162,95:134,104134,120,21,80:"-":,21,96:"+":,80,88:"41}{0":,136,88:"21}{0":,220,88:"51}{0":,189,112:"31}{0REWRITE:,X(5),Y(18):"Press ESC to stop, or H for":"help with special keys.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"H"(RESPNSE$"6"RESPNSE$"8")25070aRESPNSE$EXIT$ıbRESPNSE$"H"ı; bCHOICE(RESPNSE$)5:,X(5),Y(7Ccuits, Part 2":I$(2,1)"WELCOME.SERIES-PARALLEL.2"aI$(3,0)"Series-Parallel Circuits, Part 3":I$(3,1)"WELCOME.SERIES-PARALLEL.3"a,35,40:"Press the number of the lesson":"you want to study:"aX13:,X(5),Y(7X2):X5". "I$(X,0):ag the":9)"X key to erase the answer":9)"that you typed in.":1000:Xa*CHOICEPAGEa7000:CHARMODE,3:,115,18:"MENU":CHARMODE,0aI$(1,0)"Series-Parallel Circuits, Part 1":I$(1,1)"WELCOME.SERIES-PARALLEL.1"2aI$(2,0)"Series-Parallel Cir)"to the next display."::" 1<-0 Press this key to go back":9)"over a letter that you":9)"typed by mistake."G]:" ESC If you want to stop at":9)"any time, press this key."::" CTRL-X Hold down the key marked":9)"CTRL while pressin.";:FROMOTHERYES:1000:RESPNSE$" "RESPNSE$M$23020? YM ]*KEYHELP ]7000:,X(4),Y(2):"To help you practice, you will be":"able to use the following keys on":"the computer's 1keyboard0:"x]::" RETURN Press this key to go on":9poration, Chicago, ILL."$ hV1000:2 Y*ASKHELP Y7000:,35,40:"Some special keys will help"::"you to go through this lesson."::"If you want to see which they"::"are, press the SPACE bar now."9 Y,X(6),Y(12)::"To continue, press RETURNr other"6 ,V"electronic devices nor copied, recast,"b 6V"transformed, adapted nor utilized in" @V"any information or retrieval system" JV"in whole or in part without the written" TV"permission of Encyclopaedia Britannica" ^V"Educational Cor R*TITLE-PAGE-PAUSED lR16368,0:X1500:X1(16384)128:X1ĂT R16368,0:g U*WARNING PAGE UBONO:7000:BOYES:32,0:33,40 V,X(1),Y(7):"WARNING:" V:"ALL RIGHTS RESERVED. This work may not" "V"be transmitted by television oX.CIRCUITRY.2 *N(6909)85(6910)170(6911)85İ21000:5120:6909,85:6910,170:6911,85:ADDR,1,64256:ADDR,2,17441:16302,0:22000:23000:RESPNSE$" "24000 4N25000:RESPNSE$EXIT$:11500 HNRESPNSE$"H"İ24000:20020 \N13000:13500 612000-6103,1:104,80:16302,0:1B8J*INITIALIZATIONVJZ9815:YE1:NO0:BOYE:A$"":A1$A2$:G$(7):M$(13):D$M$(4):EX$(27)JMOD(A)(A2)A2:I$(3,1)dKCLR%809:SWD%803:HP%812,LLS$"INDEX.CIRCUITRY.2" N*CONTROL*INDE     2260,100:260,118260,128218,128:188,128183,128:164,12857,12857,88a155,56155,62:225,56225,62:225,92225,100:155,92155,100:155,118155,128:225,118225,128*a,119,52:"IT^= ? ":,144,76:"I2^= 2A":,214,76:"I3^= 2A":,24259,62:259,92259,100:259,118259,128217,128:187,128182,128:163,12856,12856,88a154,56154,62:224,56224,62:224,92224,100:154,92154,100:154,118154,128:224,118224,128Ia7:57,8057,5678,56:97,56113,56:143,56260,56260,62:260,9nt equals the sum of the":"currents in parallel branches. What is";:"the total current for this circuit?":"Type your answer and press RETURN."aX1%0:Y1%0:X2%279:Y2%36:H1%2:S1%1:D1%1:2000Wa3:56,8056,5677,56:96,56112,56:142,56259,56al resistance equals the series":" resistance plus the equivalent":" resistance of the parallel":" branches.":RXPS14:RYPS20:15000],X(1),Y(21):"Let's start by applying the first rule.":1000:a*PAGE5a7000:,3,10:"Total currehe sum of the":,X(5),Y(7):"currents in the parallel branches.":RXPS14:RYPS9:15000],X(2),Y(10):"2. Applied voltage equals the sum of":" the voltages in any separate":" current path.":RXPS14:RYPS14:15000],X(2),Y(15):"3. Tot,X(1),Y(14):" Let's review these quickly before"::"going on."SZ1000:_]*PAGE4]7000:,X(4),Y(2):"RULES OF SERIES-PARALLEL CIRCUITS":X1%19:Y1%4:X2%254:Y2%19:H1%5:S1%1:D1%1:2000Y],X(2),Y(6):"1. Total current equals tFILE$"SERIES-PARALLEL.2.2":13500.Y*PAGE3GY7000:,X(1),Y(3)Y" In order to find values for"::"current, voltage, and resistance in a"::"series-parallel circuit, you need to"::"remember the rules of this type of"::"circuit."GY$" ":NG$"-"1NLS$"WELCOME.SERIES-PARALLEL.2"S N*CONTROL*SERIES-PARALLEL.2.1^*N23000i4N24000t>N25000HN26000RN27000\N28000:RESPNSE$"R"20030fN29000pN30000zN31000N32000N33000:RESPNSE$"R"20070"N13000::AN$(MA):FD$(MF2):FD(MA2,2):NMMF1:DNMF2:J1MA1:FD(J1,1)IG|`JRADIUS27:MODE28:CO31:XLOW249:XHIGH250:YLOW251tJMOD(A)(A2)A2JCLR%809:SWD%803:HP%812JI$(9):QU$(34) JB1$"0":T1$"9":B2$B1$:T2$T1$:PR$".":CM$",":SP:(4)"BLOAD SCHEMATIC.SYMBOLS.1,A"AD",D1":ADDR,3,(115)((116)4)256f E PF*QUESTION-DATAO ZFQ#-1W dF2,f nF1,1,,2,0,p xFQ#-2x F1, F1,1, FQ#-3 F2, F1,1,,2,0, FQ#-4 F4, F1,1,,2,0,,3,0,,4,0, 8JINITIALIZATIONI :JAD(115)((116)4)256::A1$A1$A$:A$;: d7BEEP:- n7NX9000:8 :*P.R. :,X(RX),Y(RY):"Press RETURN.";:FROMOTHERYES:1000:RESPNSE$M$15010:,X(RX),Y(RY):REWRITE:" ":WRITE: >-DRAW.CIRCLE+ >RADIUS,RD%:MODE,0:CO,H1%:XHIGH,(X1%256):RE$,1,L11):5 7(RE$,1,1)" "RE$(RE$,2):14110h (7RE$""RE(RE$):RL(RE$):NXYES::WRITE: 27BEEP:BEEP::14010 <7A1$""A1$(A1$,1,(A1$)1):(8); F7 P7A1$""A2$""A$(A2$,1):14070 Z7(A2$)(A1$)A$(A2$,(A1$)1,1) 6(A1$)IL14180Z 6C1(B1$A$)(A$T1$):C2(B2$A$)(A$T2$):C3(A$PR$)(A$NG$)m 6(C1C2C3)ı 6A1$A1$A$:C9(A2$)(A1$):C9A2$A1$(A2$,(A2$)(A1$)) 7C9A2$A1$ 7A$;: 7RE$A1$:" ":L1(RE$)11:(RE$,1)" "RE$(-, 612000-6103,1:104,80:16302,0:1K6*ALTERNATE INPUT ROUTINE6REWRITE:,IX,IY:IL1)"";:A1$"":A2$"":JD$"":,IX,IY616368,06A$:14040:140306TY(Z9):ILĭNXTY5RE$A$:141206TY14100,14130,14140,14160,14190                fҗ L L L$  5F67`N^89`HH`(wn,3L ©éĭ@JLLE C^[lO,LȐ ,Pɗ*ɘɍL=Ʌ-ɖ``````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````Ӡˠ̠ŠԠé̠΍$9ɝ ,L `<>=?<>=? , Hȱ8h  ȩ$ȱH  h i֩H MMLI L          T$RESPNSE$" "RESPNSE$M$24140j^RESPNSE$" "į,X(5),Y(7CHOICE2):REWRITE:RESET:CHOICE". "I$(CHOICE,0);:BOXIT,0:,X(5),Y(18):99)" ":24100t^WRITE:FILE$I$(CHOICE,1):#E,1):A1):_B^CHOICE(RESPNSE$):,X(5),Y(7CHOICE2):REWRITE:RESET:(9)CHOICE". "I$(CHOICE,0)(9);lG^BOXIT,3#L^,X(5),Y(17)::"Press RETURN to take this lesson":"or press the SPACE bar to choose":"another.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXI,X(5),Y(7X2):X". "I$(X,0):$^REWRITE:,X(5),Y(18):"Press ESC to stop, or H for":"help with special keys.";:FROMOTHERYES:NXNO:1000:RESPNSE$EXIT$RESPNSE$"H"(RESPNSE$"1"RESPNSE$"3")241008^RESPNSE$EXIT$ı=^RESPNSE$"H"ıRALLEL.1"\]I$(2,0)"Series-Parallel Circuits, Part 2":I$(2,1)"WELCOME.SERIES-PARALLEL.2"]I$(3,0)"Series Parallel Circuits, Part 3":I$(3,1)"WELCOME.SERIES-PARALLEL.3"^,35,40:"Press the number of the lesson":"you want to study:""^X13:omplete, so let's get"::"started."} V,X(8),Y(21):"Press RETURN to begin.";:FROMOTHERYES:1000:RESPNSE$M$22040:U"::"parallel circuits, you will learn to"::"compute values for current, voltage, and";::"resistance by applying the rules of this";::"type of circuit.$ VRXPS14:RYPS14:15000:,X(1),Y(14):" The lesson will take about 45"::"minutes to c2%78:H1%2:S1%2:D1%3:2000G 0R,57,106:"CONVERGENT SYSTEMS, INC." :R,106,128:"2 ABCDEF ":" HIJKLM ":"OPQRSTUV":"WXYZabcd":" efghij ":" lmnopq 0" NR1000: U*PAGE2 U7000:,X(1),Y(2) V" Hello! In this lesson on series- RTITLEPAGE R7000:,X(7),Y(3):" BASIC ELECTRONICS"::"FUNDAMENTALS OF DC CIRCUITRY":" DISK #3":,84,62:"Series-Parallel":,84,71:"Circuits, Part 2" !RX1%28:Y1%7:X2%254:Y2%77:H1%1:S1%2:D1%3:2000:X1%29:Y1%8:X2%254:Y):M$(13):D$M$(4):EX$(27)8 VJMOD(A)(A2)A2V tJCLR%809:SWD%803:HP%812z NLS$"WELCOME.SERIES-PARALLEL.2" N*CONTROL*WELCOME.SERIES-PARALLEL.2 %NWRITE *N21000 4N22000 9NREWRITE >N13000:FILE$"SERIES-PARALLEL.2.1":13500 ~ 612000-6103,1:104,80:16302,0:18:*P.R.:,X(RX),Y(RY):"Press RETURN.";:FROMOTHERYES:1000:RESPNSE$M$15010:,X(RX),Y(RY):REWRITE:" ":WRITE:8JINITIALIZATION BJZ9815:YE1:NO0:BOYE:A$"":A1$A2$:G$(7  uit? Type your answer and";:"press RETURN."43:21,7221,4063,40:82,40108,40:127,40168,40:187,40245,40245,48:245,66245,88:245,104245,120201,120:174,120173,120:154,12021,12021,80,6147,40147,48:147,66147,88:147,104147,120:2lel":" branches."::"3. You redrew the circuit into a":" simplified form.":"4. You added RE^ to the series":" resistance."1000:(*PAGE21.27000:,X(2),Y(1):"What is the value of IT^ in this series":"parallel circ(15),Y(2):"SUMMARY":X:WRITEO,X(6),Y(5):"To find total resistance,",X(3),Y(8):"1. You sectioned the circuit,":" starting with the branch":" farthest from the voltage":" source."T:"2. You computed RE^ for the paraltages in any":RESET:" one ";:BOXIT,3:" loop, and the voltage of each"::"loop is equal to VA^."q<}1000:~X*PAGE19b7000lX1%94:Y1%4:X2%150:Y2%20:H1%5:S1%1:D1%3:2000vREWRITE:X16:,X(15),Y(2):" ":Y180:Y:,XY(2):"SUMMARY":X:WRITE(},X(5),Y(5):"To find applied voltage, you"::"divided the circuit into"::"closed, separate loops and then"::"added the voltage across each"-}:"resistor in any one of the loops."e2}:"VA^ equals the sum of volr any of":" the resistors, you added the":" branch currents flowing into it.":VSPACE,0ki1000:x}*PAGE12 }7000}X1%96:Y1%3:X2%152:Y2%21:H1%5:S1%1:D1%2:2000}REWRITE:X16:,X(15),Y(2):" ":Y180:Y:,X(15),190:Y:,105,17:" ":X:,105,17:"SUMMARY":WRITEiVSPACE,5:,X(3),Y(6):"1. To find IT^, you added the branch":" currents because current in":" parallel branches is additive."_i,X(3),Y(13):"2. 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